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Yogita Ingle 7 years ago
Given : Let ABCD is cyclic quadrilateral.
To prove : ∠A + ∠C = 180° and ∠B + ∠D = 180°.
Construction : join OB and OD.

Proof : ∠BOD = 2 ∠BAD
∠BAD = 1/2∠ BOD
Similarly ∠BCD = 1/2 ∠DOB
∠BAD + ∠BCD = 1/2∠BOD + 1/2 ∠DOB
=1/2(∠ BOD + ∠DOB)
= (1/2)X360° = 180°
Similarly ∠B + ∠D = 180°
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Gaurav Seth 7 years ago
3x2 + 7x - 3x -7 = 0
x(3x+7) - 1 (3x +7) =0
x-1 =0 or 3x+7 =0
x= 1 or x = - 7/3
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Neha Krishnan 7 years ago
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