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Ask QuestionPosted by Mahek Rana 6 years, 7 months ago
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Posted by Harsh Bansal 6 years, 7 months ago
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Yogita Ingle 6 years, 7 months ago
(m + n)2 = m2 + 2mn + n2
(14)2 = m2 + 2(48) + n2
196 = m2 + 96 + n2
m2 + n2 = 196 - 96 = 100
(m-n)2 = m2 - 2mn + n2
(m - n)2 = 100 - 2(48)
(m - n)2 = 100 - 96
(m-n)2 = 4
m - n = 2
Posted by Supriya Kanojiya 6 years, 7 months ago
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Divyansh Jain 6 years, 7 months ago
Posted by Maya Sharma 6 years, 7 months ago
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Yogita Ingle 6 years, 7 months ago
The given data is 6, 4, 3, 8, 9, 12, 13, 9
{tex}Mean=\frac {(6+4+3+8+9+12+13+9)}{8}= \frac {64}{8}=8{/tex}
Posted by Mohd Zaid 6 years, 7 months ago
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Tripti Rawat 6 years, 7 months ago
The addition rule for equations tells us that the same quantity can be added to both sides of an equation without changing the solution set of the equation.
The multiplication/division rule for equations tell us that every term on both sides of an equation can be multiplied or divided by the same term (except zero) without changing the solution set of the equation.
Posted by Guddu Soni 6 years, 7 months ago
- 1 answers
Yogita Ingle 6 years, 7 months ago
Given observations are 38 , 48 , x - 1 , 68 , 78 , 88
Number of observations ( n ) = 6 [ even ]
median = average ( n/2 , n/2 + 1 ) th terms
= Ave( 3rd , 4th ) terms
= ( x - 1 + 68 )/2
= ( x + 67 )/2 ---( 1 )
median = 58 -----( 2 ) given
from ( 1 ) & ( 2 ) we get ,
( x + 67 )/2 = 58
x + 67 = 116
x = 116 - 67
x = 49
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Vagisha Vats 6 years, 7 months ago
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