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Ask QuestionPosted by Shreyash Shinde 7 years, 1 month ago
- 1 answers
Saurav Deka 7 years, 1 month ago
Posted by Ayush Saini 7 years, 1 month ago
- 1 answers
Posted by Neha Jaleger 7 years, 1 month ago
- 1 answers
Anu S 7 years, 1 month ago
Posted by Neeraj Neeeraj 7 years, 1 month ago
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Posted by Vishal Sharma 7 years, 1 month ago
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Satya Swaroop Nune 7 years, 1 month ago
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Posted by Man Gupta 7 years, 1 month ago
- 1 answers
Posted by Nishant Satapathy 7 years, 1 month ago
- 2 answers
A Gautam 7 years, 1 month ago
Posted by Dhanush Bonkuri 7 years, 1 month ago
- 3 answers
Posted by Dhanush Bonkuri 7 years, 1 month ago
- 1 answers
Yogita Ingle 7 years, 1 month ago
(x2 - 5) (x + 5) + 25
= x3 + 5x2 - 5x - 25 + 25
= x3 + 5x2 - 5x
Posted by Govind Bansal 7 years, 1 month ago
- 1 answers
Yogita Ingle 7 years, 1 month ago
3( x+ y) - 9(x +y)2
= 3x + 3y - 9(x2 + 2xy + y2)
= 3x + 3y - 9x2 - 18xy - 9y2
Posted by Govind Bansal 7 years, 1 month ago
- 1 answers
Yogita Ingle 7 years, 1 month ago
3(x + y) - 9(x + y)(x + y)
= 3x + 3y - 9 [x2 + xy + xy + y2]
= 3x + 3y - 9[x2 + 2xy + y2]
= 3x + 3y - 9x2 - 18xy - 9y2
Posted by Manish Kumar 7 years, 1 month ago
- 2 answers
Yogita Ingle 7 years, 1 month ago
(4pq + 3q)2 - (4pq - 3q)2
= [(4pq + 3q)+ (4pq -3q)][(4pq + 3q)- (4pq -3q)] [∵ a2 - b2 = (a+b) (a-b)]
= [4pq + 3q + 4pq - 3q][4pq + 3q- 4pq + 3q ]
= [8pq][6q]
= 48p2q
Posted by Rupika Manivannan 7 years, 1 month ago
- 1 answers
Posted by Jagpreet Singh 7 years, 1 month ago
- 0 answers
Posted by Ayesha Khan 7 years, 1 month ago
- 1 answers
Kiti Sharma 7 years, 1 month ago
Posted by Rakshith U 7 years, 1 month ago
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Posted by Biju Mathew 7 years, 1 month ago
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Posted by Shaik Fayaaz 7 years, 1 month ago
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Posted by Alankar Gaikwad 7 years, 1 month ago
- 1 answers
Yogita Ingle 7 years, 1 month ago
(2x + 5) (4x - 3)
= 2x(4x - 3) + 5(4x - 3)
= 8x2 - 6x + 20x - 15
= 8x2 + 14x - 15
Posted by Neeraj Sahu 7 years, 1 month ago
- 1 answers
Yogita Ingle 7 years, 1 month ago
{tex}\frac42\div\frac32\;=\;\frac42\times\frac23\;=\frac43{/tex}

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Kashish Bhambhani 7 years, 1 month ago
0Thank You