CBSE > Class 09 > Mathematics | CBSE Board | Homework Help

•First Let x be 0 5x-4y+8=0 5(0)-4(0)+8=0 0-0+8=0 = 8=0. • 2nd Let x be 1 5x-4y+8=0 5(1)-4(1)+8=0 5-4+8=0 1+8=0 = 9=0. • 3rd Let x be -1 5x-4y+8=0 5(-1)-4(-1)+8=0 -5+4+8=0 -1+8=0 = -7=0. I HOPE IT'LL HELP YOU A LOT ??

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From a point in the interior of an equilateral triangle, perpendiculars are drawn on the three sides. The lengths of the perpendiculars are 14 cm, 10 cm and 6 cm. Find the area of the triangle.

Posted by Hacker Zone 3 years, 2 months ago

CBSE > Class 09 > Mathematics

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पाठ 1

Posted by Laduram Bishnoi 3 years, 2 months ago

CBSE > Class 09 > Mathematics

2 answers

Prince Bhagat 3 years, 2 months ago

पाठ 2

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Pra Jit 3 years, 2 months ago

नोट्स ?

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To obtain the square root of any given positive real number (say 6.5) through an activity, involving paper folding and geometrical construction.

Posted by Rishu Kumar 3 years, 2 months ago

CBSE > Class 09 > Mathematics

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Write the rationalising factors of 4/3√5

Posted by Mehakpreet Kaur 3 years, 2 months ago

CBSE > Class 09 > Mathematics

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Chaithanya Kumar 8Th Class 3 years, 1 month ago

4√45/45

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In an equilateral triangle. S=60cm find each side of triangle?

Posted by Mehakpreet Kaur 3 years, 2 months ago

CBSE > Class 09 > Mathematics

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Chaithanya Kumar 8Th Class 3 years, 1 month ago

S=a+b+c/2 60=3a/2 3a=120 a=40cm So the each side of triangle is 40cm

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The images of a triangular board are 6cm 8cm and 10cm the cost of a painting it at the rate of 9paise cm² square is

Posted by Richa Kriplani 3 years, 2 months ago

CBSE > Class 09 > Mathematics

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Chaithanya Kumar 8Th Class 3 years, 1 month ago

Semi perimeter = 6+8+10/2 = 24/2 = 12cm. Area of triangle = √12(12-6)(12-8)(12-10) = √576 = 24 cm2 Cost = 0.09×24 = 2.16 rupees

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π is rational or irrational

Posted by Ayush Tomar 3 years, 2 months ago

CBSE > Class 09 > Mathematics

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Pra Jit 3 years, 2 months ago

It is a rational because the value of π = 22/7 .

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If 2 parallel lines are intersected by a transversal, prove that the bisectors of 2 pairs of interior angles enclose a rectangle.

Posted by Aheli Basu 3 years, 2 months ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 3 years, 2 months ago

AB and CD are two parallel lines intersected by a transversal L. X and Y are the points of intersection of L with AB and CD respectively. XP, XQ, YP and YQ are the angle bisectors of ∠ AXY, ∠ BXY, ∠ CYX and ∠ DYX.
AB || CD and L is transversal.
∴ ∠ AXY = ∠ DYX (Pair of alternate angles)
⇒ 1/2 ∠ AXY = 1/2 ∠ DYX
⇒ ∠ 1 = ∠ 4 (∠ 1 = 1/2 ∠ AXY and ∠ 4 = 1/2 ∠ DYX)
⇒ PX/YQ (If a transversal intersects two lines in such a way that a pair of alternate interior angles are equal, then the two lines are parallel)...(1)
Also ∠ BXY = ∠ CYX (Pair of alternate angles)
⇒ 1/2 ∠ BXY = 1/2 ∠ CYX
⇒ ∠ 2 = ∠ 3 (∠ 2 = 1/2 ∠ BXY and ∠ 3 = 1/2 ∠ CYX)
⇒ PY/XQ (If a transversal intersects two lines in such a way that a pair of alternate interior angles are equal, then the two lines are parallel) ...(2)
From (1) and (2), we get
PXQY is a parallelogram ....(3)
∠ CYD = 180°
⇒ 1/2 ∠ CYD = 180/2 = 90°
⇒ 1/2 (∠CYX + ∠ DYX) = 90°
⇒ 1/2 ∠ CYX + 1/2 ∠ DYX = 90°
⇒ ∠3 + ∠ 4 = 90°
⇒ ∠ PYQ = 90° ...(4)
So, using (3) and (4), we conclude that PXQY is a rectangle.
Hence proved.