Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Jay Talati 5 years, 7 months ago
- 2 answers
Posted by Saiasish Nayak 5 years, 7 months ago
- 2 answers
Tripti Bala 5 years, 7 months ago
Posted by Pratik Kaul 5 years, 7 months ago
- 1 answers
Tripti Bala 5 years, 7 months ago
Posted by Pratikshya Mishra 5 years, 7 months ago
- 2 answers
Yogita Ingle 5 years, 7 months ago
Zeroes of a polynomial p(x) is real number ‘a’ for which polynomial p(x) if p(a) = 0.
E.g.: For p(x) = x-2 , p(2) = 2-2 =0. Thus 2 is zeroes for polynomial p(x)= x-2
Note: Every real number is a zero of the zero polynomial p(x)=0.
There is no Zero for polynomial p(x)=8.
Zeroes of a polynomial is special. It is used to find factors of equation p(x)=0.
Posted by Pratikshya Mishra 5 years, 7 months ago
- 1 answers
Yogita Ingle 5 years, 7 months ago
A non zero constant polynomial is of the form
f(x) = c, where c can be any real number except for 0.
For example f(x) = 9 is a non-zero constant polynomial.
Posted by Pratikshya Mishra 5 years, 7 months ago
- 3 answers
Posted by Rishi Singh 5 years, 7 months ago
- 0 answers
Posted by Jitendra Agrawal Agarwal 5 years, 7 months ago
- 0 answers
Posted by Kartikeya Srivastav 5 years, 7 months ago
- 2 answers
Posted by Raima Saini 5 years, 7 months ago
- 3 answers
Posted by Amarjeet Sharma 5 years, 7 months ago
- 2 answers
Posted by Priyanshu Parmar 5 years, 7 months ago
- 1 answers
Posted by Krishna Kumar 5 years, 7 months ago
- 0 answers
Posted by Abhishek Kumar 5 years, 7 months ago
- 1 answers
Posted by Jeevitha R 5 years, 7 months ago
- 1 answers
Posted by Murali Behera 5 years, 7 months ago
- 0 answers
Posted by Rohit Yadav 5 years, 7 months ago
- 3 answers
Posted by Rahul Rahul Kumar 5 years, 7 months ago
- 1 answers
Kartikeya Srivastav 5 years, 7 months ago
Posted by Amandeep Kour 5 years, 7 months ago
- 1 answers
Gaurav Seth 5 years, 7 months ago
Given, f(x) = px^2+5x+r and factors are x-2, x-1/2
Substitute x = 2 in place of equation, we get
= p*2^2+5*2+r=0
= 4p + 10 + r = 0 ------------ (i)
Substitute x = 1/2 in place of equation.
p/4 + 5/2 + r = 0
p + 10 + 4r = 0 ------------------- (ii)
On solving (i),(ii) we get
4p+r=-10 and p+4r+10=0
4p+r=p+4r
3p=3r
p = r.
Posted by Akash Jha 5 years, 7 months ago
- 1 answers
Posted by Pawan Singh 5 years, 7 months ago
- 0 answers
Posted by Arvind Yadav Yadav 5 years, 7 months ago
- 1 answers
Yogita Ingle 5 years, 7 months ago
(a -b) (a+ b) = a2 - b2
(4+√5) (4-√5) = (4)2 - (√5)2 = 16 - 5 = 11
Posted by Shivani Jain 5 years, 7 months ago
- 1 answers
Posted by Khushi Rani 5 years, 7 months ago
- 1 answers
Posted by Pooja Singh 5 years, 7 months ago
- 0 answers
Posted by Ayush Man Ayush Man 5 years, 7 months ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Jahanvi Sharma 5 years, 7 months ago
0Thank You