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  • 1 answers

Yogita Ingle 7 years ago

Given : Let ABCD is cyclic quadrilateral.
To prove : ∠A + ∠C = 180°  and ∠B + ∠D = 180°.
Construction : join OB and OD.


Proof : ∠BOD = 2 ∠BAD
     ∠BAD = 1/2∠ BOD
Similarly ∠BCD = 1/2 ∠DOB
∠BAD + ∠BCD = 1/2∠BOD + 1/2 ∠DOB
                   =1/2(∠ BOD + ∠DOB)
                   = (1/2)X360° = 180°
Similarly ∠B + ∠D = 180°

  • 1 answers

Tejasvi Gaikwad 7 years ago

Understand and Practise attentively.
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  • 3 answers

Raisha Prakash 7 years ago

Great timepass????????????????????????????????????????
2
2
  • 1 answers

Gaurav Seth 7 years ago

3x2 + 7x - 3x -7 = 0

x(3x+7) - 1 (3x +7) =0

x-1 =0 or 3x+7 =0

x= 1 or x = - 7/3

  • 0 answers
  • 1 answers

Siddhi Gupta 7 years ago

Diameter=7CM; Radius=3.5cm; Circumference=(2*3.14*3.5)/2; =10.99 or 11cm
  • 1 answers

Kaavya Sethi 7 years ago

Formula = marked price - amount paid multiplied by 100 divided by marked price Marked price - amount paid is ₹1350 - 1250 which is 100 then multiply it by 100 and then divide it by 1250 ( 100x100/125)
  • 1 answers

Richa Shree 7 years ago

(×+y)^8
  • 2 answers

Kaavya Sethi 7 years ago

Square of 56=56x56=3136

Jamal Raja 7 years ago

56 square = 3136
  • 2 answers

Shivam Gaitonde 7 years ago

No specific questions but try to olve as many questions as u can

Shivam Gaitonde 7 years ago

Just learn properties and believe in ur self

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