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  • 4 answers

Surbhi Kadyan 1 year, 4 months ago

7.4

Akash Singh 1 year, 4 months ago

7.4

Mehk Kaur 1 year, 4 months ago

7.4

Arshdeep Kaur 1 year, 4 months ago

7.5
  • 1 answers

Ananya Agrawal 1 year, 4 months ago

There is a property named ANGLE SUM PROPERTY which proves that the sum of all sides of triangle is 180 .
  • 1 answers

Abhishek Sharma 1 year, 4 months ago

4 π r² = 4 x 22 / 7 x (21/2)² = 1386 sq cm
  • 2 answers

Akash Singh 1 year, 4 months ago

25√5

Manoranjan Panigrahi 1 year, 4 months ago

25√5
  • 0 answers
  • 2 answers

Sabir Hussain 1 year, 4 months ago

Question no,.5

Sadiya Bano 1 year, 4 months ago

I don't know
  • 0 answers
  • 4 answers

Surbhi Kadyan 1 year, 4 months ago

The highest power of the variable in a polynomial

Karan Gupta 1 year, 5 months ago

2

Karan Gupta 1 year, 5 months ago

I do not know

Nandini Choudhary 1 year, 5 months ago

2
  • 3 answers

Abhishek Sharma 1 year, 4 months ago

CSA of right circular cylinder= 2 π rh 88 = 2 x 22 /7 x r x 14 r = 88 x 7 ÷ ( 2 x 22 x 14 ) r = 1 cm

Mahi Agarwal 1 year, 4 months ago

9

Adarsh Kumar 1 year, 5 months ago

2
  • 2 answers

Isha Patel 1 year, 4 months ago

256

Adarsh Kumar 1 year, 5 months ago

256
  • 2 answers

Chitresh Kumar 1 year, 5 months ago

Formula

Chitresh Kumar 1 year, 5 months ago

l = √(15)×(15)+(15)×(15)
  • 1 answers

Anshika Sahu 1 year, 4 months ago

x = -5 , x= -3
  • 0 answers
  • 1 answers

Chirag Sharma 1 year, 5 months ago

17√5 + 5√3 - √2
  • 2 answers

Chirag Sharma 1 year, 5 months ago

180

Uttam Verma 1 year, 5 months ago

Match box is a cuboid having its length(l), breadth(b) and height(h) as 4 cm, 2.5 cm and 1.5 cm respectively. Volume of 1 match box = l × b × h = ( 4 × 2.5 × 1.5 ) c m 3 = 15 c m 3 Hence, Volume of 12 such matchboxes = ( 15 × 12 ) c m 3 = 180 c m 3
  • 2 answers

Arshdeep Kaur 1 year, 3 months ago

1

Ashutosh Chauhan 1 year, 5 months ago

1
  • 3 answers

Arshdeep Kaur 1 year, 3 months ago

P(x)=5x+8/11=0≈5x=11/8≈x=11/8×5≈x=11/40

Uttam Verma 1 year, 5 months ago

p(0)=5(0)+8/11 p(0)=8/11

R K 1 year, 5 months ago

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  • 2 answers

Uttam Verma 1 year, 5 months ago

Inner radius of hemispherical bowl = 5 cm Thickness of the bowl = 0.25 cm ∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm = 5.25 cm Outer CSA of hemispherical bowl = 2r2 Therefore, the outer curved surface area of the bowl is 173.25 cm2.

Uttam Verma 1 year, 5 months ago

r = 5 c m , thickness of steel sheet = 0.25 c m ⇒ R = 5 c m + 0.25 c m = 5.25 c m outer curved surface area of the bowl = 2 π R 2 = 2 × 22 7 × 525 100 × 525 100 c m 2 = 173.25 c m 2

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