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Ask QuestionPosted by Simran Bajwa Bajwa 4 years, 8 months ago
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Himani Kashyap 4 years, 8 months ago
Himani Kashyap 4 years, 8 months ago
Bro . 4 years, 8 months ago
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Bro . 4 years, 8 months ago
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Himani Kashyap 4 years, 8 months ago
Posted by Nakshathra S 4 years, 8 months ago
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Yogita Ingle 4 years, 8 months ago
Let ABC is a right angled triangle.
i) Perimeter of ∆ABC = 24
=> x+y+10=24
=> x+y = 24-10
=> x+y = 14 ---(1)
ii) By Phythagorean theorem:
AC²= AB²+BC²
=> 10²= x² + y²
=> x²+y² = 100 ---(2)
iii) On Squaring equation (1), we get
=> (x+y)² = 14²
=> x²+y²+2xy = 196
=> 100+2xy = 196( From (2) ]
=> 2xy = 196-100
=> 2xy = 96
Divide both sides by 2 , we get
=> xy = 48 ---(3)
Now ,
{tex}Area \: of \: \triangle ABC = \frac{1}{2} \times AB \times BC\\=\frac{1}{2}\times xy\\=\frac{1}{2}\times 48{/tex}
/* From (3) \
{tex}= 24\: cm^{2}{/tex}
Therefore,
{tex}Area \: of \: the\:triangle =24\: cm^{2}{/tex}
Posted by Khushi Mittal 4 years, 8 months ago
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Aarti Anand 4 years, 8 months ago
Posted by Binoy Augustine 4 years, 8 months ago
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Posted by S Vinay Kumar 4 years, 8 months ago
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Yogita Ingle 4 years, 8 months ago
{tex}Let\: side\: of \: an : equilateral \: triangle = a \: cm{/tex}
{tex}Perimeter \: of \: the \: triangle\ (P) = 180\:cm \: (given){/tex}
{tex}\implies 3a = 180\:cm{/tex}
{tex}\implies a = \frac{180}{3}{/tex}
{tex}\implies a = 60\:cm{/tex}
{tex}Area\: of \: an\ \: equilateral \: triangle (A) =\frac{\sqrt{3}}{4}\times a^{2}{/tex}
{tex}=\frac{\sqrt{3}}{4}\times 60^{2}\\=\frac{\sqrt{3}}{4}\times 60\times 60\\=\frac{\sqrt{3}}{4}\times 60\times 15\\=900\sqrt{3} \:cm^{2}{/tex}
Therefore,
{tex}Area\: of \ \: equilateral \: triangle (A)\ =900\sqrt{3}\:cm^{2}{/tex}
Posted by Muskan Jha 4 years, 8 months ago
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Posted by S Vinay Kumar 4 years, 8 months ago
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Nakshathra S 4 years, 8 months ago
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Posted by Jitendra Sharma 4 years, 8 months ago
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Yogita Ingle 4 years, 8 months ago
Circumference of base of cylinder = 22 cm
Height of cylinder = 7 cm
So,
Circumference=2 πr = 22 Given
r= 22/2 π= 22(7)/2 (22) = 7/2 = 3.5
Radius of cylinder = 3.5 cm
∴ Curved surface area of cylinder = 2 π rh = 2× 22/7 × 3.5 × 7= 2 × 22/7 × 3.5 × 7 = 44 × 3.5 = 154 cm2
Posted by Jitendra Sharma 4 years, 8 months ago
- 2 answers
Yogita Ingle 4 years, 8 months ago
Circumference of base of cylinder = 22 cm
Height of cylinder = 7 cm
So,
Circumference=2 πr = 22 Given
r= 22/2 π= 22(7)/2 (22) = 7/2 = 3.5
Radius of cylinder = 3.5 cm
∴ Curved surface area of cylinder = 2 π rh = 2× 22/7 × 3.5 × 7= 2 × 22/7 × 3.5 × 7 = 44 × 3.5 = 154 cm2
Posted by Aryan Rana 4 years, 8 months ago
- 2 answers
Yogita Ingle 4 years, 8 months ago
If a straight line falling on two straight lines makes the interior angles on the same side of it taken together less than two right angles, then the two straight lines, if produced indefinitely, meet on that side on which the sum of angles is less than two right angles.
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Aarti Anand 4 years, 8 months ago
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Dj Jd 4 years, 8 months ago
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