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Sia ? 4 years, 11 months ago
Let the digits at tens place be x.
And ones place be 3x .
Original Number = 10x + 3x = 13x
Number after interchanging = 10 × 3x + x = 30x + x = 31x
According to the Question,
⇒ Original number + New number = 88
⇒ 13x + 31x = 88
⇒ 44x = 88
⇒ x = 88/44
⇒ x = 2
Original Number = 13x = 13 × 2 = 26
Therefore, by considering the tens place and ones place as 3x and x.
The two digit number obtained is 62.
Hence, the two-digit number may be 26 or 62.
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