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Ask QuestionPosted by Puneet Kumar Palo 5 years, 4 months ago
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Posted by Mukesh Kumar 5 years, 4 months ago
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Amlan Panda 5 years, 4 months ago
Posted by Brahmpal Poonia 5 years, 4 months ago
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Gpulla Array 5 years, 4 months ago
Posted by Bhumi Raj 5 years, 4 months ago
- 3 answers
Gaurav Seth 5 years, 4 months ago
F a l s e
A n s w e r :
5 / 6 = 0 . 8 3 3 3 3 3 3 3 3 .....
so the decimal expansion is non-terminating and recurring.
place a bar over 3.
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Posted by Rohit Kumar 5 years, 4 months ago
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Posted by Samiksha Singaraj 💫 5 years, 4 months ago
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Surjeet Mohanty 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
25a²-35a+12=0
→25a²-20a-15a+12=0
→5a(5a-4)-3(5a-4)=0
→(5a-4)(5a-3)=0
→5a-4=0 or 5a-3=0
→a=4/5 or 3/5
Posted by Sumit Solanki 5 years, 4 months ago
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《Aruba》°°° 《Sayed》❤ 5 years, 4 months ago
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Alka Yadav 5 years, 4 months ago
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Surjeet Mohanty 5 years, 4 months ago
Posted by Devansh Dixit 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
To describe the position of a table lamp placed on the table, let us consider the table lamp as P and the table as a plane. Now choose two perpendicular edge of the table as the axes OX and OY. Measure the perpendicular distance ‘a’ cm of the lamp from OY. Measure the perpendicular distance ‘b’ cm of P (lamp) from OX.
Thus, the position of the table lamp P is described by the ordered pair (a, b).
Posted by Mukesh Kumar 5 years, 4 months ago
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Posted by Bhawna Saxena 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
7 / (5√3-5√2)
= 7 (5√3+5√2)/ (5√3-5√2) * (5√3+5√2) /
=7(5√3+5√2) / (5√3)²-(5√2)²
=35√3+35√2 / 75-50
=35√3+35√2 / 25
Posted by Aarushi Somani 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 3 months ago
- take LCM of 7 and 5
- LCM is 35
- then multiply 2 / 7 with such a number so that we could get 35 that is 2 / 7 *5= 10/35
- multiply 2/5 to get 35 that is 2 / 5 into 7 equals to 14 upon 35
- so we will have to find the numbers between 10 / 35 and 14 / 35
- show the numbers are 11/35 12/35 13/35
- we could get three numbers only but the question is we need five rational numbers
- so we will multiply the LCM with two that is 70 70 also comes in Table of 7 and 5
- then multiply 2/7 with 10 to get 20/70
- multiply 2/5 with 14 to get 28 / 70
- so now we get so many rational numbers between these two these are as follows 21 / 70 22 / 70 23 / 70 24/70 25/70 26 / 70 and so on
Posted by Bhawana Mali 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 3 months ago
1. In Fig. 6.13, lines AB and CD intersect at O. If AOC +BOE = 70° and BOD = 40°, find BOE and reflex COE.

Solution:
From the diagram, we have
(AOC +BOE +COE) and (COE +BOD +BOE) forms a straight line.
So, AOC+BOE +COE = COE +BOD+BOE = 180°
Now, by putting the values of AOC+BOE = 70° and BOD = 40° we get
COE = 110° and
BOE = 30°
For more click:
<a href="https://mycbseguide.com/blog/ncert-solutions-for-class-9-maths-exercise-6-1/" ping="/url?sa=t&source=web&rct=j&url=https://mycbseguide.com/blog/ncert-solutions-for-class-9-maths-exercise-6-1/&ved=2ahUKEwiWrY2woPLsAhWLwjgGHZVtARIQFjAAegQIBBAC" rel="noopener" target="_blank">NCERT Solutions for Class 9 Maths Exercise 6.1 ...</a>
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Posted by Deepankar Sharma 5 years, 4 months ago
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Yogita Ingle 5 years, 4 months ago
2x²-7x+6
= 2x²-4x -3x+6
= 2x ( x - 2) - 3 ( x - 2)
= (2x - 3) (x - 2)
Posted by Sarthak Purohit 5 years, 4 months ago
- 2 answers
Posted by Aadarsh Kumar 5 years, 4 months ago
- 2 answers
Surjeet Mohanty 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
By angle sum property we know that the sum of all the angles of a triangle is 1800
We know that all the sides of a triangle are equal.
i.e all the angles of an equilateral triangle are equal.
Let each angle be x.
x +
x +
x = 1800
3
x = 1800
⇒
x = 600
Hence the answe
Posted by Gowtham Sai Venkat Kavuru 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 3 months ago
WAVY CURVE METHOD
inequalities
If p, q and r are real numbers, then
-
-
-
and
-
-
-
and equality holds for a = 1
-
and equality holds for a = –1
Inequation Involving Exponential Expression:
-
If k > 0, then kx > 0 for all real x.
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If k > 1, then kx > 1, when x > 0
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If 0 < k < 1, then kx < 1, when x > 0 and kx > 1, when x < 0.
How to solve inequalities by wavy curve method
In order to solve the inequalities of the form
where n1, n2, ……. , n k , m1, m2, ……. , mp are real numbers and a1, a2, ……. , ak, b1, b2, ……., bp are any real number such that ai ≠ bj where i = 1, 2, 3, ….k and j = 1, 2, 3, ….p.
Method:
Step - 1→ First arrange all values of x at which either numerator or denominator is becomes zero, that means a1, a2,….., ak, b1, b2, ….bp in increasing order say c1, c2, c3,……. cp + k. Plot them on real line
Step -2 → Value of x at which numerator becomes zero should be marked with dark circles.
Step - 3 → All pints of discontinuities (x at which denominator becomes zero) should be marked on number line with empty circles. Check the value of ƒ(x) for any real number greater than the right most marked number on the number line.
Step - 4 → From right to left draw a wavy curve (beginnings above the number line in case of value of ƒ(x) is positive in step–3 otherwise from below the number line), passing thoroughly all the marked points. So that when passes through a point (exponent whose corresponds factor is odd) intersects the number line, and when passing thoroughly a point (exponent whose corresponds factor is even) the curve doesn’t intersect the real line and remain on the same side of real line.
Step - 5 → The appropriate intervals are chosen in accordance with the sign of inequality (the function ƒ(x) is positive wherever the curve is above the number line, it is negative if the curve is found below the number line). Their union represents the Detail Explanation of inequality
Example : Let
Detail Explanation :
Step - 1 → make on real line all x at which numerator becomes zero with dark circles.
Step - 2 → mark point of discontinuity (value of x at which denominator becomes zero) with empty circles
Step - 3 → Check ƒ(x) for x > 7, ƒ(8) > 0
Exponents of factors of –1, 3, 4 is even, hence wave will not change the direction at these points.
Hence
Posted by Lalruatzeli Cvanlalruatzeli 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 3 months ago
1. State whether the following statements are true or false. Justify your answers.
(i) Every irrational number is a real number.
Solution:
True
Irrational Numbers – A number is said to be irrational, if it cannot be written in the p/q, where p and q are integers and q ≠ 0.
i.e., Irrational numbers = π, e, √3, 5+√2, 6.23146…. , 0.101001001000….
Real numbers – The collection of both rational and irrational numbers are known as real numbers.
i.e., Real numbers = √2, √5, 0.102…
Every irrational number is a real number, however, every real numbers are not irrational numbers.
For more click on the given link:
<a href="https://mycbseguide.com/blog/ncert-solutions-class-9-maths-exercise-1-2/" ping="/url?sa=t&source=web&rct=j&url=https://mycbseguide.com/blog/ncert-solutions-class-9-maths-exercise-1-2/&ved=2ahUKEwjL18TnpPLsAhWswjgGHWopB_YQFjADegQIBBAC" rel="noopener" target="_blank">NCERT Solutions for Class 9 Maths Exercise 1.2 ...</a>
Posted by Rishi Passi 5 years, 4 months ago
- 2 answers
Gaurav Seth 5 years, 4 months ago
HRD Minister Ramesh Nishank announced a major CBSE syllabus reduction for the new academic year 2020-21 on July 7 which was soon followed by an official notification by CBSE on the same.
Considering the loss of classroom teaching time due to the Covid-19 pandemic and lockdown, CBSE reduced the syllabus of classes 9 to 12 with the help of suggestions from NCERT.
Click on the given links:
- <a href="http://cbseacademic.nic.in/web_material/CurriculumMain21/revisedsyllabi/Main-Secondary/REVISEDMathematics_Sec_2020-21.pdf" target="_blank">REVISED - Mathematics</a>
- <a href="http://cbseacademic.nic.in/web_material/CurriculumMain21/revisedsyllabi/Main-Secondary/REVISEDScience_Sec_2020-21.pdf" target="_blank">REVISED - Science</a>
- <a href="http://cbseacademic.nic.in/web_material/CurriculumMain21/revisedsyllabi/Main-Secondary/REVISEDSocial_Science_Sec_2020-21.pdf" target="_blank">REVISED - Social Science</a>
For deleted topics :
- <a href="http://cbseacademic.nic.in/web_material/CurriculumMain21/revisedsyllabi/Deduction/DELETEDComputer_Application_Sec_2020-21.pdf" target="_blank">Deleted - Computer Application</a>
- <a href="http://cbseacademic.nic.in/web_material/CurriculumMain21/revisedsyllabi/Deduction/DELETEDEnglish_Sec_2020-21.pdf" target="_blank">Deleted - English - Language and Literature</a>
- <a href="http://cbseacademic.nic.in/web_material/CurriculumMain21/revisedsyllabi/Deduction/DELETEDHindi_A_Sec_2020-21.pdf" target="_blank">Deleted - Hindi A</a>
- <a href="http://cbseacademic.nic.in/web_material/CurriculumMain21/revisedsyllabi/Deduction/DELETEDHindi_B_Sec_2020-21.pdf" target="_blank">Deleted - Hindi B</a>
- <a href="http://cbseacademic.nic.in/web_material/CurriculumMain21/revisedsyllabi/Deduction/DELETEDHome_Science_Sec_2020-21.pdf" target="_blank">Deleted - Home Science</a>
- <a href="http://cbseacademic.nic.in/web_material/CurriculumMain21/revisedsyllabi/Deduction/DELETEDMathematics_Sec_2020-21.pdf" target="_blank">Deleted - Mathematics</a>
- <a href="http://cbseacademic.nic.in/web_material/CurriculumMain21/revisedsyllabi/Deduction/DELETEDScience_Sec_2020-21.pdf" target="_blank">Deleted - Science</a>
- <a href="http://cbseacademic.nic.in/web_material/CurriculumMain21/revisedsyllabi/Deduction/DELETEDSocial_Science_Sec_2020-21.pdf" target="_blank">Deleted - Social Science</a>
Posted by Aditya Yadav 5 years, 4 months ago
- 1 answers
Kaushal Singh 5 years, 4 months ago

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