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Let x = 0.666... {equation 1} Multiply both sides by 10. 10 × x = 10 × 0.6666... Therefore, 10x=6.666... {equation 2} Subtract equation 1 from equation 2. 10x-x = 6.666...- 0.666... 9x = 6 x = 6/9 x = 2/3 Ans.

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Ramesh Sawant 2 years, 3 months ago

X =0.6 bar 10×=6.6 bar Subtract both 10x -×=6.6-0.6 9×=6 ×=6/9 ×=2/3

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Prove that (a+b+c)^3 -a^3-b^3-c^3 =3(a+b) (b+c) (c+a)

Posted by Chinmayee Kumari Sahu 2 years, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Aanvi Saxena 2 years, 3 months ago

=>(a+b+c) 3 =(a 3 +3a 2 b+3ab 2 +b 3 )+3(a 2 +2ab+b 2 )c+3(a+b)c 2 +c 3 =>(a+b+c) 3 =a 3 +b 3 +c 3 +3a 2 b+3a 2 c+3ab 2 +3b 2 c+3ac 2 +3bc 2 +6abc =>(a+b+c) 3 =a 3 +b 3 +c 3 +3a 2 b+3a 2 c+3ab 2 +3b 2 c+3ac 2 +3bc 2 +3abc+3abc =>(a+b+c) 3 =a 3 +b 3 +c 3 +3a(ab+ac+b 2 +bc)+3c(ab+ac+b 2 +bc) =>(a+b+c) 3 =a 3 +b 3 +c 3 +3(a+c)(ab+ac+b 2 +bc) =>(a+b+c) 3 =a 3 +b 3 +c 3 +3(a+c)[a(b+c)+b(b+c)] =>(a+b+c) 3 =a 3 +b 3 +c 3 +3(a+c)(b+c)(a+b) =>(a+b+c) 3 −a 3 −b 3 −c 3 =3(a+c)(b+c)(a+b)

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Represent 0.7 bar in the form of p/q

Posted by Naman Kumar 2 years, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Atharva Shukla 2 years, 3 months ago

Let x = 0.7 bar Therefore, 10x = 7.7 bar 10x = 7+x 10x - x = 7 9x = 7 x = 7/9

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Ex 4.3

Posted by Sumit Mandal 2 years, 3 months ago

CBSE > Class 09 > Mathematics

2 answers

Yashika Tyagi 2 years, 3 months ago

Which question ?

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Mansvi Jhajharia 2 years, 3 months ago

Of which chapter?

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Xcube - 3x square-9x-5

Posted by Moksh Bhardwaj 2 years, 3 months ago

CBSE > Class 09 > Mathematics

0 answers

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Express 2x+1=x-3=-4

Posted by Himanshu Saini 2 years, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Sonam Sonam 2 years, 3 months ago

2/3

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(-9/14) + (-4/3)

Posted by Himanshi Sharma 2 years, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Gagan Goyal 2 years, 3 months ago

83/62

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How to represent 3+√2.6 on the number line

Posted by Kartiki Ghodke 2 years, 3 months ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

What is the sum of X2+ab-(45+3)

Posted by Kartiki Ghodke 2 years, 3 months ago

CBSE > Class 09 > Mathematics

0 answers

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2 + (-1) + [2×(-1)]+(-1)×(-1)×(-1)

Posted by Jeet Patel 2 years, 3 months ago

CBSE > Class 09 > Mathematics

2 answers

Ritika Poddar 2 years, 3 months ago

First open the brackets then solve it☺

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Ritika Poddar 2 years, 3 months ago

=2-1-2-1 = -2

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Express 0.1254 bar in the form of p upon 1

Posted by Benazir Sabha 2 years, 3 months ago

CBSE > Class 09 > Mathematics

2 answers

Ritika Poddar 2 years, 3 months ago

Let x =0.12541254..... (1) eqn. (1) ×10000=10000x =1254.1254....(2) Subtracting eqn.(1) from eqn.(2) ->10000x-x = 1254.1254...- 0.1254... 9999x = 1254 x = 1254/9999 = 139/1111 Thank you 🤗

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Simran Thapa 2 years, 3 months ago

1254 upon 10000

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Simplyfy 7root3minus5root2upon root48plus root18

Posted by Himani Singh 2 years, 3 months ago

CBSE > Class 09 > Mathematics