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Rashmi Dahiya 6 years, 8 months ago
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Sia ? 6 years, 8 months ago
Let the numbers be x and 5x.
If 21 is added to both the numbers, then first new number = x + 21
and, second new number = 5x + 21
Case I. When first new number is twice the second new number.
Then,
x + 21 = 2(5x + 21)
∴ x + 21 = 10x + 42
∴ x – 10x = 42 – 21 . . . . [Transposing 10x to L.H.S. and 21 to R.H.S.]
∴ – 9x = 21
∴ {tex}x = - \frac{{21}}{9}{/tex}. . . . [Dividing both sides by –9]
∴ {tex}x = \frac{{ - 21 \div 3}}{{9 \div 3}}{/tex}
∴ {tex}x = - \frac{7}{3}{/tex}
∴ {tex}5x = \left( { - \frac{7}{3}} \right) \times 5 = - \frac{{35}}{3}{/tex} hence the numbers are {tex} - \frac{7}{3}{/tex} and {tex} - \frac{{35}}{3}{/tex}.
This case is inadmissible as the required numbers are positive.
Case II. When second new number is twice the first new number.
Then, 5x + 21 = 2(x + 21)
∴ 5x + 21 = 2x + 42
∴ 5x – 2x = 42 – 21 . . . . [Transposing 2x to L.H.S. and 21 to R.H.S.]
∴ 3x = 21
∴ {tex}x = \frac{{21}}{3}{/tex} . . . . [Dividing both sides by 3]
∴ x = 7
∴ 5x = 5 × 7 = 35 hence, the numbers and 7 and 35.
Posted by Aayush Raj 6 years, 8 months ago
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Yogita Ingle 6 years, 8 months ago
A fraction is written in the form of m/n , where n is not 0 and m & n are natural numbers. For example: 12/23, 10/32, 12/10, 4/21.
A rational number can also be written in the form of m/n , where n is not 0 and m & n are integers. For example: 15/7, -18/13, 3/-7, -6/-12.
All Fractions can be termed as Rational Numbers, however, all Rational Numbers cannot be termed as Fractions. Only those Rational Numbers in which ‘m’ and ‘n’ are positive integers are termed as Fractions.
Posted by Aditya Deshmukh 6 years, 8 months ago
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Ashish Raj 6 years, 8 months ago
Rachna Kukreti 6 years, 8 months ago
Posted by ♥️Aayusha Kshirsagar♥️ 6 years, 8 months ago
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Yogita Ingle 6 years, 8 months ago
-3(z - 4) - 2 (3z + 1) = -8
-3z + 12 - 6z - 2 = -8
-9z + 10 = -8
-9z = -8 -10
-9z = -18
9z = 18
z = 18/9 = 2
Posted by Abhinav Gupta 6 years, 8 months ago
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Hitarth Takkar 6 years, 8 months ago
Yogita Ingle 6 years, 8 months ago
If any two angles and side included between the angles of one triangle are equivalent to the corresponding two angles and side included between the angles of the second triangle, then the two triangles are said to be congruent by ASA rule.
Posted by Devi Rajkumar 6 years, 8 months ago
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Renuka Seiwal 6 years, 8 months ago
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Sia ? 6 years, 8 months ago
The number of diagonals in a polygon = {tex}\frac{n(n - 3)}{2}{/tex}
Posted by Maana Kaushik 6 years, 8 months ago
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