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Ask QuestionPosted by Nano Fibres 3 years, 3 months ago
- 4 answers
Posted by Prachi Patil 3 years, 3 months ago
- 1 answers
Sia ? 3 years, 3 months ago
The remainder when p(x) is divided by (x−a) is p(a)
Geven that,
p(x) = x4 − 3x2 + 2x + 5
Divisor = (x − 1)
So, Remainder = p(1)
= (1)4 − 3(1)2 + 2(1) + 5
= 1 − 3 + 2 + 5
= 5
Posted by Priyanshi Dubey 3 years, 3 months ago
- 1 answers
Preeti Dabral 3 years, 3 months ago
x³ - 2x² - x + 2
=> x²(x - 2) - 1(x - 2)
=> (x - 2)(x² - 1)
=> (x - 2){(x)² - (1)²}
=> (x - 2)(x - 1)(x + 1)
Posted by Shuvasmita Nayak 3 years, 3 months ago
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Posted by Óp Łùciferyt 3 years, 3 months ago
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Anshika Sharma 3 years, 3 months ago
Posted by Tanu Tomar 3 years, 3 months ago
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Sia ? 3 years, 3 months ago
2x+y=k
x=3, y=5
Put these values in equation
2(3)+5=k
6+5=k
K=11
Posted by Tanu Tomar 3 years, 3 months ago
- 1 answers
Sia ? 3 years, 3 months ago
2x+y=k
x=3, y=5
Put these values in equation
2(3)+5=k
6+5=k
K=11
Posted by Sanket .........✨ 3 years, 3 months ago
- 5 answers
Sanket .........✨ 3 years, 3 months ago
Posted by Rakesh Singh Rakesh Singh 3 years, 3 months ago
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Posted by Utkarash Babar 3 years, 3 months ago
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Preeti Dabral 3 years, 3 months ago
No. Square roots of all positive integers are not irrational.
Example 4, 9, 16, etc. are positive integers and their square roots are 2, 9 and 4 which are rational numbers.
Posted by Jasmine Kaur 3 years, 3 months ago
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Diksha Laniya 3 years, 3 months ago
Saɴᴋᴇᴛ ???? 3 years, 3 months ago
Posted by Diksha Laniya 3 years, 3 months ago
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Saɴᴋᴇᴛ ???? 3 years, 3 months ago
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