Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Dimple Verms 4 years ago
- 1 answers
Gaurav Seth 4 years ago
8. Find three different irrational numbers between the rational numbers 5/7 and 9/11.
Solution:
Three different irrational numbers are:
- 0.73073007300073000073…
- 0.75075007300075000075…
- 0.76076007600076000076…
Posted by Tanu Shree 4 years ago
- 2 answers
Posted by Muskan Kumari 4 years ago
- 1 answers
Gaurav Seth 4 years ago
In triangle ABC
a-b=33
a=33+b ------------1
b-c=18
c=b-18 ------------2
Now in triangle abc by angle sum property
a+b+c=180
33+b+b+b-18=180 (by 1 and 2)
15+3b=180
3b=180-15
3b=165
b=165/3
b=55
Now put value of b in eq. 1 and 2
a-b=33
a-55=33
a=33+55
a=88
b-c=18
55-c=18
c=55-18
c=37
Your answer is:
a=88
b=55
c=37
Posted by Rani ? 4 years ago
- 1 answers
Posted by Krishna Sharma 4 years ago
- 1 answers
Posted by Varun Dharne 4 years ago
- 2 answers
Aliza Taufiq 4 years ago
Gaurav Seth 4 years ago
1. The angles of quadrilateral are in the ratio 3 : 5 : 9 : 13. Find all the angles of the quadrilateral.
Solution:
Let the common ratio between the angles be = x.
We know that the sum of the interior angles of the quadrilateral = 360°
Now,
3x+5x+9x+13x = 360°
⇒ 30x = 360°
⇒ x = 12°
, Angles of the quadrilateral are:
3x = 3×12° = 36°
5x = 5×12° = 60°
9x = 9×12° = 108°
13x = 13×12° = 156°
Posted by M U 4 years ago
- 4 answers
Posted by M U 4 years ago
- 2 answers
Gaurav Seth 4 years ago
Let us convert 5/7 and 9/11 into decimal form, to get
5/7 = 0.714285... and 9/1 = 0.818181.... .
Three irrational numbers that lie between 0.714285.... and 0.818181.... are:
0.73073007300073….
0.74074007400074….
0.76076007600076….
Posted by Shreyansh Sutariya 4 years ago
- 4 answers
Kashak Jadav 4 years ago
M U 4 years ago
Posted by Shreyansh Sutariya 4 years ago
- 5 answers
Posted by Ayush Singh 4 years ago
- 3 answers
Posted by Sanjana Bharti 4 years ago
- 2 answers
M U 4 years ago
Gaurav Seth 4 years ago
Suppose we have two rational numbers a and b, then the irrational numbers between those two will be, √ab. Now let us find two irrational numbers between two given rational numbers.
1. Find an irrational number between two rational numbers 2 – √3 and 5 – √3
Let x be the irrational number between two rational numbers 2 – √3 and 5 – √3. Then we get,
2 – √3 < x < 5 – √3
⇒ 2 < x + < √3 < 5
We see that x + √3 is an irrational number between 2 – √3 and 5 – √3 where 2 – √3 < x < 5 – √3.
2. Find two irrational numbers between two given rational numbers.
Now let us take any two numbers, say a and b. Let x be any number between a and b. Then,
We have a < x < b….. let this be equation (1)
Now, subtract √2 from both the sides of equation (1)
So, a – √2 < x < b – √2……equation (2)
= a < x + √2 < b
Addition of irrational number with any number results into an irrational number. So, x + √2 is an irrational number which exists between two rational numbers a and b.
Posted by Tisha Rajour 4 years ago
- 3 answers
M U 4 years ago
Yogita Ingle 4 years ago
Constant Polynomials : An expression consisting of only constants is called as constant polynomial.
For Example: 7, -27, 3, etc. are some constant polynomials.
Tisha Rajour 4 years ago
Posted by Shashank Aryan 4 years ago
- 1 answers
Gaurav Seth 4 years ago
Question 5. In Fig. 6.32, if AB || CD, ∠ APQ = 50° and ∠ PRD = 127°, find x and y.
Solution: Use property of Alternate interior angles
∠APR = ∠PRD
50° + y = 127°
y = 127° − 50°
y = 77°
use same property of Alternate interior angles
∠APQ = ∠PQR
50° = x
∠ x = 50° and y = 77°
Posted by Chandn Singh 4 years ago
- 3 answers
Agnes Jimmy 4 years ago
Posted by Anfal Pananghat 4 years ago
- 1 answers
Posted by Abhinandan Dubey 4 years ago
- 3 answers
Shubham Singh 4 years ago
Gaurav Seth 4 years ago
Answer
Bepin Babu said that he spent the Durga Puja of October 1958 in Kanpur and he didn’t go to Ranchi at all.
He went to Kanpur at his friend's Place in October '58'.
Posted by Ashmit Sharma 4 years ago
- 1 answers
Gaurav Seth 4 years ago
Answer:
Sides of the triangle are 20 cm, 16 cm, 12 cm
Step-by-step explanation:
Formula used:
If a, b, c are sides of triangle then
s=(a+b+c)/2
Given:
s-a=4 cm
s-b=8 cm
s-c=12 cm
Adding these we get
s+s+s-a-b-c = 24
3s-(a+b+c) =24
3s-2s = 24
s = 24
Now,
s-a=4
24 - a =4
a = 24 - 4 = 20 cm
s-b=8
24 - b = 8
b = 24 - 8 = 16 cm
s - c = 12
24 - c = 12
c = 24 -12 = 12 cm
Posted by Samruddhi Khonde 4 years ago
- 5 answers
Aarushi Erande 4 years ago
Posted by Vandana Bari 4 years ago
- 5 answers
Khushi Sawanliya 4 years ago
Abhinandan Dubey 4 years ago
Abhinandan Dubey 4 years ago
Aarushi Erande 4 years ago
Samruddhi Khonde 4 years ago
Posted by Vivek Vallyapur 4 years ago
- 1 answers
Vivek Vallyapur 4 years ago
Posted by Ananya Sharma 4 years ago
- 1 answers
Posted by Shravani Walke 4 years ago
- 2 answers
Arpit Agnihotri 4 years ago
Gaurav Seth 4 years ago
A n s w e r:
By Herons formula,
Area of equilateral triangle=√3a²/4
Given,
a= 2cm
Therefore,
Area of the triangle
= (√3a²/4) cm²
= (√3 × 2²/4) cm²
= (4√3 /4) cm²
= √3 cm²
Posted by Himanshi Arora 4 years ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Rishi Passi 4 years ago
2Thank You