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  • 1 answers

Niyatti Niyatti 5 years, 4 months ago

What to do
  • 2 answers

Aliza Taufiq 5 years, 4 months ago

1. The angles of quadrilateral are in the ratio 3 : 5 : 9 : 13. Find all the angles of the quadrilateral. Solution: Let the common ratio between the angles be = x. We know that the sum of the interior angles of the quadrilateral = 360° Now, 3x+5x+9x+13x = 360° ⇒ 30x = 360° ⇒ x = 12° , Angles of the quadrilateral are: 3x = 3×12° = 36° 5x = 5×12° = 60° 9x = 9×12° = 108° 13x = 13×12° = 156°

Gaurav Seth 5 years, 4 months ago

1. The angles of quadrilateral are in the ratio 3 : 5 : 9 : 13. Find all the angles of the quadrilateral.

Solution:

Let the common ratio between the angles be = x.

We know that the sum of the interior angles of the quadrilateral = 360°

Now,

3x+5x+9x+13x = 360°

⇒ 30x = 360°

⇒ x = 12°

, Angles of the quadrilateral are:

3x = 3×12° = 36°

5x = 5×12° = 60°

9x = 9×12° = 108°

13x = 13×12° = 156°

  • 4 answers

Anjali Joshi 5 years, 4 months ago

Irrational

Aaditya Mishra 5 years, 4 months ago

What's is polynomial

M U 5 years, 4 months ago

proof

Suraj Pratap 5 years, 4 months ago

Irrational number hai
  • 2 answers

M U 5 years, 4 months ago

Thanks a lot!!! ?

Gaurav Seth 5 years, 4 months ago

Let us convert 5/7 and 9/11 into decimal form, to get 

5/7 = 0.714285... and 9/1 = 0.818181.... .

Three irrational numbers that lie between 0.714285.... and 0.818181.... are:

0.73073007300073….

0.74074007400074….

0.76076007600076….

  • 4 answers

Anjali Joshi 5 years, 4 months ago

Ans: 1

Suraj Pratap 5 years, 4 months ago

1

Kashak Jadav 5 years, 4 months ago

If, 2a+1=3 We want to find value of A 2a=3-1 2a=2 a=2/2 a=1 Value of a=1

M U 5 years, 4 months ago

1.......let me proof = See 2a+1=3 ====2a=3-1=====2a=2=====a=2/2 by dividing it. We get, 1
  • 5 answers

Pragati Singh 5 years, 4 months ago

2

Suraj Pratap 5 years, 4 months ago

2

Manyata Joshi 5 years, 4 months ago

2

M U 5 years, 4 months ago

2

Shreyansh Sutariya 5 years, 4 months ago

2
  • 3 answers

Anjali Joshi 5 years, 4 months ago

5 is cofficent

Kashak Jadav 5 years, 4 months ago

In eqation 5x²+6x+3 coefficients is 5

Trishla Jain 5 years, 4 months ago

5 is the coefficient of x² in the polynomial 5x²+6x+3
  • 2 answers

M U 5 years, 4 months ago

This is just an example Let us convert 5/7 and 9/11 into decimal form, to get  5/7 = 0.714285... and 9/1 = 0.818181.... . Three irrational numbers that lie between 0.714285.... and 0.818181.... are: 0.73073007300073…. 0.74074007400074…. 0.76076007600076….

Gaurav Seth 5 years, 4 months ago

Suppose we have two rational numbers a and b, then the irrational numbers between those two will be, √ab. Now let us find two irrational numbers between two given rational numbers.

1. Find an irrational number between two rational numbers 2 – √3 and 5 – √3

Let x be the irrational number between two rational numbers  2 – √3 and 5 – √3. Then we get,
2 – √3 < x < 5 – √3
⇒ 2 < x + < √3 < 5
We see that  x + √3 is an irrational number between 2 – √3 and 5 – √3 where 2 – √3 < x < 5 – √3.

2. Find two irrational numbers between two given rational numbers.

Now let us take any two numbers, say a and b. Let x be any number between a and b. Then,
We have a < x < b….. let this be equation (1)
Now, subtract √2 from both the sides of equation (1)
So, a – √2 < x < b – √2……equation (2)
= a  < x + √2 < b
Addition of irrational number with any number results into an irrational number. So, x + √2 is an irrational number which exists between two rational numbers a and b.

  • 3 answers

M U 5 years, 4 months ago

A polynomial with degree 0 is called a constant polynomial. Any constant number for example, 3, 4/5, 679, 8.34 are examples of constant polynomials.

Yogita Ingle 5 years, 4 months ago

Constant Polynomials : An expression consisting of only constants is called as constant polynomial.
For Example: 7, -27, 3, etc. are some constant polynomials.

Tisha Rajour 5 years, 4 months ago

Constant polynomial: A constant polynomial is of the form p(x) = k, where k is a real number. For example, –9, 10, 0 are constant polynomials.
  • 1 answers

Gaurav Seth 5 years, 4 months ago

<div style="color: rgb(0, 102, 255); font-family: Helvetica, Roboto, Verdana, Geneva, sans-serif; font-size: 14px;">In Fig. 6.32, if AB || CD, ∠ APQ = 50° and ∠ PRD = 127°, find x and y.</div> <div style="color: rgb(0, 102, 255); font-family: Helvetica, Roboto, Verdana, Geneva, sans-serif; font-size: 14px;"> <div class="fontx">

Question 5. In Fig. 6.32, if AB || CD, ∠ APQ = 50° and ∠ PRD = 127°, find and y.

Solution: Use property of Alternate interior angles
∠APR = ∠PRD
50° + y = 127°
y = 127° − 50°
y = 77°
use same property of Alternate interior angles
∠APQ = ∠PQR
50° = x
∠ x = 50° and y = 77°

<div> </div> </div> </div>
  • 3 answers

Rut@J@ $Ingh 5 years, 4 months ago

False

Agnes Jimmy 5 years, 4 months ago

No ,this statement is wrong .numbers can be rational or irrational

Khushi Sawanliya 5 years, 4 months ago

No, it may be rational or irrational number
  • 1 answers

Rashika Maithil 5 years, 4 months ago

22500
  • 3 answers

Shubham Singh 5 years, 4 months ago

Bepin Babu said that he spent the Durga Puja of October 1958 in Kanpur and he didn’t go to Ranchi at all. He went to Kanpur at his friend's Place in October '58'.

Gaurav Seth 5 years, 4 months ago

Answer
Bepin Babu said that he spent the Durga Puja of October 1958 in Kanpur and he didn’t go to Ranchi at all.
He went to Kanpur at his friend's Place in October '58'.

Samruddhi Khonde 5 years, 4 months ago

Kanpur
  • 0 answers
  • 1 answers

Gaurav Seth 5 years, 4 months ago

Answer:

Sides of the triangle are 20 cm, 16 cm, 12 cm

Step-by-step explanation:

 

Formula used:

 

If a, b, c are sides of triangle then

 

s=(a+b+c)/2

 

 

Given:

s-a=4 cm

 

s-b=8 cm

 

s-c=12 cm

 

 

Adding these we get

 

s+s+s-a-b-c = 24

 

3s-(a+b+c) =24

 

3s-2s = 24

 

s = 24

 

 

Now,

 

s-a=4

 

24 - a =4

 

a = 24 - 4 = 20 cm

 

s-b=8

 

24 - b = 8

 

b = 24 - 8 = 16 cm

 

s - c = 12

 

24 - c = 12

 

c = 24 -12 = 12 cm

  • 5 answers

Samruddhi Khonde 5 years, 4 months ago

Thanks for answer

Samruddhi Khonde 5 years, 4 months ago

No I'm not navodayan...and all

Aarushi Erande 5 years, 4 months ago

•Putting x=2 and y=0 •We get 2×2 + 3×0 = k •So, 4 + 0= k • Hence the answer is, k=4

Satyam Gupta 5 years, 4 months ago

You are navodayan yes or not

Satyam Gupta 5 years, 4 months ago

4 hoga
  • 5 answers

Khushi Sawanliya 5 years, 4 months ago

Let the cost of notebooks is x And the cost of pen is y So , The linear equation is x = 2y

Abhinandan Dubey 5 years, 4 months ago

there! Have questions about your homework? At Brainly, there are 150 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D JOIN US!

Abhinandan Dubey 5 years, 4 months ago

Let, the cost of pen be Rs x and Cost of notebook is twice the cost of pen=Rs 2x It's given that cost of notebook = 2× cost of pen Therefore, x=2x x-2x=0 x-2x=0 is the linear equation in two variables.Let, the cost of pen be Rs x and Cost of notebook is twice the cost of pen=Rs 2x It's given that cost of notebook = 2× cost of pen Therefore, x=2x x-2x=0 x-2x=0 is the linear equation in two variables.

Aarushi Erande 5 years, 4 months ago

•Let the cost of the notebook be x and the cost of the pen be y •Now, the equation would be x = 2y. now putting any value for x or y we will get the coordinates. • Now you can draw the graph with this equation.

Samruddhi Khonde 5 years, 4 months ago

Let, the cost of pen be Rs x and Cost of notebook is twice the cost of pen=Rs 2x It's given that cost of notebook = 2× cost of pen Therefore, x=2x x-2x=0 x-2x=0 is the linear equation in two variables.
  • 1 answers

Vivek Vallyapur 5 years, 4 months ago

Rationalise the denominator of *   Option 1  Option 2  Option 3 
  • 1 answers

Ananya Sharma 5 years, 4 months ago

12345
  • 2 answers

Arpit Agnihotri 5 years, 4 months ago

Sides of equilateral triangle =2cm,2cm,2cm If a=2cm , b= 2cm and c=2 cm Then, s(semi perimeter)=(2+2+2)/2 =6/2 =3cm =s Now by, heron's Formula area of a triangle=√s(s-a)(s-b)(s-c) =√3(3-2)(3-2)(3-2) =√3(1)(1)(1) =√3 cm² Therefore area of equilateral triangle with sides 2cm each is √3cm².

Gaurav Seth 5 years, 4 months ago

A n s w e r:

By Herons formula,

Area of equilateral triangle=√3a²/4

Given,

a= 2cm

Therefore,

Area of the triangle

= (√3a²/4) cm²

= (√3 × 2²/4) cm²

= (4√3 /4) cm²

= √3 cm²

  • 0 answers
  • 0 answers
  • 0 answers
  • 2 answers

M U 5 years, 4 months ago

To construct 135 degree angle we first construct 90 degree angle and its steps of constructions are as follows:  1). Use ruler and draw a Line segment OB of any convenient length. (as shown below)   2). Now use compass and open it to any convenient radius. And with O as center , draw an arc which cuts line segment OB at X . (as shown below)   3). Again use compass and opened to the same radius (as of step 2). And with X as center , draw an arc which cuts first arc at D . (as shown below)   4). Again use compass and opened to the same radius (as of step 2). And with D as center , draw another arc which cuts first arc at C . (as shown below)   5). Again use compass and opened to the same radius (as of step 2). And With C & D as center, draw two arc which cuts each other atE . (as shown below)   6). Join OE and extent it to A. (as shown below)   7). Above formed angle AOB = 90 Degree .  8) . Extend BO to Z . (as shown below)   9). Since ZB is a straight line, so formed Angle AOZ = 90 Degree (angle sum property)   Now, to construct at 135 degree angle, we will construct the angle bisector of above angle AOB. And its done in the following steps:  10). Again use compass and open it to any convenient radius. And with O as center , draw an arc which cuts line segment OB at P and OA at Q . (as shown below)   11). Again use compass and opened to same radius (as of step 10).And with P & Q as center and, draw two arcs which cuts each other at point F. (as shown below)   12). Join OF and extend to E . (as shown below)   13). EO is the bisector of Angle AOB.  Therefore, Angle AOE = Angle EOB = ½ of Angle AOB = 45 Degree each (as shown below)   14). Now observe that:  Angle ZOA = 90°  Angle AOE = 45°  Add both the angles and we get  Angle ZOA + Angle AOE = 90° + 45° ..... (Statement 1)  Now observe the above diagram:  Angle ZOA + Angle AOE = Angle ZOE ..... (Statement 2)  From Statement 1 and 2, we get:  Angle ZOE = 135° (as highlighted with pink color)  

Gaurav Seth 5 years, 4 months ago

The steps of constructions are: 

(a) Draw a line PQ and take a point O on it.

(b) Taking O as the centre and convenient radius, mark an arc, which intersects PQ at A and B.

(c) Taking A and B as centres and radius more than half of AB, draw two arcs intersecting each other at R.

(d) Join OR. Thus, ∠QOR = ∠POQ = 90 .

(e) Draw OD the bisector of ∠POR. Thus, ∠QOD is the required angle of 135.

(f) Now, draw OE as the bisector of ∠QOD=1/2 of 135=67.5

  • 1 answers

Gaurav Seth 5 years, 4 months ago

AD and BC are equal perpendiculars to a line segment AB (see figure). Show that CD bisects AB.

<hr />

Given: AD and BC are equal perpendiculars to a line segment AB.
To Prove: CD bisects AB.
Proof: In ∆O AD and ∆OBC
AD = BC    | Given
∠OAD = ∠OBC    | Each = 90°
∠AOD = ∠BOC
| Vertically Opposite Angles
∴ ∠OAD ≅ ∆OBC    | AAS Rule
∴ OA = OB    | C.P.C.T.
∴ CD bisects AB.

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