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Shreya Singh 5 years, 4 months ago
Gaurav Seth 5 years, 4 months ago
Question -3 Find five rational numbers between 3/5 and 4/5.
Solution: Since we want five numbers, we write 3/5 and 4/5 So multiply in numerator and denominator by 5+1 =6 we get
Posted by Shruti Padhan 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
0
If a point lies on the x-axis then its y-coordinate is 0. Similarly, a point on the y-axis has its x-coordinate 0. The origin has coordinates (0,0). On the right you see an example of a (Cartesian) coordinate plane with some points sketched in it.
Posted by Tulendra Chandrakar 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
{tex}P(x)=x^3+3x^2+5x+6{/tex}
g(x)=x+2
x=-2
put x=-2 in p(x)
{tex}p(-2)=(-2)^3+3(-2)^2+5(-2)+6{/tex}
=-8+12-10+6
=0
since p(x) is zero
x+2 is a factor of {tex}x^3+3x^2+5x+6{/tex}
Posted by Ashish Mor 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
Mean = 15
Sum = 15 x 6
= 90
10+12+18+13+17+x=90
60+x=90
x = 90-60
x = 30
Verification:-
Mean =
Hence, verified
Posted by Aditya Koshti 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
(2x – y + 3z) (4x2 + y2 + 9z2+ 2xy + 3yz – 6xz).
=(2x+(-y)+z) {(2x)²+y²+(3z)²-(2x)(-y)-(-y)(3z)-(3z)(2x)
It is based on this formula
=a³+b³+c³-3abc
=2x³+(-y)³+3z³-3(2x)(-y)(3z)
=2x³+(-y)³+3z³+18xyz
Posted by Sunita Sethi 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
यहाँ पर,
ताश की गड्डी में पत्तों की कुल संख्या = 52
∴ सभी संभव परिणामों की संख्या = 52
1. हुकुम के पत्तों की संख्या = 13
अनुकूल परिणामों की संख्या = 13
अत: P(हुकुम का पत्ता) = 
2. kALE PATTE : 13 + 13 = 26
अनुकूल परिणामों की संख्या = 26
अत: P =13 / 26 = 1/2
3. ईंट की इक्का की संख्या = 1
अनुकूल परिणामों की संख्या = 1
अत: P(एक ईंट की बेगम) = 
Posted by Saloni Chauhan 5 years, 4 months ago
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Prashasti Pandey 5 years, 4 months ago
Gaurav Seth 5 years, 4 months ago
Question
Find six rational numbers between 3 and 4.
Solution: Since we want six numbers, we write 1 and 2 as rational numbers with denominator 6 + 1 =7
So multiply in numerator and denominator by 7 we get
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Yogita Ingle 5 years, 4 months ago
x= 3 - √7
(x) 2 =( 3 - √7)
= 32 +√72 - 2 (3) √7
= 9 + 7 - 6 √7
= 16 - 6√7
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Posted by Bhabana Sarma 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
We know that The equation of line which is parallel to x-axis is y = k.
Given that, Equation of line passes through (3,2) so, y = 2 , x = 3.
So, The equation of line is y = 2 .
Posted by Bhabana Sarma 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
Answer:
Step-by-step explanation:
/* By algebraic identity:
a³+3a²b+3ab²+b³ = (a+b)³ */
Therefore,
Posted by Bhabana Sarma 5 years, 4 months ago
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Gaurav Seth 5 years, 4 months ago
We know that,x3 - y3 = (x - y)(x² + xy + y²) ....(i)
Given that, x/y + y/x = -1
(x² + y²)/xy = -1
x² + y² = -xy
x² + y² + xy = 0
(x² + xy + y²) = 0
Multyplying by (x - y) on both sides we get,(x - y)(x² + xy + y²) = (x - y) × 0
x3 - y3 = 0 using (i)
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Gaurav Seth 5 years, 4 months ago
3. A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4cm. (see fig. 13.11). Find its
(i) inner curved surface area,
(ii) outer curved surface area
(iii) total surface area
(Assume π=22/7)
Solution:
Let r1 and r2 Inner and outer radii of cylindrical pipe
r1 = 4/2 cm = 2 cm
r2 = 4.4/2 cm = 2.2 cm
Height of cylindrical pipe, h = length of cylindrical pipe = 77 cm
(i) curved surface area of outer surface of pipe = 2πr1h
= 2×(22/7)×2×77 cm2
= 968 cm2
(ii) curved surface area of outer surface of pipe = 2πr2h
= 2×(22/7)×2.2×77 cm2
= (22×22×2.2) cm2
= 1064.8 cm2
(iii) Total surface area of pipe = inner curved surface area+ outer curved surface area+ Area of both circular ends of pipe.
= 2r1h+2r2h+(r12-r22)
= 9668+1064.8+2(2.22-22)
= 2031.8+5.28
= 2038.08 cm2
Therefore, the total surface area of the cylindrical pipe is 2038.08 cm2.
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