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(2a)3 + (4b)3 + 2 × 2a × 4b(2a+4b)
8a + 64b + 8ab + 16a2b + 32ab2
Posted by C Anil Kumar 4 years, 6 months ago
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Sia ? 4 years, 6 months ago
(a−2b−3c)2
According to the equation ,
(a+b+c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
So we get,
Using the formula we can it write it as
(a−2b−3c)2 = a2+(−2b)2+(−3c)2+2a(−2b)+(2(−2b)(−3c)+2(−3c)a
On further calculation we get,
(a−2b−3c)2 = a2 + 4b2 + 9c2 − 4ab + 12bc − 6ac
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