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  • 2 answers

Gaurav Rana 5 years, 7 months ago

A circle is the locus of points which is equidistance from the centre in a plane

Tulika Kashyap 5 years, 7 months ago

Perimeter-2×22/7×r Area - 22/7×r^2
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Girish Karhana 5 years, 7 months ago

In geometry, Heron's formula (sometimes called Hero's formula), named after Hero of Alexandria, gives the area of a triangle when the length of all three sides are known. Unlike other triangle area formulae, there is no need to calculate angles or other distances in the triangle first.
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Ash Ketchum 5 years, 7 months ago

You can leave the answer either in root or sometimes if i want to know complete exact answer then i need to solve root to 5-6 decimals by calculators..so it can vary....

Vashu Tyagi 5 years, 7 months ago

1.73
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  • 1 answers

Girish Karhana 5 years, 7 months ago

In geometry, a hectogon or hecatontagon or 100-gon is a hundred-sided polygon.
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  • 1 answers

Anurag Choudhary 5 years, 7 months ago

Three or more points which are in a line is called non collinear points
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Gaurav Rana 5 years, 7 months ago

Construction =draw pn perpendicular sr and qm perpendicular sr Proof =In triangle psn and triangle qmr PS =QR (given) Angle PNS =Angle QMR ( each 90°) PN= QM(perpendicular distance between two ll lines always equal) Triangle PSN =~(means congurent to) triangle QMR ( by RHS ) Angle SPN =Angle RQM(by CPCT) Adding 90° both sides Angle P= Angle Q Angle S +Angle P=180°( by co- interior) Angle S+Angle Q=180°( angle P = Angle Q) Angle R +Angle Q =180°(by co -interior ) Angle R+Angle P =180°(Angle P=Angle Q) Since sum of the opposite angle of the trapezium is 180° hence it is a cyclic trapezium

Gaurav Rana 5 years, 7 months ago

Given=PQRS is a trapezium in which PS =QR and PQ ||SR To prove = angle p+ angle R = 180°and angle S + angle Q=180°
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Girish Karhana 5 years, 7 months ago

Proof = ΔAPB and //gm ABCD are on same base AB and b/w same parllels AB and DC. So,area(ΔAPB)=1/2 area (//gm ABCD) -1 ΔBQC of //gm ABCD have same base BC and b/w same parllels BC and AD So,area(ΔBQC)=1/2 area (//gm ABCD) -2 From eq. 1 and 2 area(ΔAPB)=area(ΔBQC) Hence Proved
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Anurag Choudhary 5 years, 7 months ago

15:18:20
  • 1 answers

Girish Karhana 5 years, 7 months ago

632.48 Indian rupee 8 Euro
  • 1 answers

Gaurav Seth 5 years, 7 months ago

SinceΔEAD=ΔABC
(Corresponding angles),&AD=BC(sides of the rhombus)
By side angle side congrugency,the triangles
Therefore the corresponding parts of the triangle are also equal.
ΔCBF & ΔDAB
Since the sides 
BF=AB
∠CBF∠DAB(corresponding angles)
ΔCBF&ΔDAB are congrugent
ΔAOB
∠ABO+∠BAO+∠AOB=180°
∠ABO+∠BAO=90°
∠CFB+∠AED=90°
∠XFE+∠XEF=90°

Read more on Brainly.in - https://brainly.in/question/987606#readmore

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Shivam Raj 5 years, 7 months ago

√5x-4=2√5+6 √5x=2√5+6+4 √5x=2√5+10 x=2√5+10÷√5 x=2√5(1+√5)÷√5 x=2(1+√5) x=2+2√5

Daniya Khatoon 5 years, 7 months ago

Yeah Kaisa saval h
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Namrata Jindal 5 years, 7 months ago

Mean of 5 numbers? is 30. So sum of the numbers will be 5*30=150. If one number is excluded, Mean of 4 numbers was 28. So sum will be 4*28=112. Excluded number?=150-112=38.
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Vedika Šäbłè 5 years, 7 months ago

√2*√2 = 2

Yogita Ingle 5 years, 7 months ago

  √2(√2) = √4 = 2

  • 1 answers

Gaurav Seth 5 years, 7 months ago

SHORT FORMULA
NEW MEAN =MEAN - THE COMMON NUMBER DECREASED
=40-12
=30

Detailed solution :

Mean=sum of total observation /total number of observation
42=sum of total observation /10
420=sum of total observation
Now each member of the observation is decreased 12
=12*10=120
New sum of total observation =420-120
=300
New mean =300/10
=30

 

  • 1 answers

Shriya Samaga 5 years, 7 months ago

Volume of cone= 1/3×22/7×R²×H =1/3× 22/7×3.5×3.5×12=154cm²
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Hariom Dalal 5 years, 7 months ago

Almost full because in 10th everything is based on its base i.e 9th & if student is weak in studies than atleast 30% which includes common questions. Actually there is a choice now for weak students they can choose computer as optional & maths(basic) for proceedings.

Abhinav Prience 5 years, 7 months ago

At least 10 to 20 percent

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