No products in the cart.

Ask questions which are clear, concise and easy to understand.

Jitendra Kumar 1 day, 9 hours ago

0.03125

Jitendra Kumar 1 day, 9 hours ago

Cube of 33- 35937 Cube of 97- 912673

Jitendra Kumar 1 day, 8 hours ago

Commutative Property- a+b=b+a

Jitendra Kumar 1 day, 8 hours ago

3\5

Nihal Bendi 3 days, 12 hours ago

Fast

Jitendra Kumar 11 hours ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
• Don't post personal information, mobile numbers and other details.
• Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
• Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
• Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Swati Jha 4 days, 10 hours ago

<hr />

=2√2 ( 2√2 - 3√3) + 3√3 (2√2 - 3√3)

=2√2 × 2√2 - 2 √2 × 3√3 + 3 √3 × 2√2 -3√3 ×3√3

=8 - 6 √6 + 6√6 - 27

=8 -27

=-19 Ans.

Jitendra Kumar 1 day, 8 hours ago

-183/70

Himanshu Kumar 11 hours ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
• Don't post personal information, mobile numbers and other details.
• Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
• Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
• Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Ishan Chatterjee 11 hours ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
• Don't post personal information, mobile numbers and other details.
• Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
• Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
• Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Jitendra Kumar 1 day, 8 hours ago

603/70

Rithwak Kumar 6 days, 11 hours ago

1.2857142

Saif Khan 1 week ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
• Don't post personal information, mobile numbers and other details.
• Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
• Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
• Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
• Don't post personal information, mobile numbers and other details.
• Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
• Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
• Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Prafful Goyal 1 week, 3 days ago

-59/8

Rithwak Kumar 6 days, 11 hours ago

Reciproal of 0is not defined

Varshitha Siriki 1 week, 3 days ago

Yes

Manjesh Kumar 1 week, 4 days ago

4-3n+5n 6=21 42

Aryan Singh 1 week, 6 days ago

Yes

Deepika Sharma 1 week, 6 days ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
• Don't post personal information, mobile numbers and other details.
• Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
• Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
• Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Deepika Sharma 1 week, 6 days ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
• Don't post personal information, mobile numbers and other details.
• Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
• Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
• Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Deepika Sharma 2 weeks, 1 day ago

What is (a²+b²)??..

Pallavi Ladwa 3 weeks, 4 days ago

08 h :58 m : 07 s

Manjesh Kumar 1 week, 4 days ago

Mc

Anurag Singh 2 weeks, 5 days ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
• Don't post personal information, mobile numbers and other details.
• Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
• Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
• Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Chenna Ram 3 weeks, 5 days ago

Vansh Sharma 3 weeks, 5 days ago

Volume of the cube with side 6 cm is

Chenna Ram 3 weeks, 5 days ago

2p2_37q

Yusuf Mahmood 4 weeks ago

Bro I can't understand what u ask but btw area of trapezium= 1/2 × (sum of ll sides ) × height

Mayank Dhruw 4 weeks, 1 day ago

Whole numbers, also known as counting numbers, are the set of numbers that include all positive integers from zero onwards. This set does not include fractions or decimals. It typically includes the numbers 0, 1, 2, 3, 4, and so on, up to infinity.

Sachi Salavi 1 week, 6 days ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
• Don't post personal information, mobile numbers and other details.
• Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
• Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
• Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Tejjas Verma 4 weeks, 1 day ago

49.10000000.25/.5

Mayank Dhruw 4 weeks, 1 day ago

To find the root of the equation $$x - 8 = 2$$, you need to isolate $$x$$ on one side of the equation. Starting with: $x - 8 = 2$ Add 8 to both sides to isolate $$x$$: $x = 2 + 8$ Simplify: $x = 10$ So, the root of the equation $$x - 8 = 2$$ is $$x = 10$$.

Mayank Dhruw 4 weeks, 1 day ago

To find the square root of 400 using long division method, you can follow these steps: 1. Start by grouping the digits in pairs from right to left. Since 400 is a perfect square, it can be written as $$20^2$$. So, we group the digits as 4 and 00. 2. Begin with the largest number whose square is less than or equal to 4, which is 2. Write 2 as the quotient and divisor, and place a decimal point after it. 3. Square 2, which equals 4. Subtract 4 from the first group (4). Bring down the next group (00) next to the remainder. 4. Double the quotient (2) to get 4, and write it as the trial divisor. Add a digit to the quotient (let's say 'x') such that 4x multiplied by x is less than or equal to 400. Since $$20^2 = 400$$, we know that x should be 0. 5. Multiply the trial divisor (40) by 0, and subtract the result from the number formed by the first two groups (400). This gives you the remainder. 6. Bring down the next pair of zeros (00) and repeat steps 4 and 5 until you have enough decimal places or until you reach the desired level of accuracy. Since 400 is a perfect square, its square root is a whole number, which is 20. So, the square root of 400 by long division method is 20.

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
• Don't post personal information, mobile numbers and other details.
• Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
• Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
• Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Mayank Dhruw 4 weeks, 1 day ago

To find the gain or loss percent, we first need to calculate the profit or loss made by the man. Profit = Selling Price - Cost Price Given: Cost Price (CP) = ₹1250 Selling Price (SP) = ₹1600 Profit = SP - CP Profit = ₹1600 - ₹1250 Profit = ₹350 Now, to find the gain percent: Gain Percent = (Profit / Cost Price) * 100 Substitute the values: Gain Percent = (350 / 1250) * 100 Calculate: Gain Percent = (0.28) * 100 Gain Percent = 28% So, the man made a profit of 28%.

M.K Sanjai 9Th 1 month ago

1250-1600 =350 350÷1250×100

Dhiyashri M 1 month ago

It seems not a question u have typed it randomly

Yusuf Mahmood 4 weeks ago

Hey vanshika, We all know that sum of angle of a parallelogram is 360°. So if you give the measurement of 3 sides so we can find it by let the unknown side as x. and make an equation like : X + sum of angle of all three sides = 360° But the problem is that you give the measurement of only one side 110° and ask 2 variable and we all know that we learn to find only one variable by the chapter 'linear equation in one variable' so yahhhh make your question right 👍🏼

Mayank Dhruw 4 weeks, 1 day ago

Let's denote the tens digit of the two-digit number as $$x$$ and the units digit as $$y$$. According to the given conditions: 1. The sum of the digits is 9: $x + y = 9$ 2. The number is 6 times the unit digit: $10x + y = 6y$ Now, we have a system of two equations: $\begin{cases} x + y = 9 \\ 10x + y = 6y \end{cases}$ From the first equation, we can express $$x$$ in terms of $$y$$: $x = 9 - y$ Substitute this expression for $$x$$ into the second equation: $10(9 - y) + y = 6y$ $90 - 10y + y = 6y$ $90 - 9y = 6y$ $90 = 15y$ $y = 6$ Now, substitute the value of $$y$$ back into the first equation to find $$x$$: $x = 9 - 6$ $x = 3$ So, the tens digit $$x$$ is 3 and the units digit $$y$$ is 6. Therefore, the number is 36.

## myCBSEguide

Trusted by 1 Crore+ Students

## Test Generator

Create papers online. It's FREE.

## CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app