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Ask QuestionPosted by Ch Alli 5 years, 5 months ago
- 3 answers
Posted by Sangeeta Rani 5 years, 5 months ago
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Posted by Dhananjay Sharma 5 years, 5 months ago
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Akshiii ?? 5 years, 5 months ago
Akshiii ?? 5 years, 5 months ago
Posted by Mohan Lal 5 years, 5 months ago
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Posted by [email protected] [email protected] 5 years, 5 months ago
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Posted by Mahi 07 A 5 years, 5 months ago
- 1 answers
Yogita Ingle 5 years, 5 months ago
(a+b) (a-b)
a) a²-64
= a2- (8)2
= (a - 8) ( a +8)
b)49x²-1
= (7x)2 - (1)2
= (7x - 1) (7x + 1)
Posted by Abhipsa Patra 5 years, 5 months ago
- 1 answers
Yogita Ingle 5 years, 5 months ago
Let the numbers are x and y
Then sum of two number is 11
x + y = 11........... (1)
And difference = 5
x - y = 5............. (2)
Addding (1) and (2), we get
2x = 16
x = 16/2 = 8
Put x = 8 in (1) , we get
8 + y = 11
y = 11 -8
y = 3
Posted by Palak Khandal 5 years, 5 months ago
- 1 answers
Yogita Ingle 5 years, 5 months ago
The sum of the two digits is 9.
On interchanging the digits, the resulting new number is greater than the original number by 27.
Let us assume the digit of units place be x.
Then the digit of tens place will be 9-x.
Thus the two-digit number is 10(9-x) + x
Let us reverse the digit
the number becomes 10x + (9-x).
As per the given condition
10x + (9-x) = 10(9-x) + x + 27
= 9x + 9 = 90 – 10x + x + 27
= 9x + 9 = 117 – 9x
On rearranging the terms we get,
=18x = 108
x = 6
So the digit in units place is 6
Digit in tens place is 9-x= 9-6=3
Hence the number is 36
</article>Posted by Prabhat Yadav 5 years, 5 months ago
- 1 answers
Gaurav Seth 5 years, 5 months ago
Every parallelogram is not a trapezium .
The pair of opposite sides of a parallelogram are equal and parallel but in the case of the trapezium , this is not true .
Posted by Shahfed Khan 5 years, 5 months ago
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Posted by Digbijoy Debnath 5 years, 5 months ago
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Abhay Singh 5 years, 5 months ago
Posted by Anshuman Samantaray 5 years, 5 months ago
- 5 answers
Posted by Vatsal Lad 5 years, 5 months ago
- 1 answers
Yogita Ingle 5 years, 5 months ago
let two numbers are x and y
As per given condition
x - y = 10...... (I)
And the second condition
x: y = 2: 3
x/y = 2/3
x = 2/3 y
Put value of x in (I)
2/3 y - y = 10
(2/3 - 1) y = 10
-1/3 y = 10
y = -30
Put it in (I)
x - (-30) = 10
x + 30 = 10
x = 10 - 30
x= -20
Posted by Kishora L 5 years, 5 months ago
- 2 answers
Posted by [email protected] [email protected] 5 years, 5 months ago
- 1 answers
Digbijoy Debnath 5 years, 5 months ago
Posted by Helping Girl ? 5 years, 5 months ago
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Gaurav Seth 5 years, 5 months ago
inverse variation = x1y1 = x2y2
= 800×25=(800+200)×x
= 800×25=1000×x
20000 = 1000×x
x = 20000 ÷ 1000
x = 20
Posted by Akash Kumar 5 years, 5 months ago
- 2 answers
Gaurav Seth 5 years, 5 months ago
Let x be the first number.
Since, it is odd
Let x + 2 be the second number.
Let x + 4 be the third number.
Given that the sum is 81
x + (x+2) + (x+4) = 81
3x + 6 = 81
3x = 81 - 6
3x = 75
x = 75/3
x = 25
Therefore,
x+2 = 25 + 2 = 27
x + 4 = 25 + 4 = 29
There fore the numbers are x, x+2, x+4
25, 27, 29
Posted by Golden Shankar 5 years, 5 months ago
- 1 answers
Gaurav Seth 5 years, 5 months ago
A linear equation is an equation for a straight line.
Example:
These are all linear equations:
| y = 2x + 1 |
| 5x = 6 + 3y |
| y/2 = 3 − x |
Posted by Sangeeta Rani 5 years, 5 months ago
- 4 answers
Posted by Sangeeta Rani 5 years, 5 months ago
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Posted by Sen Kathir 5 years, 5 months ago
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Posted by Kanishka Salukethakur 5 years, 5 months ago
- 4 answers
Gaurav Seth 5 years, 5 months ago
Let consecutive numbers be, x, x+1 and x+2.
According to the condition, we have
x + [x+1] +[x+2] =51
or x + x + 1 + x + 2 =51
or 3x + 3 = 51
Transposing 3 to RHS, we have
3x = 51 - 3 = 48
Dividing both sides by 3, we have:
or x =16
Now x + 1 = 16 + 1 = 17
and x + 2 = 16 + 2 =18
Thus, the required three consecutive numbers are: 16, 17 and 18.
Posted by Sabina Perween 5 years, 5 months ago
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Posted by Ch Alli 5 years, 5 months ago
- 2 answers
Aryan Raj 5 years, 5 months ago
Posted by Arpit Kumar 5 years, 5 months ago
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Posted by Shantanu Goyal 5 years, 5 months ago
- 1 answers
Yogita Ingle 5 years, 5 months ago
Let Asha's present age=x
let Nirmal's present age = y
therefore, x:y = 5:6
let common multiple be k
then, x=5k and y=6k
and, asha's age 5 years from now = x+5
Nirmal's age 5 years from now= y+5
therefore, (x+5):(y+5)= 6:7
5k+5 / 6k+5 = 6/7
or, 35k+35= 36k+30
or, k=5
therefore, present age of Asha=25
and Nirmal= 30
Posted by Bhuvan Sai Naidupalli Bhuvan Sai 5 years, 5 months ago
- 5 answers
Posted by Khushpreet Kaur 5 years, 5 months ago
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Posted by Kajal Kumari 5 years, 5 months ago
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Ch Alli 5 years, 5 months ago
1Thank You