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If a diameter of circle bisect each of the two chord of a circle prove that chords are parallel

Posted by Rishu Singh 5 years ago

CBSE > Class 09 > Mathematics

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If x+2is a factor of x3+2ax2+ax-1 wht is the sol of a

Posted by Jigyasa Majoka 5 years ago

CBSE > Class 09 > Mathematics

1 answers

Yaadavi Tandon 5 years ago

We will find the ans by applying remainder theorem. We will put x=(-2) as (x+2) is the divisor. So, remaknder = 6a-7 As x+2 is tge factor of given pol. So, rem.=0 6a-7=0 6a=7 a=7/6

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Can someone give me xam idea class 9 maths promo code

Posted by Divick Pandey 5 years ago

CBSE > Class 09 > Mathematics

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4 = √4+√4+√4 ..... infinity

Posted by Shubham Raj 5 years ago

CBSE > Class 09 > Mathematics

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which are the important theorm of class 9 maths

Posted by Chirag Bhardwaj 5 years ago

CBSE > Class 09 > Mathematics

4 answers

Chandan Kumar 5 years ago

Theorms of circle

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Manasvi Balakrishna 5 years ago

Everything is imp. for class 9

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Divya Gehlot 5 years ago

Angle subtended by a an arc&cyclic qudrilatral

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Sudeep Darshan 5 years ago

All

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Two sides of a triangle are of length 5cm and 1.5cm. The length of the thired side of the triangle cannot be ? a-3.4cm b-3.6cm c-3.8 d-4.1

Posted by Yajat Gupta 5 years ago

CBSE > Class 09 > Mathematics

1 answers

Kyōka ( Demon Snow ) 5 years ago

3.4 cm

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a(a-1)-b(b-1) factorise

Posted by Anmol Jaiswal 5 years ago

CBSE > Class 09 > Mathematics

2 answers

Bhoomi Mutnale 5 years ago

(a²-a)-(b²+b)

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Rijul Arora 5 years ago

(a+b)(a-b)(a-b)

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Find the radius of a sphere whole surface area is 154cm

Posted by Akash Kadakol 5 years ago

CBSE > Class 09 > Mathematics

4 answers

Cutie Pie 5 years ago

Answer is 3.5cm

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Shilpi Singh 5 years ago

Ajggu

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Rijul Arora 5 years ago

3.5 cm

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Rijul Arora 5 years ago

3.5

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(√(10)−√(5))÷(2×√(2))

Posted by Saud Khan 5 years ago

CBSE > Class 09 > Mathematics

2 answers

Dharma Pal 5 years ago

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Keshav Kumar 5 years ago

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Find the value of (a)3 and (b)3 if root 3 + 1/root3_1

Posted by Alisha Khan 5 years ago

CBSE > Class 09 > Mathematics

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Ch 12 example 1

Posted by Ankit Bansal 5 years ago

CBSE > Class 09 > Mathematics

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Some important question of surface area and volume

Posted by Ishika Jain 5 years ago

CBSE > Class 09 > Mathematics

1 answers

Sebin Eapen 5 years ago

If TSA and CSA of a cuboid are 40 sq. cm and 26 sq. cm, find the surface area of base.

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Represent (1+9.5) on the number line

Posted by Ayush Singh 5 years ago

CBSE > Class 09 > Mathematics

1 answers

Rijul Arora 5 years ago

It is very easy

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1.3 question number 3 all answer

Posted by Bishal Bhuyan 5 years ago

CBSE > Class 09 > Mathematics

1 answers

Bishal Bhuyan 5 years ago

Vll

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Find the area of traingle the are 18cm 14cm 10 cm

Posted by Goutham Kumar 5 years ago

CBSE > Class 09 > Mathematics

2 answers

Seema Chandel 5 years ago

a=18cm b=14cm c=10cm s=18+14+10/2=42/2=21 By Heron's Formula area of triangle =√s(s-a) (s-b) (s-c) =√21(21-18)(21-14)(21-10) =√21×3×9×11 =√7×3×3×3×3×11 =3×3√7×11 =9√77cm^2

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Suryaveer Singh Chauhan 5 years ago

Under root 231

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The diameter of a roller is 84cm and length 120cm it 500 complete reviolation to move one cover 2 leval play ground of m.sq

Posted by Brajesh Bhadouria 5 years ago

CBSE > Class 09 > Mathematics

2 answers

Tiger Boos 5 years ago

T.s.a =2×22/7×42×120 =31680cm² Change = m =1584m²

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Gaurav Seth 5 years ago

Given,
Diameter = d = 84cm
Radius = r = d/2 = 42cm
Length = l = 120 cm
T.S.A of cylinder = 2πrh
= 2 x 22/7 x 42 x 120
= 31680 cm²
Area levelled by 500 revolution = Area of playground
= 500 x 31680cm²
= 15840000 cm² [ change into m]
= 1584 m²

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An isosceles triangle has perimeter 30 cm and each of the equal sides is 6 cm. Find the area of the triangle

Posted by Pradeep Chaudhary 5 years ago

CBSE > Class 09 > Mathematics

1 answers

Gaurav Seth 5 years ago

Length of the equal sides = 12cm
Perimeter of the triangle = 30cm
Length of the third side = 30 - (12+12) cm = 6cm
Semi perimeter of the triangle(s) = 30/2 cm = 15cm
Using heron's formula,
Area of the triangle = √s (s-a) (s-b) (s-c)
                                       = √15(15 - 12) (15 - 12) (15 - 6)cm2
                                       = √15 × 3 × 3 × 9 cm2
                                       = 9√15 cm2

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(1+tanA+secA)(1+cotA-cosec²A)=

Posted by Rohan Rauniyar 5 years ago

CBSE > Class 09 > Mathematics