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Ask QuestionPosted by Sangita Devi 4 years, 3 months ago
- 1 answers
Abhijeet Pawar 4 years, 3 months ago
Posted by Mrudula Peddireddy 4 years, 3 months ago
- 1 answers
Posted by Priya Kainth 4 years, 3 months ago
- 1 answers
Gaurav Seth 4 years, 3 months ago
Volume of a matchbox = 4 x 2.5 x 1.5 cm3 = 15 cm3
∴ Volume of a packet containing 12 such boxes = 15 x 12 cm3 = 180 cm3.
Posted by Akash S 4 years, 3 months ago
- 1 answers
Gaurav Seth 4 years, 3 months ago
Given, f(x) = px^2+5x+r and factors are x-2, x-1/2
Substitute x = 2 in place of equation, we get
= p*2^2+5*2+r=0
= 4p + 10 + r = 0 ------------ (i)
Substitute x = 1/2 in place of equation.
p/4 + 5/2 + r = 0
p + 10 + 4r = 0 ------------------- (ii)
On solving (i),(ii) we get
4p+r=-10 and p+4r+10=0
4p+r=p+4r
3p=3r
p = r
Posted by Akash S 4 years, 3 months ago
- 1 answers
Yogita Ingle 4 years, 3 months ago
According to Remainder Theorem, if a polynomial f(x) is divided by ( x - a), then f(a) will be the remainder.
f(x) = 8x⁴ - 8x2 + 7 and a = -1/2
f(-1/2) = 8(-1/2)⁴ - 8(-1/2)2 + 7
= 8 x (1/16) - 8 x (1/4) + 7
= 1/2 - 2 + 7
= 1/2 + 5
= 11/2
Posted by Akash S 4 years, 3 months ago
- 3 answers
Yogita Ingle 4 years, 3 months ago
30² + 20³ - 50³
= 900 + 8000 - 125000
= 8900 - 125000
= -116100
Gaurav Seth 4 years, 3 months ago
Different method to evaluate
1. 30³ + 20³ - 50³
= 27000 + 8000 - 125000
= 35000 - 125000
= -90000
OR
2. 30³ + 20³ - 50³
= (3*10)³ + (2*10)³ - (5*10)³
= 27*10³ + 8*10³ - 125*10³
= 10³(27 + 8 - 125)
= 1000(-90)
= -90000
OR
3. 30³ + 20³ - 50³
a³ + b³ = (a +b)³ - 3ab(a+b)
a = 30
b = 20
= (30 + 20)³ - 3(30)(20)(30 + 20) - 50³
= 50³ - 1800(50) - 50³
= -90000
Posted by Nidhika Khiani 4 years, 3 months ago
- 0 answers
Posted by Nidhika Khiani 4 years, 3 months ago
- 0 answers
Posted by Nidhika Khiani 4 years, 3 months ago
- 0 answers
Posted by Harpreet Singh 4 years, 3 months ago
- 1 answers
Dhanyatha S Maddodi 4 years, 3 months ago
Posted by Nidhika Khiani 4 years, 3 months ago
- 2 answers
Yogita Ingle 4 years, 3 months ago
The coordinates of a point on the x-axis are of the form (x, 0) and that of the point on the y-axis are (0, y). The coordinates of the origin are (0, 0).
Posted by Nidhika Khiani 4 years, 3 months ago
- 3 answers
Yogita Ingle 4 years, 3 months ago
The coordinates of a point on the x-axis are of the form (x, 0) and that of the point on the y-axis are (0, y). The coordinates of the origin are (0, 0).
Posted by Nidhika Khiani 4 years, 3 months ago
- 1 answers
Nidhika Khiani 4 years, 3 months ago
Posted by Shivam Kumar 4 years, 3 months ago
- 1 answers
Yogita Ingle 4 years, 3 months ago
(5x - 7)(2x+1)
= 5x (2x + 1) - 7 (2x +1)
= 10x2 + 5x - 14x - 7
= 10x2 - 9x - 7
Posted by Prajwal Bhovi 4 years, 3 months ago
- 0 answers
Posted by Shantnu Bhati 4 years, 3 months ago
- 0 answers
Posted by Nandika Singh 4 years, 3 months ago
- 1 answers
Posted by Om Pal Malik 4 years, 3 months ago
- 0 answers
Posted by Abhinav Singh 4 years, 3 months ago
- 1 answers
Posted by Tanishka Mate 4 years, 3 months ago
- 1 answers
Posted by Bhabana Sarma 4 years, 3 months ago
- 1 answers
Gaurav Seth 4 years, 3 months ago
ides of triangle are x, x+1, 2x-1
Area of triangle is
To find out:- Value of x
We Know That,
Semi-Perimeter(S)= Perimeter/2
=x+x+1+2x-1/2
=4x/2
=2x
Area Of Triangle=
or, =
or,
or,
or,
Squaring Both Sides, We get
or, 10=2(x-1)
or, 10=2x-2
or, 10+2=2x
or, 12/2 = x
or, 6 = x
Therefore, x = 6
Posted by Arjumand Khan 4 years, 3 months ago
- 0 answers
Posted by Akib Khan 4 years, 3 months ago
- 1 answers
Gaurav Seth 4 years, 3 months ago
The decimal expansion of an irrational number is non-terminating non-repeating.
There are infinitely many irrational numbers between 0.5 and 0.55
The two irrational numbers between 0.5 and 0.55 are of non-terminating and non-repeating decimal numbers. For example, 0.512122122212222 . and 0.539399399939999 .
Posted by Pauldurai Eswaran 4 years, 3 months ago
- 1 answers
Posted by Vikash Jaiswal 4 years, 3 months ago
- 4 answers
Priya Kainth 4 years, 3 months ago
Posted by Tanisha Chakrabarti 4 years, 3 months ago
- 1 answers
Gaurav Seth 4 years, 3 months ago
Question: If abc =1,then show that 1/(1+a+ b^(-1) )+ 1/(1+b+ c^(-1) )+ 1/(1+c+ a^(-1) ) = 1
Answer:
Posted by Prajwal Bhovi 4 years, 3 months ago
- 3 answers
Kashak Jadav 4 years, 3 months ago
Prajwal Bhovi 4 years, 3 months ago
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