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Ask QuestionPosted by Rabikant Behera 4 years, 8 months ago
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Posted by Anil Sharma 4 years, 8 months ago
- 1 answers
Adarsh Singh 4 years, 8 months ago
Posted by Anil Sharma 4 years, 8 months ago
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Yogita Ingle 4 years, 8 months ago
WE have,
∠B - ∠D = 60o (i)
Since, ABCD is a cyclic quadrilateral
Then,
∠B+ ∠D = 180o (ii)
Adding (i) and (ii), we get
∠B - ∠D + ∠B + ∠D = 60o + 180o
2 ∠B = 240o
∠B = 120o
Put value of ∠B in (ii), we get
120o + ∠D = 180o
∠D = 60o
Posted by Anil Sharma 4 years, 8 months ago
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Yogita Ingle 4 years, 8 months ago
Let O be the point of intersection of the diagonals BD and AC of rectangle ABCD.
Since, the diagonals of a rectangle are equal and bisect each other.
∴ OA = OB = OC = OD
Hence, O is the center of the circle through A, B, C, D.
Posted by Saurav Kumar 4 years, 8 months ago
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Posted by Vijay Gupta 4 years, 8 months ago
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Posted by Asha Sager 4 years, 8 months ago
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Posted by Paras Sharma 4 years, 8 months ago
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Posted by Nitish Bhardwaj 4 years, 8 months ago
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Posted by Kumar Sandarbh Vagish 4 years, 8 months ago
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Yogita Ingle 4 years, 8 months ago
When two cubes are joined end to end, then
Length of the cuboid = 6 + 6 = 12 cm
Breadth of the cuboid = 6 cm
Height of the cuboid = 6 cm
Total surface area of the cuboid = 2 (lb + bh + hi)
= 2(12 x6 + 6×6 + 6×12)
= 2(72 + 36 + 72) = 2(180) = 360 cm2
Posted by Navya Dwivedi 4 years, 8 months ago
- 1 answers
Yogita Ingle 4 years, 8 months ago
Let there be cone 1 and cone 2 respectively.
Let the r and R be the radii of the two right circular cones respectively.
Ratio of base radii = 3 : 5
Volume of cone = 1/3πr²h
⇒Volume of cone 1/Volume of cone 2
⇒ (1/3*πr²h)/(1/3πR²h)
⇒ (1/3*π*3²*h)/(1/3*π*5²*h)
= 3²/5²
= 9/25
= 9 : 25
So, the ratio of their volumes is 9 : 25
Posted by Sumit Chirania 4 years, 8 months ago
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Posted by Ram Ratan 4 years, 8 months ago
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Posted by Rahul Nik 4 years, 8 months ago
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Posted by Gaming Beast 4 years, 8 months ago
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Posted by Pinki Roy 4 years, 8 months ago
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Posted by Antram Sharma 4 years, 8 months ago
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Yogita Ingle 4 years, 8 months ago
The converse of the midpoint theorem states that ” if a line is drawn through the midpoint of one side of a triangle, and parallel to the other side, it bisects the third side”.
Posted by Premchand Hembrom 4 years, 8 months ago
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Posted by Dakshita Dharwal 4 years, 8 months ago
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Posted by Tushar Patel 4 years, 8 months ago
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Yogita Ingle 4 years, 8 months ago
P(x) = x3 - 3x2 - 9x - 5
Factors of 5 = 1,5,-1,-5
p(1) = 13 - 3 x (1)2 - 9 x (1) - 5
= 1 -3 - 9 - 5
= 1 - 17 = - 16 ≠ 0
p(-1) = (-1)3 x 3 x (-1)2 - 9 x (-1) -5
= -1 - 3 + 9 - 5 = -9 + 9 = 0
p(-1) =0
∴ (x+1) is a factor of p(x)
p(x) ÷ (x+1)
x3 - 3x2 - 9x - 5 ÷ x + 1
= x2 - 4x - 5
x2 - 4x - 5
= x2 - 5x + 1x - 5
= x ( x - 5) + 1 ( x - 5)
= ( x - 5) ( x + 1)
Posted by Hadhi Vs 4 years, 8 months ago
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Posted by Pankaj Kumar 4 years, 8 months ago
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Posted by Pankaj Kumar 4 years, 8 months ago
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