Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Sana Khan 4 years, 2 months ago
- 1 answers
Posted by Sowparnika Ram 4 years, 2 months ago
- 4 answers
Shehrebanu .... 4 years, 2 months ago
Posted by Shine Rai 4 years, 2 months ago
- 3 answers
Gaurav Seth 4 years, 2 months ago
Let 'x' be 0.47(bar on 7).
Since the number of repeating decimal is 1,we should multiply x and it's value with 10.
10*x=10*0.47(bar on 7).
10x=4.77(bar on 7).
Now, we should subtract x and it's value from 10x and it's value.
10x-x=4.77(bar on 7)-0.47(bar on 7).
9x=4.3(bar gets cancelled).
x=4.3/9.
This still needs to be multiplied with 10 in order to make p also an integer.
43/90 is the p/q form of 0.47(bar on 7) where p and q are integers and q is mot equal to 0.
Posted by Roshan Suna 4 years, 2 months ago
- 4 answers
Shehrebanu .... 4 years, 2 months ago
Yogita Ingle 4 years, 2 months ago
104×96
= (100 + 4) 96
= 96 (100) + 96(4)
= 9600 + 384
= 9984
Posted by Roshan Suna 4 years, 2 months ago
- 1 answers
Dharmesh Jagrat 4 years, 2 months ago
Posted by Sourabh Sasture 4 years, 2 months ago
- 3 answers
Rishikesh Patidar 4 years, 2 months ago
Ash Greninja 4 years, 2 months ago
Posted by Daksh Arora 4 years, 2 months ago
- 1 answers
Yogita Ingle 4 years, 2 months ago
In order to prove that the sum of angles of a triangle is 180, you must know the theorems of angles of a triangle.
We know that, alternate interior angles are of equal magnitude.
This'll help us get the answer. Let us assume a triangle ABC. Now we have to substitute the angles.
∠PAB + ∠BAC + ∠CAQ = 180°. where PQ line parallel to side BC touching vertex A.
∠PAB = ∠ABC & ∠CAQ = ∠ACB BECAUSE alternate interior angles are congruent..
Hence we get, ∠ABC + ∠BAC + ∠ACB = 180° [Proved]
Posted by Punita Raja Piush 4 years, 2 months ago
- 1 answers
Posted by Kavi Pavi 4 years, 2 months ago
- 4 answers
Shehrebanu .... 4 years, 2 months ago
Sreya Dutta 4 years, 2 months ago
Posted by Nidhi Singh 4 years, 2 months ago
- 1 answers
Ash Greninja 4 years, 2 months ago
Posted by Nidhi Singh 4 years, 2 months ago
- 1 answers
Shehrebanu .... 4 years, 2 months ago
Posted by Naveen Jain 4 years, 2 months ago
- 1 answers
Alok Gupta 4 years, 2 months ago
Posted by Mufeedha S 4 years, 2 months ago
- 2 answers
Gaurav Seth 4 years, 2 months ago
A n s w e r:
x = 2 , y = 5
S t e p-b y-s t e p e x p l a n a t i o n:
x = 2
2y-3 = 7
2y = 10
y = 5
Posted by Sachchidanand 9119 4 years, 2 months ago
- 1 answers
Gaurav Seth 4 years, 2 months ago
• The axiom is a statement which is self evident.
But,a theorem is a statement which is not self evident.
• An axiom cannot be proven by any kind of mathematical representation.
But, a theorem can be proved by mathematical representation.
• A theorem can be proved or derived from the axioms.
But,axioms cannot be proven or derived by the theorems.
Posted by Garima Chaudhary 4 years, 2 months ago
- 1 answers
Silviya Shrivastav 4 years, 2 months ago
Posted by Harsh Gupta 4 years, 2 months ago
- 5 answers
Cm| Black Bolt 4 years, 2 months ago
Posted by Azhar Mulla 4 years, 2 months ago
- 3 answers
Posted by Femely Shaji 4 years, 2 months ago
- 2 answers
Yogita Ingle 4 years, 2 months ago
2x2 - 9x + 4
= 2x2 - 8x - x + 4
= 2x ( x - 4) - 1 ( x - 4)
= (x - 4) (2x - 1)
Posted by Yagneswar Gorriparthi 4 years, 2 months ago
- 1 answers
Yogita Ingle 4 years, 2 months ago
Given,
p(x) = 2x²-3x+7a
2 is the zero of the polynomial
So, substitution
p(2) = 0
p(2) = 2(2)2 - 3x + 7a
0 = 2(4)-3(2)+7a
0 = 8-6+7a
0 = 2+7a
-2 = 7a
-2/7 = a
-2/7 = a
The value of a is -2/7
Posted by Vishal Kumar 4 years, 2 months ago
- 1 answers
Posted by Vishal Kumar 4 years, 2 months ago
- 2 answers
Roshan Chand 4 years, 2 months ago
Roshan Chand 4 years, 2 months ago
Posted by Vishal Kumar 4 years, 2 months ago
- 3 answers
Yogita Ingle 4 years, 2 months ago
Given class interval (40-60)
Lower limit = 40
Upper limit = 60
Class mark = (40 + 60)/2
= 100/2
= 50
Therefore, Class mark of the class interval 40-60 is 50.
Posted by Ramohan Maddipati 4 years, 2 months ago
- 1 answers
Gaurav Seth 4 years, 2 months ago
Given a quadrilateral ABCD in which ∠C = 90º, AB = 9 m, BC = 12 m, CD = 5 m & AD = 8 m.
Join the diagonal BD which divides quadrilateral ABCD in two triangles i.e ∆BCD & ∆ABD.
In ΔBCD,
By applying Pythagoras Theorem
BD²=BC² +CD²
BD²= 12²+ 5²= 144+25
BD²= 169
BD = √169= 13m
∆BCD is a right angled triangle.
Area of ΔBCD = 1/2 ×base× height
=1/2× 5 × 12= 30 m²
For ∆ABD,
Let a= 9m, b= 8m, c=13m
Now,
Semi perimeter of ΔABD,(s) = (a+b+c) /2
s=(8 + 9 + 13)/2 m
= 30/2 m = 15 m
s = 15m
Using heron’s formula,
Area of ΔABD = √s (s-a) (s-b) (s-c)
= √15(15 – 9) (15 – 9) (15 – 13)
= √15 × 6 × 7× 2
=√5×3×3×2×7×2
=3×2√35
= 6√35= 6× 5.92
[ √6= 5.92..]
= 35.52m² (approx)
Area of quadrilateral ABCD = Area of ΔBCD + Area of ΔABD
= 30+ 35.5= 65.5 m²
Hence, area of the park is 65.5m²
Posted by Sumith Singh Sumith Singh 4 years, 2 months ago
- 0 answers
Posted by Femely Shaji 4 years, 2 months ago
- 3 answers
Yogita Ingle 4 years, 2 months ago
5x2 + 16x + 3 = 0
5x2 + 15x + x + 3 = 0
5x ( x + 3) + 1 (x + 3) =0
(x + 3) (5x + 1) =0
x + 3 = 0 or 5x + 1 =0
x = -3 or 5x = -1
x = -3 or x = -1/5
Posted by Femely Shaji 4 years, 2 months ago
- 0 answers
Posted by Chanchal Patil 4 years, 2 months ago
- 2 answers
Gaurav Seth 4 years, 2 months ago
Posted by Mishika Pandey 4 years, 2 months ago
- 2 answers
Yogita Ingle 4 years, 2 months ago
Decimal form of 3/13 is 0.2307692. Decimal expansion is the Terminating and repeating which is about 9th numbers is repeating it.
Converting the fraction to the decimal which is easily dividing numerator by denominator is the correct answer that is 0.2307692.
Get 3/13 converted to decimal with dividing 3 by 13.3 /13 as a decimal are then converted into the above aspects.
Posted by Krish Jaiswal 4 years, 2 months ago
- 1 answers
Cm| Black Bolt 4 years, 2 months ago
Posted by Rishav Thakur 4 years, 2 months ago
- 0 answers
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Shivanya R 4 years, 2 months ago
1Thank You