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  • 1 answers

Manshu Singh 7 months, 2 weeks ago

We have, Area of a triangle by heron's formula= √s(s-a)(s-b) (s-c) Now we know, s = perimeter of triangle/2 So, s=13+13+20/2=23 Let, put the value of s in formula =√23(23-13) (23-13) (23-20) =√23*10*10*3 =√23*2*5*2*5*3 Area = 10√69 cm square
  • 1 answers

Anshika Choudhary 7 months, 2 weeks ago

We have given interval is 100 - 120. Here upper limit is 120 and lower limit is 100. Hence, answer is 110.
  • 1 answers

Anshika Choudhary 7 months, 2 weeks ago

a = (√5 + 2)/(√5 – 2) b = (√5 – 2)/( √5 + 2) Concept: First rationalize the values of ‘a’ and ‘b’ and then proceed. Formula used: (a + b)2 = a2 + b2 + 2ab (a + b)(a – b) = a2 – b2 Calculation: ∵ a = (√5 + 2)/(√5 – 2) ⇒ a = [(√5 + 2)( (√5 + 2)]/[(√5 – 2)(√5 + 2)] ⇒ a = [(√5 + 2)2]/[(√5)2 – (2)2] ⇒ a = [5 + 4 + 4√5]/(5 – 4) ⇒ a = (9 + 4√5) Similarly; b = (√5 – 2)/( √5 + 2) ⇒ b = [(√5 – 2)(√5 - 2)]/[(√5 + 2)(√5 – 2)] ⇒ b = [(√5 – 2)2]/[(√5)2 – (2)2] ⇒ b = [5 + 4 – 4√5]/(5 – 4) ⇒ b = (9 – 4√5) Now, a2 + b2 + ab = (a + b)2 – ab ⇒ (9 + 4√5 + 9 – 4√5)2 – [(9 + 4√5)( 9 – 4√5)] ⇒ (18)2 – [(9)2 – (4√5)2] ⇒ 324 – (81 – 80) ⇒ 324 – 1 ⇒ 323 ∴ The value of the given expression is 323.
  • 3 answers

Anurag Singh 7 months, 2 weeks ago

x+y=8 xy=15, using : (x+y)^2 = x^2 + y^2 +2(x)(y) , (8)^2 = x^2 + y^2 + 2(15) , 64 = x^2 + y^2 + 30, 64 - 30 = x^2 + y^2 , 34 = x^2 + y^2

Anshika Choudhary 7 months, 2 weeks ago

x+y=8 xy=15 using : (x+y)^2 = x^2 + y^2 +2(x)(y) (8)^2 = x^2 + y^2 + 2(15) 64 = x^2 + y^2 + 30 64 - 30 = x^2 + y^2 34 = x^2 + y^2

Anurag Singh 7 months, 2 weeks ago

x+y=8 xy=15 using : (x+y)^2 = x^2 + y^2 +2(x)(y) (8)^2 = x^2 + y^2 + 2(15) 64 = x^2 + y^2 + 30 64 - 30 = x^2 + y^2 34 = x^2 + y^2
  • 1 answers

Abhijit Garai 7 months, 2 weeks ago

Let x = 0.999 10x = 9.999 10x - x =9.999 -0.999 9x = 9 x = 9/9 x = 1
  • 1 answers

Jasmeet Kaur 7 months, 2 weeks ago

( √ 5 + √ 2 ) 2 = ( √ 5 ) 2 + ( √ 2 ) 2 + 2 × √ 5 × √ 2 [ ∵ ( a + b ) 2 = a 2 + b 2 + 2 a b ] = 5 + 2 + 2 × √ 5 × √ 2 = 7 + 2 √ 10
  • 3 answers

Binod Binod 7 months, 2 weeks ago

In jee 2024

Binod Binod 7 months, 2 weeks ago

Have you cracked because I have received AIR -977

Ashis Shome 7 months, 2 weeks ago

P(1)=0 P(-1)=6 P(2)=0 P1+p-1+p2=6
  • 1 answers

Abhijit Garai 7 months, 1 week ago

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  • 1 answers

Anshika Choudhary 7 months, 2 weeks ago

Hence, the cost of painting the triangular board at the rate of 9 paise per cm2 is Rs 2.16​​​​​​​.
  • 1 answers

Anshika Choudhary 7 months, 2 weeks ago

In a square A B C D , P , Q , R and S are the mid-points of A B , B C , C D and D A respectively. ⇒ A B = B C = C D = A D [ Sides of square are equal ] In △ A D C , S R ∥ A C and S R = 1 2 A C [ By mid-point theorem ] ---- ( 1 ) In △ A B C , P Q ∥ A C and P Q = 1 2 A C [ By mid-point theorem ] ---- ( 2 ) From equation ( 1 ) and ( 2 ), S R ∥ P Q and S R = P Q = 1 2 A C ---- ( 3 ) Similarly, S P ∥ B D and B D ∥ R Q ∴ S P ∥ R Q and S P = 1 2 B D and R Q = 1 2 B D ∴ S P = R Q = 1 2 B D Since, diagonals of a square bisect each other at right angle. ∴ A C = B D ⇒ S P = R Q = 1 2 A C ----- ( 4 ) From ( 3 ) and ( 4 ) S R = P Q = S P = R Q We know that the diagonals of a square bisect each other at right angles. ∠ E O F = 90 o . Now, R Q ∥ D B R E ∥ F O Also, S R ∥ A C ⇒ F R ∥ O E ∴ O E R F is a parallelogram. So, ∠ F R E = ∠ E O F = 90 o (Opposite angles are equal) Thus, P Q R S is a parallelogram with ∠ R = 90 o and S R = P Q = S P = R Q ∴ P Q R S is a square.
  • 1 answers

Yuvraj Singh 7 months, 3 weeks ago

AB=BC=CD=DA
  • 1 answers

Anurag Saikia 7 months, 3 weeks ago

A number which can be expressed in a simple fractional form of p/q where q≠0 is called a rational number. Eg: 1/10, 827/20838 etc.
  • 1 answers

Chandan Suri 7 months, 3 weeks ago

(i) equation of x-axis is y=0. (ii) equation of y-axis is x=0.
  • 5 answers

Account Deleted 7 months, 3 weeks ago

10

Rehan Khan 7 months, 3 weeks ago

The symbol of rational number

Kyna Gupta 7 months, 3 weeks ago

3x−5y−7=0 3(2k−1)−5(k)−7=0 6k−3−5k−7=0 k−10=0 k=10 Hope this helps you 😊

Kyna Gupta 7 months, 3 weeks ago

3x−5y−7=0 3(2k−1)−5(k)−7=0 6k−3−5k−7=0 k−10=0 k=10 Hope this helps you 😊

Hem Raj 7 months, 3 weeks ago

10
  • 2 answers

Aliya Parween 7 months, 3 weeks ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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Atul Kumar 7 months, 3 weeks ago

KN and LM are equal perpendicular to a line segment AB
  • 1 answers

Tanvi Bhatt 7 months, 3 weeks ago

Let the angles be x and 3x. We know that sum of adjacent angles of parallelogram is 180° x+3x=180 x= 45° 3x= 135° .:. angle A=angle C=45 Angle B= angle D= 135
  • 1 answers

Account Deleted 7 months, 3 weeks ago

Y=115°; X= 115°; Z= 25° Step-by-step explanation: Y= 180°-65°=115° (Cointerior angles) X=Y= 115° (Corresponding Angles) Z=90°+z+65°=180° = 155°+z=180° Z= 25°
  • 1 answers

Kawaii _ 7 months, 3 weeks ago

1.(0,-3) 2.(1,4) 3.(-2,-3)
  • 5 answers

Professional Gamer 7 months, 3 weeks ago

X axis

Dipa Sinha 7 months, 3 weeks ago

x axis

Arnav Shahi 7 months, 3 weeks ago

X axis

Naitik Gujrati 7 months, 3 weeks ago

Positive side of x-axis

Akshit Gautam 7 months, 3 weeks ago

X axis
  • 2 answers

Anubhav Dubey 7 months, 1 week ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
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Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Kawaii _ 7 months, 3 weeks ago

15.2 cm^2
  • 2 answers

Dipa Sinha 7 months, 3 weeks ago

Sorry mod point theorm

Dipa Sinha 7 months, 3 weeks ago

Converse of mod point theorm
  • 1 answers

Saksham Jain 7 months, 3 weeks ago

All are 75
  • 0 answers
  • 2 answers

Harshal Patil 7 months, 4 weeks ago

(3x+7y)³ = (3x)³+(7y)³+3 × 3x × 7y(3x+7y) =27x³+343y³+63xy(3x+7y) =27x³+343y³+189x²+441xy². Ans.

Ritika Burnwal 7 months, 4 weeks ago

(3x+7y)³ = (3x)³+(7y)³+3 × 3x × 7y(3x+7y) =27x³+343y³+63xy(3x+7y) =27x³+343y³+189x²+441xy². Ans.
  • 2 answers

Ritika Burnwal 7 months, 4 weeks ago

Here given, x= -2 and y=5 So, 2x+my=11 Therefore, 2(-2)+m(5)=11 -4+5m=11 5m=11+4 m=15/5 m=3

Aditya Singh 7 months, 4 weeks ago

3

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