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Ask QuestionPosted by Shayia Banu 5 years, 8 months ago
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Posted by Vijay Mukind 5 years, 8 months ago
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Yogita Ingle 5 years, 8 months ago
{tex}let \: x = 0.12 \bar{5} \bar{4} \\ \\ or \: x = 0.12545454... \\ \\ 100x = 12.545454... \\ \\ 10000x = 1254.545454... \\ \\subtract : \\ 10000x - 100x = 1254.5454... - 12.5454... \\ \\ 9900x = 1242 \\ \\ x = \frac{9900}{1242} \\ \\ x = \frac{550}{69} \\ \\ thus \: \: \: 0.12 \bar{5} \bar{4} = \frac{550}{69} \:{/tex}
Posted by Vijay Mukind 5 years, 8 months ago
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Posted by Vijay Mukind 5 years, 8 months ago
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Posted by Sunny Yadav 5 years, 8 months ago
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Yogita Ingle 5 years, 8 months ago
0.4x + 0.3y=1.7...(1)
0.7x - 0.2y= 0.8...(2)
multiplying eq 1 by 2 & eq 2 by 3, we get
0.8x + 0.6y = 3.4..(3)
2.1x - 0.6y = 2.4..(4) now adding eq 3&4
2.9x= 5.8
x=5.8/2.9
x=2
putting the value of x in eq (1)
0.4×2 + 0.3y=1.7
0.3y= 1.7-0.8
y=0.9/0.3
y=3
Answer x=2 y=3
Posted by Shalini Chaurasia 5 years, 8 months ago
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Posted by Soham Dalwe 5 years, 8 months ago
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Posted by Lahari T 5 years, 8 months ago
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Posted by Anshu Singh Dudi 5 years, 8 months ago
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Yogita Ingle 5 years, 8 months ago
The pointy where graph cut x-axis and y-axis are x-intercept and y-intercept.
The x-intercept is when y=0,
2x+3(0)=12
2x=12
{tex}x=\frac{12}{2}{/tex}
x=6
So, Graph cut x-axis at (6,0).
The y-intercept is when x=0,
2(0)+3y=12
3y=12
{tex}y=\frac{12}{3}{/tex}
y=4
So, Graph cut y-axis at (0,4).
Refer the attached figure for graph.
Posted by Idk ;) 5 years, 8 months ago
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Jashandeep Kaur 5 years, 8 months ago
Meghna Thapar 5 years, 8 months ago
Fractions and decimals are not integers. All whole numbers are integers (and all natural numbers are integers), but not all integers are whole numbers or natural numbers. For example, -5 is an integer but not a whole number or a natural number.
Posted by Vansh Kumar 5 years, 8 months ago
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Shayia Banu 5 years, 8 months ago
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Posted by Harshit Singh 5 years, 8 months ago
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Shadan Ahmed 5 years, 8 months ago
Arpit Raj 5 years, 8 months ago
Posted by んム尺丂んノイ 丂丨几ム卄 5 years, 8 months ago
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Posted by んム尺丂んノイ 丂丨几ム卄 5 years, 8 months ago
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Posted by Harvinder Kaur 5 years, 8 months ago
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Posted by Krish Kharake 5 years, 8 months ago
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Yogita Ingle 5 years, 8 months ago
i) p(x) = 5x - 4x² + 3
On putting x=0 ,
p(0) = 5(0) - 4(0)² + 3
= 0 - 0 +3=3
= 3
ii) (x) = 5x - 4x² + 3
On putting x= -1,
p(-1) = 5(-1) - 4(-1)²+ 3
= -5 - 4(1) + 3
= -5-4+3= -9+3= -6
= -6
iii) p(x) = 5x - 4x² + 3
On putting x=2
p(2) = 5(2) - 4(2)² + 3
= 10 – 16 + 3 = -6+3
= -3
Posted by Raghu Nandhini 5 years, 8 months ago
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Venugopalarao Tamarapalli 5 years, 8 months ago
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