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Ask QuestionPosted by Neetesh Yadav 6 years, 6 months ago
- 3 answers
Posted by Tarun Pandey 6 years, 6 months ago
- 1 answers
Gaurav Seth 6 years, 6 months ago
For 1st buffalo:
SP= Rs 20,000
Profit = 5%
CP = 
= 
= Rs
= Rs 
For 2nd buffalo:
SP = Rs 20,000
Loss = 10%
CP = 
= Rs 
= Rs 
Now, Overall SP = Rs 2 
20,0000
= Rs 40,000
Overall CP = 
= Rs 
= Rs 
= Rs 
= Rs 41269.84
Now, CP > SP
∴ Overall loss = Rs (41269.84 - 40000)
= Rs 1269.84
Posted by Seema Bhadra 6 years, 6 months ago
- 1 answers
Sia ? 6 years, 6 months ago
we are given that the two zeroes of given polynomial are (3 + {tex}\sqrt{2}{/tex}) and (3 - {tex}\sqrt{2}{/tex}).
The given quadratic polynomial is
p(x) = 2x4 - 11x3 + 7x2 + 13x - 7
Sum of (3 + {tex}\sqrt{2}{/tex}) and (3 - {tex}\sqrt{2}{/tex}) = (3 + {tex}\sqrt{2}{/tex}) + (3 - {tex}\sqrt{2}{/tex}) = 6
Product of (3 + {tex}\sqrt{2}{/tex}) and (3 - {tex}\sqrt{2}{/tex}) = (3 + {tex}\sqrt{2}{/tex})(3 - {tex}\sqrt{2}{/tex}) = 9 - 2 = 7
Polynomial whose zeros are 3 + {tex}\sqrt{2}{/tex} and 3 - {tex}\sqrt{2}{/tex} is
x2 - (sum of zeros)x + (Product of zeros) = x2 - 6x + 7
Now we Divide p(x) by x2 - 6x + 7 as:
Therefore, Quotient = 2x2 + x - 1 and remainder = 0.
Other two zeros of polynomial p(x) are also the zeros of q(x)
i.e., q(x) = 2x2 + x - 1 = 2x2 + 2x - x - 1 (by splitting the midddle term)
= 2x(x + 1) - (x + 1) = (x + 1 ) (2x - 1)
In order to find the values of x, put(x) = 0
{tex}\Rightarrow{/tex} (x + 1) (2x - 1) = 0
{tex}\Rightarrow{/tex} Either x + 1 = 0 or 2x - 1 = 0
{tex}\Rightarrow{/tex} Either x = -1 or x = {tex}\frac{1}{2}{/tex}
{tex}\therefore{/tex} The zeros of given polynomial p(x) are
{tex}\frac{1}{2}{/tex}, -1, (3 + {tex}\sqrt{2}{/tex}) and (3 - {tex}\sqrt{2}{/tex})
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Charu Verma 6 years, 6 months ago
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