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Ask QuestionPosted by Ayush Tiwari 4 years ago
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Posted by Avinash 8055 4 years ago
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Posted by T S 4 years ago
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Posted by Abhilasha Jhudele 4 years ago
- 1 answers
Gaurav Seth 4 years ago
The curved surface area of a cylinder is 1210cm square and its diameter is 20 cm . Find its height and volume
Posted by Aryan Sunil 4 years ago
- 2 answers
Posted by Amit Raj 4 years ago
- 2 answers
Gaurav Seth 4 years ago
(i) Given:
Diameter of the spherical ball (d)= 28 cm
Radius =d/2= 28/2 cm = 14 cm
Amount of water displaced by a solid spherical ball = Volume of spherical ball = 4/3πr³
= (4/3 × 22/7 × 14 × 14 × 14)
= 34496/3 = 11498.67 cm³
Amount of water displaced by a solid spherical ball= 11498.67 cm³
(ii) Diameter of the spherical ball (d)= 0.21 m
Radius (r) = d/2= 0.21/2 m = 0.105 m
Amount of water displaced by a solid spherical ball = Volume of spherical ball= 4/3πr³
=(4/3×22/7×0.105×0.105×0.105)
= 0.004851 m³
Amount of water displaced by a solid spherical ball =0.004851 m³
Posted by Ariba Bano Class 10 4 years ago
- 1 answers
Yogita Ingle 4 years ago
Given, side of an equilateral triangle is 4√3 cm.
Area of an equilateral triangle = √3/4 (Side)2
= √3/4 (4√3)2 = (√3/4) x 16 x 3
= 3√3 x 4 = 12 x 1.732 = 20.784 cm2
Hence, the area of an equilateral triangle is 20.784 cm2.
Posted by Nishant Kumar 4 years ago
- 5 answers
Posted by Muskan Singh 4 years ago
- 1 answers
Gaurav Seth 3 years, 11 months ago
Diameter of Copper Sphere = 18 cm
Radius = 9 cm [Radius = Diameter / 2]
Length of cylindrical wire = 108 m or 10800 cm [ 1 m = 100 cm]
Let radius of cylindrical wire be R
Since wire is made by melting the sphere
∴ Volume of Cylindrical wire = Volume of Copper Sphere
[Volume of Cylinder = π × Radius² × height and
Volume of Sphere = (4/3)×π×Radius³]
∴ π × R² × 10800 = (4/3) × π × (9)³
Dividing both sides by π
R² × 10800 = (4/3) × (9)³
Taking Square Root of both sides
R = 0.30 cm
Radius of wire = 0.3 cm or 3 mm
[∵ Diameter = 2×Radius]
∴Diameter of wire = 0.6 cm or 6 mm
Posted by Satyam Kumar 4 years ago
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Posted by Satyam Kumar 4 years ago
- 2 answers
Gaurav Seth 4 years ago
bac = y as they are corresponding angles since ac is parallel to de
then,
cda=90 (as my assumption) cdg+y+25=90
cdg+20+25=90; cdg=45
cdg+20 i mean 45 +20 =65=acd (alternate angles)
x+acd=180 (linear pair)
x+65=180
x=115
Posted by Rajani Naik 4 years ago
- 1 answers
Gaurav Seth 4 years ago
Draw the graph of the equation represented by the straight line which is parallel to the x-axis and is 4 units above it. Solution : Any straight line parallel to x-axis is given by y = k, where k is the distance of the line from the x-axis. Here k = 4. Therefore, the equation of the line is y = 4. To draw the graph of this equation, plot the points (1, 4) and (2, 4) and join them. This is the required graph
Click the given link:
<a href="https://ncert.nic.in/ncerts/l/ieep204.pdf" ping="/url?sa=t&source=web&rct=j&url=https://ncert.nic.in/ncerts/l/ieep204.pdf&ved=2ahUKEwjniObt45XsAhWTj-YKHQ-zAuwQFjAZegQICxAC" rel="noopener" target="_blank">linear equations in two variables - ncert</a>
Go to page no. 38
and see Sample Question 4
Posted by Santosh Ram 4 years ago
- 2 answers
Gaurav Seth 4 years ago
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The length and breadth of a cuboid are in the ratio 4 : 5. The height and total surface area |
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Answer:
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Posted by Sourav Singh 4 years ago
- 1 answers
Gaurav Seth 3 years, 11 months ago
Here,
1 metric ton = 1000 kg
So, 90 metric ton = 90×103 kg
m = 9×104 kg
h = 200 m
g = 9.8 ms-2
Time taken = 1 hr = 3600 s
The potential energy of a mass m raised to a height h = mgh
Now to raise a mass 9×104 kg to a height 200 m we must do work equal to the potential energy of the mass at 200 m.
Potential energy of mass at 200 m = mgh= 9×104×9.8×200 Joule
So, work done must be = 9×104×9.8×200 Joule
Again we know power P = work done / time taken
P = 9×104×9.8×200/3600 = 49000 watt. or 49 kW
Posted by Tanmay Lende 4 years ago
- 1 answers
Gaurav Seth 4 years ago
(5a+3b)³ - (5a-3b)³
= (5a)³+3*(5a)²*3b+3*5a*(3b)²+(3b)³- [(5a)³-3*(5a)²*3b+3*5a*(3b)²-(3b)³]
=(5a)³+3*(5a)²*3b+3*5a*(3b)²+(3b)³-(5a)³+3*(5a)²*3b-3*5a*(3b)²+(3b)³
=2*3*(5a)²*3b+2*(3b)³
=450a²b+54b³
Posted by Ankit Raj 4 years ago
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Posted by Manish Jevaliya 4 years ago
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Posted by Harpreet Kaur 4 years ago
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Posted by Shubham Chopra 4 years ago
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Posted by Aditya Kumar 3 years, 9 months ago
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Posted by Panu Sahu 4 years ago
- 2 answers
Gaurav Seth 4 years ago
Radius of circle = 50/2 = 25 cm
perpendicular distance = 24 cm
Therefore, By Pythagoras theorem:
Hypotenuse² = Base² + Perpendicular ²
25² = Base² + 24²
Base² = 625 - 576
Base² = 49
Base = 7
Chord = 2 × Base
Chord = 2 × 7
Answer: 14 cm
Posted by Jashanpreet Singh 4 years ago
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Tamanna Yadav 4 years ago
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Posted by Manya Manjunatha 4 years ago
- 2 answers
Devashish Kumar 4 years ago
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Meghna Thapar 4 years ago
Heron's Formula -- An algebraic proof
where b is the length of a base and h is the height to that base. There is at least one side of our triangle for which the altitude lies "inside" the triangle. For convenience make that the side of length c. It will not make any difference, just simpler. Heron's formula computes the area of a triangle given the length of each side. If you have a very thin triangle, one where two of the sides approximately equal s and the third side is much shorter, a direct implementation Heron's formula may not be accurate.
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