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  • 0 answers
  • 0 answers
  • 1 answers

Anshika Mishra 5 years, 5 months ago

1.415,1.416.......
  • 0 answers
  • 0 answers
  • 2 answers

Vansh Kukreja 5 years, 5 months ago

16root3

Yash Sharma 5 years, 5 months ago

Yarr please koi to ans do
  • 5 answers

Vansh Kukreja 5 years, 5 months ago

a=5

Ashutosh Kumar Tiwari 5 years, 5 months ago

a=5

Ayush Nikumbh 5 years, 5 months ago

a=1×5=5

Shashank Sah 5 years, 5 months ago

A=5

Vaibhav Sharma 5 years, 5 months ago

a=5
  • 2 answers

Priyanka Iomror 5 years, 5 months ago

9602

Sandy K Kandari 5 years, 5 months ago

Hff
  • 1 answers

Yogita Ingle 5 years, 5 months ago

Let there is a right angle triangle ABC where

AB is the perpendicular, AC is hypotenuse and BC is the base of the triangle.

From Pythagoras Theorem, 

      hypotenuse2 = Perpendicular2 + base2

=> AC2 = BC2 + AB2

=> AC = √(BC2 + AB2 )

So hypotenuse is the longest side in a right angle triangle.

  • 1 answers

Ajab Murtaza 5 years, 5 months ago

Divide it
  • 2 answers

Ayush Nikumbh 5 years, 5 months ago

157

Yogendra Singh Jodha 5 years, 5 months ago

180-23=157
  • 3 answers

Ayush Nikumbh 5 years, 5 months ago

Speed=scaler,distance related Velocity=vector,displacement related

Mysterious Science World 5 years, 5 months ago

Speed = distance_time where as velocity=displacement/time

Chirag Sharma 5 years, 5 months ago

Speed is scaler while velocity is vector
  • 3 answers

Shreyansh Dwivedi 5 years, 5 months ago

Explain the answer plzz

Chirag Sharma 5 years, 5 months ago

27

Gh Mn 5 years, 5 months ago

27
  • 1 answers

..... Sharma 5 years, 5 months ago

I also need sample papers
  • 2 answers

Yogita Ingle 5 years, 5 months ago

  • b = base of the isosceles triangle
  • h = Height of the isosceles triangle
  • a = length of the two equal sides

Yogita Ingle 5 years, 5 months ago

<th colspan="2">Formulas to Find Area of Isosceles Triangle</th>
Using base and height A = ½ × b × h
Using all 3 sides A = ½[√(a2 − b2 ⁄4) × b]
Area formula for isosceles right triangle A = ½ × a2
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  • 1 answers

Nikhil B 5 years, 5 months ago

1/2×b×h
  • 2 answers

..... Sharma 5 years, 5 months ago

☺️☺️

Salamat Ansari 5 years, 5 months ago

Take a line segment, say, AB. Choose a point C on it. With center C, and radius BC, draw an arc. With center B and radius BC, cut the previous arc at say DD. (∠DCB=60∘∠DCB=60∘because we just made CD=BC=BD .) With center D, and radius BC draw an arc. With center B and radius BC, cut this arc at, say, EE. Then EC is the bisector of ∠BCD, and hence ∠BCE=30∘ .Then, ∠ACE=180∘−∠BCE=150∘. HOPE THIS HELPS YOU......✌✌
  • 1 answers

Salamat Ansari 5 years, 5 months ago

50/243

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