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Sia ? 6 years, 5 months ago
Let the number in one’s place be x and the number in ten’s place be y such that the number is yx.
Given that x + y = 11
y = 11 – x
Thus the number
= 10 y + x
= 10(11 – x) + x = 110 – 10x +x = 110 – 9x
After interchanging, the number becomes
= 10x + y
= 10(x) + (11 – x) = 11 + 9x
Given that after interchanging the number exceeds by 27.
11 + 9x = 110 – 9x + 27
9x + 9x = 110 – 11 + 27
18x = 126
x = {tex}\frac{126}{18}{/tex}
x = 7
y = 11 - x = 11 – 7 = 4
y = 4
Therefore the number is 47.
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Yogita Ingle 6 years, 5 months ago
A collection of 3 numbers such that the sum of the square of the smaller 2 numbers is equal to the square of the third number.
Let us take an example : 3, 4, 5
3² + 4² = 5²
9 + 16 = 25
25 = 25
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Pranjal Srivastava 6 years, 5 months ago
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