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Ask QuestionPosted by Inder Antil 6 years, 4 months ago
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Yogita Ingle 6 years, 4 months ago
Given that the ratio of circumference of two circles is 1:3
Let the radius of two circles be m and n
2πm : 2πn = 1 : 3
Hence, m : n = 1 : 3
Ratio of areas of the circles will be ,
2πm² : 2πn² = m² : n² = 1 : 9
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Sia ? 6 years, 4 months ago
After arranging the given data in ascending or descending order we have to apply the formula given below. If n is odd then
{tex}Median= \text { Size of } \left( \frac { n + 1 } { 2 } \right)th\ item{/tex}
If n is even then
{tex}Median= \frac { \text { Size of } \left( \frac { n } { 2 } \right) \text { thitem } + \text { Size of } \left( \frac { n } { 2 } + 1 \right) \text { th item } } { 2 }{/tex}
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Aadi Prajapati 6 years, 4 months ago
0Thank You