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Yogita Ingle 5 years, 5 months ago
7-(6-(5+(1-3+4)))
= 7-(6-(5+(2)))
= 7-(6-(7)
= 7 - (-1)
= 7 + 1
= 8
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Gaurav Seth 5 years, 5 months ago
(e) 4p – 3 = 13; (p = -A)
Put p = -4 in LHS
4 × (-4) – 3 = -16 – 3 = -19 ≠ 13 (RHS)
Since LHS ≠ RHS
Thus p = -4 is not the solution of the given equation.
(f) 4p – 3 = 13; (p = 0)
Put p = 0 in LHS
4 × (0) – 3 = 0 – 3 = -3 ≠ 13 (RHS)
Since LHS ≠ RHS
Thus p – 0 is not the solution of the given equation.
Gaurav Seth 5 years, 5 months ago
Check whether the value given in the brackets is a solution to the given equation or not:
(a) n + 5 = 19; (n = 1)
(b) 7n + 5 = 19; in – -2)
(c) 7n + 5 = 19; (n = 2)
(d) 4p – 3 = 13; (p = 1)
(e) 4p – 3 = 13; (p = -4)
(f) 4p-3 = 13; (p = 0)
Solution:
(a) n + 5 = 19 (n = 1)
Put n = 1 in LHS
1 + 5 = 6 ≠ 19 (RHS)
Since LHS ≠ RHS
Thus n = 1 is not the solution of the given equation.
(b) 7n + 5 = 19; (n = -2)
Put n = – 2 in LHS
7 × (-2) + 5 = -14 + 5 = -9 ≠ 19 (RHS)
Since LHS ≠ RHS
Thus, n = -2 is not the solution of the given equation.
(c) 7n+ 5 = 19; (n = 2)
Put n = 2 in LHS
7 × 2 + 5 = 14 + 5 = 19 = 19 (RHS)
Since LHS = RHS
Thus, n – 2 is the solution of the given equation.
(d) 4p – 3 = 13; (p = 1)
Put p = 1 in LHS
4 × 1 – 3 = 4 – 3 = 1 ≠ 13 (RHS)
Since LHS ≠ RHS
Thus, p = 1 is not the solution of the given equation.
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Yogita Ingle 5 years, 5 months ago
The Chola kings often gave land grants or Brahmadeya to Brahmins. An assembly or Sabha of prominent Brahmin landholders looked after each Brahmadeya, while associations of traders, known as Nagarams, looked after the administration in towns. The decisions taken by these Sabhas were recorded on the walls of the temples by way of inscriptions.
The Uttaramerur inscriptions, state the details and the basis on which a person could become a member of a Sabha. The Chola inscriptions mention several categories of land. Land was named according to the purpose for which it was donated by the Chola kings.
Posted by Sumitra Choudhary 5 years, 5 months ago
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