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Navya Singh 7 years, 2 months ago
let the denominator be x then numerator becomes x-4, further your question is incomplete what is added to both ? whatever the no. is add it with the numerator x-4 and denominator x which will be equal to 1/2 than solve the equation
Posted by Ayush Lamba 6 years, 5 months ago
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Sia ? 6 years, 5 months ago
Steps of Construction.
- Draw MO = 4.5 cm
- With M as centre and radius ME = 6 cm, draw an arc.
- With O as centre and radius OE = 7.5 cm, draw an arc to intersect the arc of step 2 at E.
- With O as centre and radius OR = 6 cm, draw an arc on the side of OE opposite to that of M.
- With E as centre and radius ER = 4.5 cm, draw another arc to intersect the arc of step 4 at R.
- Join OR, RE, EM and EO
Then, MORE is the required parallelogram.
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Meghna Thapar 5 years, 6 months ago
The zones of weakness in the earth's crust due to the abrupt release of strain and it is called the Seismic zones. In the earth surface we can see various cracks found and those are called faults. The zone of weakness concept implies that there exist within the earth's crust relatively weak zones which when differentially stressed will fail more readily than will the surrounding rock. Such zones are often inferred to determine the extent, orientation and style of younger deformation.
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Meghna Thapar 5 years, 6 months ago
The major glands of the endocrine system include the pineal gland, pituitary gland, pancreas, ovaries, testes, thyroid gland, parathyroid gland, hypothalamus and adrenal glands. The endocrine system is the collection of glands that produce hormones that regulate metabolism, growth and development, tissue function, sexual function, reproduction, sleep, and mood, among other things.
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Posted by Sujal Rai 6 years, 5 months ago
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Sia ? 6 years, 5 months ago
Let a be the first term and d be the common difference of the given AP. Then,
Sm = sum of first m terms of the given AP;
Sn = sum of first n terms of the given AP.
{tex}\frac { S _ { m } } { S _ { n } } = \frac { m ^ { 2 } } { n ^ { 2 } } \Rightarrow \frac { \frac { m } { 2 } [ 2 a + ( m - 1 ) d ] } { \frac { n } { 2 } [ 2 a + ( n - 1 ) d ] } = \frac { m ^ { 2 } } { n ^ { 2 } }{/tex}
{tex} \Rightarrow \frac { 2 a + ( m - 1 ) d } { 2 a + ( n - 1 ) d } = \frac { m } { n }{/tex}
{tex}\Rightarrow{/tex} 2an+mnd-nd= 2am+mnd-md
{tex}\Rightarrow{/tex} 2an-2am=nd-md
{tex}\Rightarrow{/tex} 2a(n - m) = d(n - m) {tex}\Rightarrow{/tex}2a=d...(i)
{tex}\therefore \quad \frac { T _ { m } } { T _ { n } } = \frac { a + ( m - 1 ) d } { a + ( n - 1 ) d } = \frac { a + ( m - 1 ) \cdot 2 a } { a + ( n - 1 ) \cdot 2 a }{/tex} [from (i)]
{tex}= \frac { a + 2 a m - 2 a } { a + 2 a n - 2 a } = \frac { 2 a m - a } { 2 a n - a } = \frac { a ( 2 m - 1 ) } { a ( 2 n - 1 ) } = \frac { 2 m - 1 } { 2 n - 1 }{/tex}.
Posted by Sujal Rai 6 years, 5 months ago
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Sia ? 6 years, 5 months ago
Let units digit and tens digit of the two digit number be 'x' and 'y' respectively.
{tex}\therefore{/tex} Number is 10y + x
According to question, The two digit number = 4 {tex}\times{/tex} The sum of the digits
{tex}\therefore{/tex}10y + x = 4(y + x)
10y + x = 4y + 4x
10y - 4y = 4x - x
6y = 3x
2y = x....(i)
Also, The two digit number = 3 {tex}\times{/tex} The produce of the digits
10y + x = 3xy......(ii)
From equation...(i) 2y=x
{tex}\therefore{/tex}10y + 2y = 3(2y)y
12y = 6y2
6y2 - 12y = 0
6y(y - 2) = 0
{tex}\therefore y=0 \quad or \quad y=2{/tex}
The number cannot be zero, {tex}\therefore{/tex} y=0 is not possible
{tex}\therefore y=2 \quad and \quad x=4{/tex}
{tex}\therefore{/tex} The required number is 24.
Posted by Aмιт Ꭾ𝙰𝙷𝙰𝙳𝙸 7 years, 2 months ago
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Samridhi Yadav 7 years, 2 months ago
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