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  • 3 answers

Rohit Rathore 5 years, 2 months ago

The whole number starts from 0 (zero) to infinite.for eg.0,1,2,3,4,5 ...................and so on.

Yogita Ingle 5 years, 2 months ago

The numbers 1,2, 3, are called natural numbers or counting numbers. 
Let us add one more number i.e., zero (0), to the collection of natural numbers. Now the numbers are 0,1,2, … These numbers are called whole numbers
We can say that whole nos. consist of zero and the natural numbers. Therefore, except zero all the whole nos. are natural numbers.
Facts of Whole numbers
1) The smallest natural number is 1.
2) The number 0 is the first and the smallest whole nos.
3) There are infinitely many or uncountable number of whole-numbers

Pavan I 5 years, 2 months ago

????
  • 2 answers

Pavan I 5 years, 2 months ago

??????????????

Bhagwati Bishnoi 5 years, 2 months ago

9th ki book ke important question
  • 2 answers

Gaurav Seth 5 years, 2 months ago

A n s w e r

Apply remainder theorem
=> x - 1 =0
=> x = 1
Replace x by 1 we get
=> x+ 3x2 + 3x + 1
=>(1)3 + 3(1)2 + 3(1) + 1
=> 1 + 3 + 3 + 1
=> 8
Remainder is 8

Daksh Maru 5 years, 2 months ago

14
  • 4 answers

Harish Ss 2 years, 1 month ago

To say the diffucult chapter is , Circles . You need to concentrate more in those theorems . If you are okay with theorems, You will ace 9th maths

Rohit Rathore 5 years, 2 months ago

The most difficult chapter in mathematics in class 9th is euclids'geometry(chapter5) but in new syllabus resumed by cbse this chapter is removed.So I don't take stress about this chapter .

Piyush Kumar 5 years, 2 months ago

if u think this chapter is difficult then u never solve it.

Vansh Kumar 5 years, 2 months ago

13
  • 3 answers

Sahil Chopade 5 years, 2 months ago

In the given figure, the measure of ABC is :

Daksh Maru 5 years, 2 months ago

No one

Vansh Kumar 5 years, 2 months ago

13
  • 1 answers

Gaurav Seth 5 years, 2 months ago

 1. Give five examples of data that you can collect from your day-to-day life.

Solution:

Five examples from day-to-day life:

  1. Number of students in our class.
  2. Number of fans in our school.
  3. Electricity bills of our house for last two years.
  4. Election results obtained from television or newspapers.
  5. Literacy rate figures obtained from Educational Survey

2. Classify the data in Q.1 above as primary or secondary data.

Solution:

Primary data: when the information was collected by the investigator herself or himself with a definite objective in her or his mind, the data obtained is called primary data.

Primary data; (i), (ii) and (iii)

Secondary data; when the information was gathered from a source which already had the information stored, the data obtained is called secondary data

Secondary data; (iv) and (v)

  • 2 answers

Pavan I 5 years, 2 months ago

69

Black Yadav 5 years, 2 months ago

69
  • 1 answers

Yogita Ingle 5 years, 2 months ago

In Maths, integers are the numbers which can be positive, negative or zero, but cannot be a fraction. 

The examples of integers are, 1, 2, 5,8, -9, -12, etc. The symbol of integers is “Z“.

  • 0 answers
  • 1 answers

Gaurav Seth 5 years, 2 months ago

. Construct an angle of 90° at the initial point of a given ray and justify the construction.

Construction Procedure:

To construct an angle 90°, follow the given steps:

1. Draw a ray OA

2. Take O as a centre with any radius, draw an arc DCB is that cuts OA at B.

3. With B as a centre with the same radius, mark a point C on the arc DCB.

4. With C as a centre and the same radius, mark a point D on the arc DCB.

5. Take C and D as centre, draw two arcs which intersect each other with the same radius at P.

6. Finally, the ray OP is joined which makes an angle 90° with OP is formed.

Justification

To prove ∠POA = 90°

In order to prove this, draw a dotted line from the point O to C and O to D and the angles formed are:

From the construction, it is observed that

OB = BC = OC

Therefore, OBC is an equilateral triangle

So that, ∠BOC = 60°.

Similarly,

OD = DC = OC

Therefore, DOC is an equilateral triangle

So that, ∠DOC = 60°.

From SSS triangle congruence rule

△OBC ≅ OCD

So, ∠BOC = ∠DOC [By C.P.C.T]

Therefore, ∠COP = ½ ∠DOC = ½ (60°).

∠COP = 30°

To find the ∠POA = 90°:

∠POA = ∠BOC+∠COP

∠POA = 60°+30°

∠POA = 90°

Hence, justified.

For more click on the given link:

<a href="https://mycbseguide.com/blog/ncert-solutions-for-class-9-maths-exercise-11-1/" ping="/url?sa=t&source=web&rct=j&url=https://mycbseguide.com/blog/ncert-solutions-for-class-9-maths-exercise-11-1/&ved=2ahUKEwjcspLywbHtAhU54zgGHafxBXwQFjALegQICxAC" rel="noopener" target="_blank">NCERT Solutions for Class 9 Maths Exercise 11.1 ...</a>

  • 5 answers

Kripa Daga 5 years, 2 months ago

Given :x=8 x²+x-5 (8)² + 8-5 64+8-5 72-5 67

Bhoomika Garg 5 years, 2 months ago

67

Yogita Ingle 5 years, 2 months ago

Sorry by-mistake added x = 6 in place of x= 8.

Shweta Singh 5 years, 2 months ago

Let p(x)=x^2 +x-5 Putting x=8 in p(x) = (8)^2+8-5 = 64+8-5 = 64+3 = 67

Yogita Ingle 5 years, 2 months ago

Put x = 8

x²+x-5

= (6)2 + 6 - 5

= 36 + 1

= 37

 

 

  • 4 answers

Srishty Negi 5 years, 2 months ago

All angles of equilateral triangle is equal x+x+ x= 180 3x = 180 x= 180/3= 60

Ankur Pal 5 years, 2 months ago

Not sufficient

Khushi Vats 5 years, 2 months ago

By angle sum property we know that the sum of all the angles of a triangle is 180o We know that all the sides of a triangle are equal. i.e all the angles of an equilateral triangle are equal. Let each angle be x. x+x+x=180 60o 3x = 180 ⇒x = 60 Hence the answer.

Soham Basu 5 years, 2 months ago

By angle sum property we know that the sum of all the angles of a triangle is 180o We know that all the sides of a triangle are equal. i.e all the angles of an equilateral triangle are equal. Let each angle be x. x+x+x=180 60o 3x = 180 ⇒x = 60 Hence the answer.
  • 1 answers

Kripa Daga 5 years, 2 months ago

??????:- ???=2(bh+hl) ???=2(lb+bh+hl) ????:- ???=4a² ???=6a² ????:- ???=πrl ???=πr(r+l) ????????:- ???=2πrh ???=2πr(r+h) ??????????:- ???=2πr² ???=3πr²
  • 1 answers

Black Yadav 5 years, 2 months ago

963846208815
  • 5 answers

Black Yadav 5 years, 2 months ago

Rhombus

Kripa Daga 5 years, 2 months ago

4) rectangle

Lakshya Maharia 5 years, 2 months ago

Rectangle

Akash Varshney 5 years, 2 months ago

Really??!!

H G 5 years, 2 months ago

Rhombus
  • 1 answers

Yogita Ingle 5 years, 2 months ago

Median =120 and mean = 124 

mode = 3median - 2mean

mode = 3(120) - 2(124)

mode = 360 - 248 = 112

  • 1 answers

Yogita Ingle 5 years, 2 months ago

If two lines intersect each other, then the vertically opposite angles are equal.

Proof :

In the statement above, it is given that ‘two lines intersect each other’. So, let AB and CD be two lines intersecting at O as shown in Fig. 6.8. They lead to two pairs of vertically opposite angles, namely,

(i) ∠ AOC and ∠ BOD (ii) ∠ AOD and ∠ BOC.

We need to prove that ∠ AOC = ∠ BOD and ∠ AOD = ∠ BOC.

Now, ray OA stands on line CD.

Therefore, ∠ AOC + ∠ AOD = 180°  (Linear pair axiom) ………..(1)

Can we write ∠ AOD + ∠ BOD = 180°?  (Linear pair axiom)……………(2)

From (1) and (2), we can write

∠ AOC + ∠ AOD = ∠ AOD + ∠ BOD

This implies that ∠ AOC = ∠ BOD

Similarly, it can be proved that ∠AOD = ∠BOC

  • 2 answers

Kripa Daga 5 years, 2 months ago

1/(√7-√5) 1(√7+√5) /(√7-√5) (√7+√5) (√7+√5) /(√7)²-(√5) ² (√7+√5) /7-5 (√7+√5) /2

Vinod Kumar 5 years, 2 months ago

√7+√5/2
  • 1 answers

Tanmay Verma 5 years, 2 months ago

Question to likh be
  • 2 answers

Sanjay Kumar 5 years, 2 months ago

(20,4), (15,2)

Sarthak Gore 5 years, 2 months ago

2x=20+5 2x=25 X=25/2 X=12.5
  • 4 answers

Rohit Rathore 5 years, 2 months ago

1

Sanjay Kumar 5 years, 2 months ago

1

Kripa Daga 5 years, 2 months ago

1 is coefficient of x²

Abhishek Shukla 5 years, 2 months ago

1
  • 3 answers

Sanjay Kumar 5 years, 2 months ago

Degree is 3

Abhishek Shukla 5 years, 2 months ago

3

Yash Dhiman 5 years, 2 months ago

1 degree
  • 2 answers

Yogita Ingle 5 years, 2 months ago

Here, PQ = SR = 12cm 

Let PS = x and PS = QR 

∴ x + 12 + x +12 = Perimeter 

2x + 24 = 40

2x = 16

x = 8 

Hence, length of each side of the parallelogram is 12cm , 8cm , 12cm and 8cm.

Gaurav Seth 5 years, 2 months ago

Here, PQ = SR = 12cm 

Let PS = x and PS = QR 

∴ x + 12 + x +12 = Perimeter 

2x + 24 = 40

2x = 16

x = 8 

Hence, length of each side of the parallelogram is 12cm , 8cm , 12cm and 8cm.

  • 2 answers

Queen 14 5 years, 2 months ago

Let the smallest angle be x One angle = 2x - 30° ∴ x + 2x - 30° = 180° ⇒ 3x = 210° ⇒ x = 70° ∴ 2x - 30° = 110° ∴ Angles are 70°, 110° , 70°,

Yogita Ingle 5 years, 2 months ago

Let the smallest angle be x

One angle = 2x - 30° 

∴ x + 2x - 30° = 180° 

 ⇒ 3x  = 210° 

 ⇒ x = 70° 

∴ 2x - 30° = 110° 

∴ Angles are 70°, 110° ,  70°, 110° .

  • 3 answers

Queen 14 5 years, 2 months ago

73/99

Yogita Ingle 5 years, 2 months ago

0.73 bar =73/99 

Soham Patel 5 years, 2 months ago

Yes
  • 1 answers

Yogita Ingle 5 years, 2 months ago

In ∆ABC , angle B=90° and D is a point on hypotenuse AC such that angle DBC

= angle DCB.

In,∆ABC. let angle ACB or DCB = x° , then angle BAC or BAD = 90°-x………..(1)

In. ∆ DBC angle DBC= angle DCB=x°………..(given)

But angle ABD+angle DBC =90°

or. angle ABD. = 90°-x°……………(2)

from eqn. (1) and (2)

angle BAD =angle ABD…….(In ∆ DAB opposite angles are equal ,then opposite

sides are also equal.)

Thus , side BD = side AD. Proved.

  • 5 answers

Sanjay Kumar 5 years, 2 months ago

Meningitis, brain Cancer

Pankaj Gautam 5 years, 2 months ago

Brain tumours, brain abscess

N T 5 years, 2 months ago

Brain हथौड़ा ??????????

Tanushri Deshpande 5 years, 2 months ago

Thanks

Yogita Ingle 5 years, 2 months ago

Brain tumours: Abnormal growth of tissue within the brain is termed as the brain tumour.
Neurodegenerative Diseases: A neurodegenerative disease is also called as the Degenerative Nerve Diseases.
Meningitis, Encephalitis, Seizures, Trauma, Hydrocephalus, Brain abscess, Tumors are the list of most common brain diseases.

  • 2 answers

Cbz Hero 5 years, 2 months ago

Thanks

Gaurav Seth 5 years, 2 months ago

Step-by-step explanation:

in triangle BCD,

semiperimeter (s) = BC + CD + BD/2

s = 60 + 30 + 70 /2

s = 160/2

s = 80

 

​a = root[80 x (80-60) (80-30) (80 - 70)]

a = root[80 x 20 x 50 x 10]

a = root[ 10 x 4 x 2 x 2 x 10 x 5 x 10 x 10]

a = 10 x 4 x 10 root(5)

a = 400xroot(5)

a = 894.4 (approx)

 

In triangle ABD,

semiperimeter (s) = AB + BD + DA/2

s = 50 + 70 + 90/2

s = 210/2

s = 105

 

​a = root[105 x (105- 50) (105-90) (105 - 70)]

a = root[105 x 55 x 15 x 35]

a = root[ 5 x 7 x 3 x 5 x 11 x 5 x 3 x 7 x 5]

a = 25 x 7 x 3 root(11)

a = 525 * root(11)

a = 1741.2 (approx)

Total area = ​894.4 + ​1741.2

= 2635.6 cm2(approx

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