CBSE > Class 08 > Mathematics | CBSE Board | Homework Help

Let a,b,c be the sides of the original ∆ & s be its semi perimeter.
S= (a+b+c)/2
2s= a+b+c.................(1)
The sides of a new ∆ are 2a,2b,2c [ given: Side is doubled]

Let s' be the new semi perimeter.
s'= (2a+2b+2c)/2
s'= 2(a+b+c) /2
s'= a+b+c
S'= 2s. ( From eq 1)......(2)
Let ∆= area of original triangle
∆= √s(s-a)(s-b)(s-c).........(3)

∆'= area of new Triangle
∆' = √s'(s'-2a)(s'-2b)(s'-2c)
∆'= √ 2s(2s-2a)(2s-2b)(2s-2c) [From eq. 2]
∆'= √ 2s×2(s-a)×2(s-b)×2(s-c)
= √16s(s-a)(s-b)(s-c)
∆'= 4 √s(s-a)(s-b)(s-c)
∆'= 4∆. (From eq (3))
Increase in the area of the triangle= ∆'- ∆= 4∆ - 1∆= 3∆
%increase in area= (increase in the area of the triangle/ original area of the triangle)× 100
% increase in area= (3∆/∆)×100
% increase in area= 3×100=300 %
Hence, the percentage increase in the area of a triangle is 300%.

1Thank You

ANSWER

Find area of the following polygons.

Posted by Kashyap Mandal 6 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Gajavelli Swathi 6 years, 11 months ago

Type full question then i will give the answer

0Thank You

Vansh Chauhan 6 years, 11 months ago

First show us "FOLLOWING POLYGON"

0Thank You

ANSWER

Find height of cuboif whose base area is 180 cm and volume is 900 cm

Posted by Shivam Maurya 6 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Vansh Chauhan 6 years, 11 months ago

Or 1 simple equation be like this Base Area= 180cm2 Volume=900cm3 Le the height be h cm As we know Volume =ba ×h 900cm3=180cm2×h H=900cm3/180cm2 H=5 answer

0Thank You

Vansh Chauhan 6 years, 11 months ago

Here, base area of cuboid is =180cm2 (given) And volume of same cuboid is = 900 cm3 Let the height be h cm As we know that Since ,Volume =ba × h Therefore Equation 900 cm3 = 180cm2 × h H= 900cm3/180cm2 H= 5 cm ans

0Thank You

ANSWER

a field is 80 m long and 50 m broad in one corner of the field a pit which is 10 m long 7.5 m broad and 8m deep has been dugout the earth taken out of it is evenly spread over the remaining part of the field find the rise in the level of the field

Posted by Prince Prince 6 years, 11 months ago

CBSE > Class 08 > Mathematics

0 answers

ANSWER

Evaluate (1upon2)to the power -5

Posted by Ayush Gupta 6 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Pranjali Singh 6 years, 11 months ago

1Thank You

ANSWER

Any one tell me about factorsiation ?

Posted by Payal Ahlawat 6 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Payal Ahlawat 6 years, 11 months ago

But can u give me some example

2Thank You

Saurabh Sharma 6 years, 11 months ago

I'm

1Thank You

ANSWER

the numerators of a friction is 8 less than its denominator when is added to the numerator and 2 is subtracted from the denominator the friction abtained is 2/7 find the origin friction

Posted by Devaa Pandat 7 years ago

CBSE > Class 08 > Mathematics

0 answers

ANSWER

Product of : 1. 2m , 3pq

Posted by Shreya Sengar 7 years ago

CBSE > Class 08 > Mathematics

2 answers

Yogita Ingle 7 years ago

1.2 m × 3 pq
= (1.2 × 3) mpq
= 3.6 mpq

1Thank You

Shreya Sengar 5 years, 8 months ago

6pqm

1Thank You

ANSWER

The value of 30.5 - 30.4+ 30.3 - 30.2 +30.1-30+29.9-29.8+29.7-29.6+29.5-29.4+29.2+29.1-29.0=________

Posted by Karunya Karunya 4 years, 8 months ago

CBSE > Class 08 > Mathematics

1 answers

Sia ? 4 years, 8 months ago

29.9

0Thank You

ANSWER

Whay is the area of cuboid

Posted by Aashish Manish Jha 7 years ago

CBSE > Class 08 > Mathematics

5 answers

Arunitha Mohan 6 years, 11 months ago

Area of cuboid is also called as TSA of cuboid where TSA is total surface area that is 2lb+2bh+2lhwhich is also 2(lb+bh+lh)where l is length , b is breadth and h is height.

0Thank You

Asif Saleem 7 years ago

2(lb+bh+hl)

0Thank You

Aashu Kumar 7 years ago

Area of cuboid = 2(lb+bh+hl)

1Thank You

Kasaraneni Sujan 7 years ago

2(lb+bh+lh) Where l is length H is heigh and B is width or breath

0Thank You

Aarti Prajapati Prajapati 7 years ago

l×b×h