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Preeti Dabral 2 years, 9 months ago
the number in an ordered pair of numbers (as x in (x, y)) that gives the location of a point along the x-axis. called also x-coordinate.
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Posted by 𝕳𝖆𝖙𝖍𝖎𝖒 𝕾𝖍𝖊𝖗𝖆𝖋 2 years, 9 months ago
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𝕳𝖆𝖙𝖍𝖎𝖒 𝕾𝖍𝖊𝖗𝖆𝖋 2 years, 9 months ago
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Posted by A J 2 years, 9 months ago
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Preeti Dabral 2 years, 9 months ago
We have, y2 + 8zx - 2xy - 4yz
= y2 - 2xy + 8zx - 4yz = y(y - 2x) -4z(y - 2x)
= (y - 2x) (y - 4z)
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Preeti Dabral 2 years, 9 months ago
4 ^ (x+3) = 1024
4 ^ (x+3) = 4 ^ (5)
Using the identity,
if a ^ n = a ^ m, then n = m
Thus, x + 3 = 5
x = 5 - 3
Thus, x = 2
Posted by Shagun Choudhary 2 years, 9 months ago
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Preeti Dabral 2 years, 9 months ago
Let the radius and height of the cylinder be r and h, respectively.
Curved surface area of cylinder = 2{tex}\pi{/tex}rh
Area of base = {tex}\pi{/tex}r2
Sum of areas of bases = 2{tex}\pi{/tex}r2
According to the question, 4 {tex}\times{/tex} Curved surface area = 6 {tex}\times{/tex} Sum of areas of bases
4 {tex}\times{/tex} 2{tex}\pi{/tex}rh = 6 {tex}\times{/tex} 2{tex}\pi{/tex}r2
= 8{tex}\pi{/tex}rh = 12{tex}\pi{/tex}r2
= 2h = 3r
{tex}\Rightarrow \quad r=\frac{2}{3} h{/tex}
{tex}\therefore \quad r=\frac{2}{3} \times 12{/tex} = 8cm [{tex}\because{/tex} h = 12 cm, given]
{tex}\therefore{/tex} Curved surface area of the cylinder = 2{tex}\pi{/tex}rh
= {tex}2 \times \frac{22}{7} \times 8 \times 12=\frac{44 \times 8 \times 12}{7}{/tex}
= 603.428 cm2
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E. Anisha 2 years, 9 months ago
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