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Ask QuestionPosted by Priya Ram 6 years, 3 months ago
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Ashutosh Katyan 6 years, 3 months ago
Yogita Ingle 6 years, 3 months ago
Average means a number which is between the largest and the smallest number.
Average = (Sum of all items)/(Number of items)
Posted by Roshan Kushwaha 6 years, 3 months ago
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Posted by Craft World 6 years, 3 months ago
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Ashutosh Katyan 6 years, 3 months ago
Posted by Anant Kumar 6 years, 3 months ago
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Posted by Rekha Ganeshan 6 years, 3 months ago
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Yogita Ingle 6 years, 3 months ago
4 (2-x) = 8
4(2) - 4(x) = 8
8 - 4x = 8
4x = 8 - 8
4x = 0
x = 0
Posted by Vikas Bansal 6 years, 3 months ago
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Posted by Malishka Singh 6 years, 3 months ago
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Sia ? 6 years, 3 months ago
Given: A quadrilateral ABCD.
To prove: AB + BC + CD + DA > AC + BD
Proof: In {tex}\Delta ABC{/tex}, we have
AB + BC > AC…(1) [{tex}\because{/tex} Sum of the lengths of any two sides of a triangle must be greater than the third side]
In {tex}\Delta BCD{/tex}, we have
BC + CD > BD...(2) [Same reason]
In {tex}\Delta CDA{/tex}, we have
CD + DA > AC…(3) [Same reason]
In {tex}\Delta DAB{/tex}, we have
AD + AB > BD…(4) [Same reason]
Adding (1), (2), (3) and (4), we get
AB + BC + BC + CD + CD + DA + AD + AB > AC + BD + AC + BD
{tex}\Rightarrow{/tex} 2AB + 2BC + 2CD + 2DA > 2AC + 2BD
{tex}\Rightarrow{/tex} 2(AB + BC + CD + DA) > 2(AC + BD)
{tex}\Rightarrow{/tex} AB + BC + CD + DA > AC + BD
Hence, proved.
Posted by Krishna Chabria 6 years, 3 months ago
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Posted by Gourav Vishwakarma 6 years, 3 months ago
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Santosh Kumrawat 6 years, 3 months ago
0Thank You