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  • 2 answers

Chaitanya Saini 3 years, 11 months ago

Given: A ∆ XYZ in which ∠XYZ = 90°. To prove: XZ2 = XY2 + YZ2 Construction: Draw YO ⊥ XZ Proof: In ∆XOY and ∆XYZ, we have, ∠X = ∠X                             → common ∠XOY = ∠XYZ                     →  each equal to 90°   Therefore, ∆ XOY ~ ∆ XYZ   → by AA-similarity ⇒ XO/XY = XY/XZ                  ⇒ XO × XZ = XY2 ----------------- (i) In ∆YOZ and ∆XYZ, we have,   ∠Z = ∠Z                                     →            common ∠YOZ = ∠XYZ                             →            each equal to 90° Therefore, ∆ YOZ ~ ∆ XYZ           →            by AA-similarity ⇒ OZ/YZ = YZ/XZ                    ⇒ OZ × XZ = YZ2 ----------------- (ii) From (i) and (ii) we get, XO × XZ + OZ × XZ = (XY2 + YZ2) ⇒ (XO + OZ) × XZ = (XY2 + YZ2) ⇒ XZ × XZ = (XY2 + YZ2) ⇒ XZ 2 = (XY2 + YZ2) 

Yogita Ingle 3 years, 11 months ago

Given: A ∆ XYZ in which ∠XYZ = 90°.

To prove: XZ2 = XY2 + YZ2

Construction: Draw YO ⊥ XZ

Proof: In ∆XOY and ∆XYZ, we have,

∠X = ∠X                             → common

∠XOY = ∠XYZ                     →  each equal to 90°

 

Therefore, ∆ XOY ~ ∆ XYZ   → by AA-similarity

⇒ XO/XY = XY/XZ               

 

⇒ XO × XZ = XY2 ----------------- (i)

In ∆YOZ and ∆XYZ, we have,

 

∠Z = ∠Z                                     →            common

∠YOZ = ∠XYZ                             →            each equal to 90°

Therefore, ∆ YOZ ~ ∆ XYZ           →            by AA-similarity

⇒ OZ/YZ = YZ/XZ                 

 

⇒ OZ × XZ = YZ2 ----------------- (ii)

From (i) and (ii) we get,

XO × XZ + OZ × XZ = (XY2 + YZ2)

⇒ (XO + OZ) × XZ = (XY2 + YZ2)

⇒ XZ × XZ = (XY2 + YZ2)

⇒ XZ 2 = (XY2 + YZ2)

  • 1 answers

Gaurav Seth 3 years, 11 months ago

1. Practice concentration: Maths and Physics terms and formulas require intense focus and deep concentration to get absorbed into the mind. So you need to work on your concentration level to get all complicated or lengthy formulas stick to your mind.

2. Relax your brain: Maths and Physics problems can never be learned under stress as a stressed brain loses its work potential and finds it difficult to work on complex things. So you need to first relax your mind. By doing this, you will be able to focus more on your task.

3. Practice as much as you can: This may sound like an obvious point, but the more you practice using the formulas you need to know, the more likely you are to remember the same. List down all important formulas on a sheet and whenever you are free, glance at them once. After all, repetition leads to memorization.

4. Minimize your reference checks: Many students think that once they take a glance at a formula, it is in their mind, but the next morning when they try to recall the same, they are shocked to realize that the formula leaked out during the night. To avoid such situation, try to practice solving a problem with the formula without looking it up.

5. Understand the basic concept of the formula: Try to clear your basic concepts before moving ahead with the formulas. This will help you understand the sense of the formula.

For example: In the formula, a = F / m, where acceleration (a) is expressed in terms of Force (F) and mass (m), F is on the top of the fraction. This makes sense, since if you exert more force on an object, it will speed up more quickly. Whereas, mass is on the bottom of the fraction, which means the speed of the object will decrease, since more mass means more inertia thus making the object more difficult to accelerate.

6. Keep away with all distractions: Not only the gadgets you use need to be talked under this heading, but your physical desires like hunger, thirst, drowsiness, etc., also need to be kept away.

7. Learn the derivation of every formula. Derivation of a formula will help you familiarise with the roots and concepts of that formula which can help you retain the same for long time in your brain. Moreover, when you derive a formula, you come across a number of other formulas. That way you can memorize just the bare minimum number of formulae that you need to derive the rest from.

8. Use memorising tricks: Try to create a story that involves everything you are trying to learn. The sequence of a story can help you to remember things in a particular order.

For example: To learn the trigonometric ratios;  P/H = sin, B/H = cos, P/B = tanyou can use a phrase “pandit badri prasad har har bole sona chandi tole” and then set the words like: 

                                  

Work out on more of such phrases that can help you recall the long-complicated formulas.

Thus all the tips and tricks given above if followed wisely, will definitely help you master Maths and Physics, getting you an awesome score in your board exams.

  • 2 answers

Vaibhav Panday 3 years, 10 months ago

Thanks

Yogita Ingle 3 years, 11 months ago

Find the value of the polynomial 5x – 4x2 + 3 at
(i) x = 0           (ii) x = –1        (iii) x = 2

Solution: (i)x = 0
5x – 4x2 + 3
Plug x = 0 we get
=>5(0) – 4(0)2 + 3
=>0 -0 + 3
=> 3

(ii) x = –1       
Plug x  = - 1 we get
=>5x – 4x2 + 3
=>5(-1) – 4(-1)2 + 3
=> -5 – 4 +3
=>-6

(iii) x = 2
Plug x = 2 we get
=>5(2) – 4(2)2 + 3
=>10 – 16 + 3
=> -3

  • 1 answers

? ? 3 years, 11 months ago

Where is the figure
  • 2 answers

Aman Kumar Kumar 3 years, 11 months ago

-5(√3+√5)

Shreyansh Kanare 3 years, 11 months ago

Ans do na
  • 1 answers

Yuvraj Bhikane 3 years, 11 months ago

7yuu74
  • 1 answers

Aman Kumar Kumar 3 years, 11 months ago

3
  • 1 answers

Aman Kumar Kumar 3 years, 11 months ago

8 √2
  • 1 answers

Yogita Ingle 3 years, 11 months ago

(a+b+c)= a2+b2+c2+2ab+2bc+2ca

⇒(2x−y+z)2=(2x)2+(−y)2+(z)2+2(2x×−y)+2(−y×z)+2(z×2x)

=4x2 + y2+z2−4xy−2yz+4xz

  • 2 answers

Chaitanya Saini 3 years, 11 months ago

CSA:- 88cm² Height:- 7cm 2πrh=88 2×22/7×r×7=88 2×22×r=88 r=88/22×2 r= 2cm TSA:- 2πr(r+h) 2×22/7×2(2+7) 2×22/7×2×9 792/7= 113.1cm²

Pratibha Kushwah 3 years, 11 months ago

If csa of cylinder is 88 cm square 2πrh= 88 h = 7cm (given) 2×22/7×r×7 = 88 r= 2 cm Total surface area of cylinder is 2πrh+ 2πrsquare Therefore , total surface area of cylinder is 88 + 2πrsquare 2×22/7×2×2 = 88+ 25.14 Hence , area will be 113.14cm square
  • 1 answers

Yogita Ingle 3 years, 11 months ago

Total surface area of a cube = 726 cm2

6 × (side)= 726 

(side)= 121

side = 11 cm

Hence, the length of the edge of cube is 11 cm. 

  • 2 answers

Chaitanya Saini 3 years, 11 months ago

Let length:- 4x Breadth:- 2x Height:- 1x TSA of cuboid:- 1372cm² TSA of cuboid:- 2(lb+bh+hl)= 1372cm² 2(4x × 2x + 2x ×1x + 1x × 4x)= 1372 2(8x²+2x²+4x²)=1372 2(14x²)=1372 14x²= 1372/2 14x²=686 x²= 686/14 = 49 x=√49 x=7 Value of length:- 4x= 4(7)=28cm Value of breadth:- 2x= 2(7)=14cm Value of height:- 1x=1(7)=7cm I hope it will help you ...

Yogita Ingle 3 years, 11 months ago

Let the length be 4x
Let the breadth be 2x
Let the height be x

Surface area=2(lb+bh+hl)
=2(8x²+2x²+4x²)
=28x²=1372
so x²=49
and x=7

So length=4x=28cm
breadth=2x=14cm
&. height=x=7cm

  • 2 answers

Hani Soni 3 years, 9 months ago

Matlab kuchvi

Hani Soni 3 years, 11 months ago

Kuchh ni
  • 1 answers

Yashas Kumar 3 years, 11 months ago

233392/9900
  • 0 answers
  • 1 answers

Gaurav Seth 3 years, 11 months ago

<div class="ateTopicHead" style="margin:0px; padding:0px; width:853px">

 

Prove that if the diagonals of a quadrilateral bisect each other, then it is a parallelogram.

</div> <div class="qsnDetails" style="margin:0px; padding:0px">

 

</div> <div class="expertBlock" style="margin:0px; padding:0px">

 

OA = OC and OB = OD [Given]

AOB = DOC [vertically opp. angles]

 [SAS congruence]

Therefore ABO = CDO (cpct)

From this, we get AB||CD ...(i)

Similarly BC||AD ...(ii)

 From (i) and (ii) ABCD is a ||gm.

<div class="qsnDetails" style="margin:0px; padding:0px; text-align:start; -webkit-text-stroke-width:0px"> </div> </div>
  • 1 answers

Aditya Kumar Saha 3 years, 11 months ago

What
  • 2 answers

Aiswarya Raanee .K 3 years, 11 months ago

Hi ahan huda

Ahan Huda 3 years, 11 months ago

Hii
  • 1 answers

Yashas Kumar 3 years, 11 months ago

-4√5
  • 0 answers
  • 1 answers

Priyanshu Bhardwaj 3 years, 11 months ago

0.048
  • 2 answers

Arpit Bareth 3 years, 11 months ago

⇒l=30,b=25,h=25 (i) Total S.A of green house =2(lb+bh+lb) =2(30×25+30×25+25×25) =4250 cm2 (ii) For 12 edges: Total length =4l+4b+4h =4(30+25+25) =320 cm

Yogita Ingle 3 years, 11 months ago

Given:

⇒l=30,b=25,h=25

(i) Total S.A of green house 

=2(lb+bh+lb)
=2(30×25+30×25+25×25)
=4250 cm2

(ii) For 12 edges: Total length 

=4l+4b+4h
=4(30+25+25)
=320 cm

  • 5 answers

Krishna Pradhan 3 years, 11 months ago

It's irrational number

Aiswarya Raanee .K 3 years, 11 months ago

It's a irrational number

Sahil Nara 3 years, 11 months ago

It is irrational number √2+√2 =2√2

Somya Jaiswal 3 years, 11 months ago

Kskakakkwow

Kshitiz Jain 3 years, 11 months ago

It is irrational number √2+√2 =2√2

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