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Ask QuestionPosted by Sarbeswar Pradhan 4 years, 10 months ago
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Posted by Sarbeswar Pradhan 4 years, 10 months ago
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Posted by Payal Gujrati 4 years, 10 months ago
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Diya Tomar 4 years, 10 months ago
Shubham Meena 4 years, 10 months ago
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Gautam Kumar 4 years, 10 months ago
Posted by Anil Kumar 4 years, 10 months ago
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Gaurav Seth 4 years, 10 months ago
(√3+√7)/(√3-√7) × (√3+√7)/(√3+√7)
(3+2√21+7) / 3-7 = ( 10+2√21) / -4
= -10/4-1/2(√21)
=-5/2- √21/2
= (-5-√21)/2 or
=( 5+√21)/(-2)
Posted by Aayush Tiwari 4 years, 10 months ago
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Posted by Ñoßi Ţä 4 years, 10 months ago
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Gaurav Seth 4 years, 10 months ago
Given a circle with centre O and chords AB = CD
Draw OP⊥ AB and OQ ⊥ CD
Hence AP = BP = (1/2)AB and CQ = QD = (1/2)CD
Also ∠OPA = 90° and ∠OQC = 90°
Since AB = CD
⇒ (1/2) AB = (1/2) CD
⇒ AP = CQ
In Δ’s OPA and OQC,
∠OPA = ∠OQC = 90°
AP = CQ (proved)
OA = OC (Radii)
∴ ΔOPA ≅ ΔOQC (By RHS congruence criterion)
Hence OP = OQ (CPCT)
Rohit Kumar 4 years, 10 months ago
Posted by Aditya Kumar 4 years, 10 months ago
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Posted by Prerna Sinha 4 years, 10 months ago
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Yogita Ingle 4 years, 10 months ago
a-b=7 ⇒a=7+b .....(i)
a²+b²=85 ....(ii)
Substitution of equation 1 to equation 2.
(7+b)²+b² =85
49+14b +b²+b² =85
2b²+14b-36 =0
b² +7b -18 =0
(b+9)(b-2) =0
b=-9 v b=2
Find value of a
a-b=7
⇒if b=-9
a-(-9)=7
a =7-9
=-2
⇒if b=2
a-2=7
a = 7+2
=9
So value of a³ - b³ there are 2 options
⇒if (a,b) = (-2,-9)
a³-b³ = -2³ - (-9)³
= -8 +729
= 721
⇒if (a,b) = (2,9)
a³-b³ = 2³ - 9³
= 8-729
= -721
Posted by Prerna Sinha 4 years, 10 months ago
- 1 answers
Yogita Ingle 4 years, 10 months ago
a-b=7 ⇒a=7+b .....(i)
a²+b²=85 ....(ii)
Substitution of equation 1 to equation 2.
(7+b)²+b² =85
49+14b +b²+b² =85
2b²+14b-36 =0
b² +7b -18 =0
(b+9)(b-2) =0
b=-9 v b=2
Find value of a
a-b=7
⇒if b=-9
a-(-9)=7
a =7-9
=-2
⇒if b=2
a-2=7
a = 7+2
=9
So value of a³ - b³ there are 2 options
⇒if (a,b) = (-2,-9)
a³-b³ = -2³ - (-9)³
= -8 +729
= 721
⇒if (a,b) = (2,9)
a³-b³ = 2³ - 9³
= 8-729
= -721
Posted by Priya Jha 4 years, 10 months ago
- 0 answers
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Ashutosh Gupta 4 years, 10 months ago
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