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Posted by Pinky,Bipul Mondal 4 years, 5 months ago
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Yogita Ingle 4 years, 4 months ago
6/x+11=2/x +9
6 (x + 9) = 2 ( x + 11)
6x + 54 = 2x + 22
6x - 2x = 22 - 54
4x = - 32
x = -32/4
x = - 8
Posted by Mritunjay Rai 4 years, 5 months ago
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Posted by Ayush Yadav 4 years, 5 months ago
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Posted by Vikas Kashyap 4 years, 5 months ago
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Meghna Thapar 4 years, 5 months ago
Positive Integer factors of 9999 = 3, 9, 11, 99, 101, 9999 divided by 3, 3, 11, 101, gives no remainder. They are integers and prime numbers of 9999, they are also called composite number. Largest four digit number can be formed using largest digit, say 9. We get, 9999 is the largest four digit number. Now we will find sum of smallest four digit number using only one digit and largest four digit number. Hence sum is 11110.
Posted by Shabd Kumar 4 years, 5 months ago
- 1 answers
Yogita Ingle 4 years, 5 months ago
{tex}\frac{\sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}}=a+\sqrt{15} b{/tex}
Rationalizing means the process of rationalizing the denominator, by rewriting the denominator for make the denominator into rational numbers.
Rationalizing the above equation so that,
{tex}\frac{\sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}} \times \frac{\sqrt{5}+\sqrt{3}}{\sqrt{5}+\sqrt{3}}=a+\sqrt{15} b{/tex}
[By multiplying {tex}\sqrt{5}+\sqrt{3}{/tex} in both numerator and denominator of the LHS of equation]
{tex}\frac{(\sqrt{5}+\sqrt{3})^{2}}{(\sqrt{5}-\sqrt{3})^{2}}=a+\sqrt{15} b{/tex}
[Since {tex}(a+b)^{2}=a^{2}+b^{2}+2 a b{/tex}
{tex}(a+b)(a-b)=a^{2}+b^{2}]{/tex}
{tex}\frac{5+3+2 \sqrt{5} \times \sqrt{3}}{(5-3)}=a+\sqrt{15} b{/tex}
{tex}\frac{8+2 \sqrt{15}}{(2)}=a+\sqrt{15} b{/tex}
{tex}4+\sqrt{15}=a+\sqrt{15} b{/tex}
{tex}4+\sqrt{15} \times 1=a+\sqrt{15} b{/tex}
By Comparing both side of the equations, then we get:
a= 4;b = 1
Posted by Praba Praba 4 years, 5 months ago
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Posted by Praba Praba 4 years, 5 months ago
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Yogita Ingle 4 years, 5 months ago
1) a(b+c+d)
= a(b) + a (c) + a(d)
= ab + ac + ad
2) p(6p2 -7p+5)
= p(6p2) - p(7p) + p (5)
= 6p3 - 7p2 + 5p
Posted by Praba Praba 4 years, 5 months ago
- 1 answers
Yogita Ingle 4 years, 5 months ago
1) -7a(-2b+3a)
= -7a(-2b) -7a (3a)
= 14 ab - 21 a2
2) -5×(4y-2z)
= - 5 (4y) - 5 (-2z)
= - 20 y + 10z
Posted by Praba Praba 4 years, 5 months ago
- 1 answers
Yogita Ingle 4 years, 5 months ago
1) 2×(3x+4y)
= 2(3x) + 2 (4y)
= 6x + 8y
2) 3a(2a- 5b)
= 3a (2a) - 3a (5b)
= 6a2 - 15 ab
Posted by Asha Sarda 4 years, 5 months ago
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Sarita Panda 4 years, 5 months ago
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Shabd Kumar 4 years, 5 months ago
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