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Ask QuestionPosted by Manu Sinha 6 years, 6 months ago
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Posted by Soharshi Kohli 6 years, 6 months ago
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Posted by Harsh Gupta 6 years, 6 months ago
- 1 answers
Sia ? 6 years, 6 months ago
12 cm is divided into 6 cm each, 16 cm is divided into 8 cm each
Step-by-step explanation: In the parallelogram, opposite sides are equal & parallel
Let say ABCD is a parallelogram & Diagonals AC & BD intersect at O
Now comparing Δ AOB & ΔCOD
∠AOB = ∠COD ( opposite angles)
∠ABO = ∠CDO ( ad BD is cutting two ║ lines AB & CD)
Similarly ∠BAO = ∠DCO ( ad AC is cutting two ║ lines AB & CD)
So Δ AOB ≅ ΔCOD
AO/CO = BO/DO = AB/CD
AB = CD
=> AO/CO = BO/DO = 1
=> AO = CO & BO = DO
AO + CO = AC => AO = CO = AC/2
BO + DO = BD => BO = DO = BD/2
Hence Diagonals are bisected
Diagonal 12 cm is divided into 6 cm each
Diagonal 16 cm is divided into 8 cm each
Posted by Sweat Singh 6 years, 6 months ago
- 2 answers
Sia ? 6 years, 6 months ago
Five rational numbers greater than –2 are :
{tex}\frac{{ - 3}}{2}, - 1,\frac{{ - 1}}{2},0,\frac{1}{2}{/tex}
Posted by Krish Goyal 6 years, 6 months ago
- 1 answers
Posted by Neelesh Dawani 6 years, 6 months ago
- 1 answers
Soharshi Kohli 6 years, 6 months ago
Posted by Karuna Gautam 6 years, 6 months ago
- 0 answers
Posted by Sharanpreet Virk 6 years, 6 months ago
- 2 answers
Purva Dhammi 6 years, 6 months ago
Sum of measure of interior angles of a regular polygon
= (n-2) × 180°
Where n = no of sides of the polygon.
Eg. Finding the sum of measure of a quadrilateral by this formula
Sides of quadrilateral(n) = 4
Sum of interior angles = (n-2)×180°
= (4-2)×180°
= 2×180° = 360°
Posted by Pranjal Malhotra 6 years, 6 months ago
- 2 answers
Yogita Ingle 6 years, 6 months ago
Let the c.p. of 1 card be rs x.
so, the c.p. of 8 cards=rs 8.
since, the s.p. of 8 cards= the c.p. of 10 cards= rs 10.
s.p.>c.p.
so, gain=10-8=rs2
so,gain%=2/8×100%=25%
Posted by Anna Thurai 6 years, 6 months ago
- 0 answers
Posted by Pardeep Kaur 6 years, 6 months ago
- 0 answers
Posted by Sanjay Jha 6 years, 6 months ago
- 2 answers
Kiran Singh 6 years, 6 months ago
Konkana Bhattacharjee 6 years, 6 months ago
Posted by Murtaza Mushtaq 6 years, 6 months ago
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Posted by Mansi Kshirsagar 6 years, 6 months ago
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Posted by Kasthuri Nayak 6 years, 6 months ago
- 1 answers
Ananya Garg 6 years, 6 months ago
numbers that can be defined in the form of p/q and q is not equal to 0. Eg. 3/5
Posted by Devanshi Tandon 6 years, 6 months ago
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Posted by Pardeep Kaur 6 years, 6 months ago
- 1 answers
Sia ? 6 years, 6 months ago
Father was 30 years old 42 - 30 = 12 years before
Age of son 12 years before = 14 - 12 = 2 years
{tex}\therefore{/tex} Ratio of age of father to the age of son when father was 30 years old.
{tex}=\frac{30}{2}=\frac{30 \div 2}{2 \div 2}{/tex}[{tex}\therefore{/tex}H.C.F.(30, 2) = 2]
{tex}=\frac{15}{1}{/tex} = 15 : 1
Posted by Pardeep Kaur 6 years, 6 months ago
- 2 answers
Posted by Jigar Pandey 6 years, 6 months ago
- 1 answers
Sia ? 6 years, 6 months ago
{tex}\sqrt{\frac{25}{49}} =\frac{\sqrt{25}}{\sqrt{49}}=\frac{5}{7}{/tex}
Posted by Priyanshi Pathak 6 years, 6 months ago
- 2 answers
Posted by Dar Younis 6 years, 6 months ago
- 3 answers
Sia ? 6 years, 6 months ago
When starting off in math, students are introduced to pi as a value of 3.14 or 3.14159. Though it is an irrational number, some use rational expressions to estimate pi, like 22/7 of 333/106. (These rational expressions are only accurate to a couple of decimal places.)
Posted by Saroj Devi 6 years, 6 months ago
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Posted by Prabhat Kumar 6 years, 6 months ago
- 2 answers
Sia ? 6 years, 6 months ago
Area = {tex}\frac{\sqrt 3}{4}{/tex}a2, where a is the side
Area = {tex}\frac{\sqrt 3}{4} \times 8^2{/tex}
= {tex}\frac{\sqrt 3}{4} \times 64{/tex}
= {tex}\sqrt 3 \times 16{/tex}
= {tex}16\sqrt 3{/tex} cm2
Devanshi Tandon 6 years, 6 months ago
Posted by Anuj Chand 6 years, 6 months ago
- 1 answers
Posted by Naman Aggarwal 6 years, 6 months ago
- 0 answers
Posted by Umang Chaudhary 6 years, 6 months ago
- 1 answers
Sia ? 6 years, 6 months ago
(50 + 3-1) {tex}\times{/tex}32
= (1 + {tex}\frac 13{/tex}) {tex}\times{/tex}9
= {tex}\frac 43\times{/tex}9
= 4{tex}\times{/tex}3 = 12
Posted by Vishal Kumar 6 years, 6 months ago
- 1 answers
Sia ? 6 years, 6 months ago
Let the smaller number be x.
Then, the larger number = x + 15
{tex}\because {/tex} Sum of two numbers is 95
∴ x + (x + 15) = 95
∴ 2x + 15 = 95
∴ 2x = 95 – 15 . . . . [Transposing 15 to R.H.S.]
∴ 2x = 80
∴ {tex}x = \frac{{80}}{2}{/tex}. . . . [Dividing both sides by 2]
∴ x = 40
∴ x + 15 = 40 + 15 = 55
Hence, the desired numbers are 40 and 55.
Verification
55 = 40 + 15
40 + 55 = 95
Posted by Krish Aggarwal 6 years, 6 months ago
- 5 answers
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