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Ask QuestionPosted by Subodh Singh 9 years, 2 months ago
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Posted by Sai Mass 9 years, 2 months ago
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Posted by Himanshi M 9 years, 2 months ago
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Manish Gandhi 9 years ago
We know, (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) => (14)2 = 74 + 2(ab + bc + ca) => ab + bc + ca = 122 / 2 = 61
Again, using a3 + b3 + c3 - 3abc = (a + b + c) (a2 + b2 + c2 - ab - bc - ca)
434 - 3abc = 14 (74 - 61)
434 - 3abc = 14 (13)
434 - 3abc = 182
3abc = 434 - 182 = 252
Abc = 252/3 = 84 (Answer)
Rashmi Bajpayee 9 years, 2 months ago
(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) => (14)2 = 74 + 2(ab + bc + ca) => ab + bc + ca = 122 / 2 = 61
Again, using a3 + b3 + c3 - 3abc = (a + b + c) (a2 + b2 + c2 + ab + bc + ca)
=> 434 - 3abc = 14 (74 - 61)
=> -3abc = -252
=> abc = 84
Posted by Siddharth Yadav 9 years, 2 months ago
- 1 answers
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