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Ask QuestionPosted by Digvijay Singh Puhan 5 years, 3 months ago
- 2 answers
Pradeep Mehta 5 years, 3 months ago
Posted by Neha Pilare 5 years, 3 months ago
- 2 answers
Yogita Ingle 5 years, 3 months ago
(a)2x + y = 7......(1)
On putting x=0 in equation 1
2x+y=7
2×0+y=7
0+y=7
y=7
So( 0, 7) is a solution of given equation.
let y=0
2x+y=7
2x+0=7
2x=7
X= 7/2
So(7/2,0) is a solution of given equation.
let x = 1
2x+y=7
2×1+y=7
2+y=7
Y= 7-2
Y=5
(1,5) is the solution.
let x = 2
2x+y=7
2×2+y=7
4+y=7
Y= 7-4
Y= 3
The solution is (2,3)
Hence, 4 out of the infinitely many solutions of the given equation are(0,7), (7/2,0),(1,5),(2,3)
(b) πx + y = 9
let x = 0
πx + y = 9
π×0+y =9
0+y= 9
Y=9
(0,9) is the solution.
Let y = 0
πx + y = 9
πx+0=9
πx=9
x= 9/π
(9/π,0) is the solution.
Let x = 1
πx + y = 9
π×1+y=9
π+y=9
Y= 9-π
(1,9-π) is the solution.
Let x = -1
πx + y = 9
π×-1+y=9
-π+y=9
Y= 9+π
(-1,9+π) is the solution.
Hence, 4 out of the infinitely many solutions of the given equation are(0,9), (9/π,0),(1,9-π),(-1,9+π)
(c) x= 4y
Let x = 0
X=4y
0=4y
Y=0/4=0
Y=0
(0,0) is the solution.
Let x= 1
X=4y
1=4y
Y= 1/4
(1,1/4) is the solution.
Let y = 1
X=4y
X=4×1
X=4
(4,1) is the solution.
Let x = 2
X=4y
2=4y
Y=2/4
Y=1/2
(2,1/2) is the solution.
Hence, 4 out of the infinitely many solutions of the given equation are(0,0), (1,1/4),(4,1),(2,1/2)
Posted by Migo Bagra 5 years, 3 months ago
- 1 answers
Silviya Shrivastav 5 years, 3 months ago
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- 3 answers
Ish Anand 5 years, 3 months ago
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- 4 answers
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- 1 answers
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- 3 answers
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- 1 answers
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- 4 answers
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- 1 answers
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- 1 answers
Krishnam Sarda 5 years, 3 months ago
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- 2 answers
Yogita Ingle 5 years, 3 months ago
Put x=2 and y=3
3x+2y=t
t = 3(2) + 2 (3)
t = 6 + 6
t = 12
Posted by Rohan Patil 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
Put x=1,y=0
[k+2/k-1]x -[3k-2/k+2]y-3=0
(k2 + 2 - k)/k] 1 -[3k-2/k+2]0-3=0
(k2 + 2 - k)/k] = 3
k2 + 2 - k = 3k
k2 + 2 - k -3k = 0
k2 -4k+ 2= 0
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Ash Greninja 5 years, 3 months ago
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Jagjeet Kaur 5 years, 3 months ago
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