CBSE > Class 07 > Mathematics | CBSE Board | Homework Help

The perimeter is the distance around the outside of a shape. Perimeter is measured in units (e.g., cm). The area is the amount of space the inside of the shape takes up. Area is measured in square units (e.g., cm2). The distance around a plane figure can be measured. This distance is the perimeter of the figure. To find the perimeter of a polygon, add the lengths of the sides. ... Area is the number of square units needed to cover a figure. To find the area of a rectangle, count the number of square units or use a formula.

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Perimeter of cicle

Posted by Srijal Pandey Pandey 5 years, 1 month ago

CBSE > Class 07 > Mathematics

1 answers

Yogita Ingle 5 years, 1 month ago

The perimeter of a circle can also be specified as Circumference of the circle.

The formula for the circumference of a circle:

C = 2πR = πD

where, C= circumference and π= It is constant pronounced as “pi” with the value of 22/7 or 3.14

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56%of 83

Posted by Keshav Panchal 5 years, 1 month ago

CBSE > Class 07 > Mathematics

1 answers

Gaurav Seth 5 years, 1 month ago

83 * Percentage/ 100

= (56 * 83) / 100

46.48

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In a test (+5) marks are given for every correct answer and (-2) marks are given for every incorrect answer. Jay answered all the questions and scored (-12) marks though he got 4 correct answers. How many incorrect answers had he given?

Posted by Arnav Jadon 5 years, 1 month ago

CBSE > Class 07 > Mathematics

1 answers

Gaurav Seth 5 years, 1 month ago

A n s w e r is 16
Jay's marks are -12

correct is 4

4×5 is 20

20--12=32

32 divided by 2 is 16

There fore, 16 questions are incorrect

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4.03840÷259.6

Posted by Yashwant Ram 5 years, 1 month ago

CBSE > Class 07 > Mathematics

1 answers

Satnamsingh Rathout 5 years, 1 month ago

Hlo

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a shopkeeper earns a profit of Rs.1 by selling one pen and incurs a loss of 40 paise per pencil while selling pencils of her old stock. In a particular month she incurs a loss of Rs.5. In a month she earns neither profit nor loss. If she sold 70 pens, how many pencils did she sell?

Posted by Meeth Bhansali 5 years, 1 month ago

CBSE > Class 07 > Mathematics

1 answers

Tejasvi . 5 years, 1 month ago

Didn't get the last line

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25%of 50

Posted by Keshav Panchal 5 years, 1 month ago

CBSE > Class 07 > Mathematics

5 answers

Arnav Jadon 5 years, 1 month ago

The answer of 25%of 50 is 12.5

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Adyashwini Nayak 5 years, 1 month ago

125 is the answer

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Sarthak Dhawley 5 years, 1 month ago

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Aariz Shaikh 5 years, 1 month ago

12.5

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Gaurav Seth 5 years, 1 month ago

Answer: 12.5

Calculate percentage:

'Percentage' is obtained by multiplying 50 by 25%.

25% × 50 =

<hr />

(25 ÷ 100) × 50 =

<hr />

(25 × 50) ÷ 100 =

<hr />

1,250 ÷ 100 =

<hr />

12.5

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54.648/0.9

Posted by Aadarsh Tiwari 5 years, 1 month ago

CBSE > Class 07 > Mathematics

1 answers

Sarthak Dhawley 5 years, 1 month ago

60.72

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Solve 10/3+9/2+8/3

Posted by Aadarsh Tiwari 5 years, 1 month ago

CBSE > Class 07 > Mathematics

3 answers

Jaya Shankar 5 years, 1 month ago

10/3+9/2+8/3 = (20 + 27 + 16)/6 = 63/6 = 10.5

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Tarika Singh 5 years, 1 month ago

10.5

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Yogita Ingle 5 years, 1 month ago

10/3+9/2+8/3

= (20 + 27 + 16)/6

= 63/6

= 10.5

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3/7-4/9

Posted by Sai Harsha Sai Harsha P Shetty 5 years, 1 month ago

CBSE > Class 07 > Mathematics

1 answers

Yogita Ingle 5 years, 1 month ago

3/7-4/9

= (27 - 28)/63

= -1/63

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1.4 question 5.

Posted by Sonam Singh 5 years, 1 month ago

CBSE > Class 07 > Mathematics

2 answers

Maheshwar Gajjam ??? 5 years, 1 month ago

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Maheshwar Gajjam ??? 5 years, 1 month ago

Answer: Following number line is representing the temperature: The temperature decreases 2oC = 1 hour The temperature decreases 1oC = hour The temperature decreases 18oC = = 9 hours Total time = 12 noon + 9 hours = 21 hours = 9 pm Thus, at 9 pm the temperature would be 8oC below 0oC. Question 6. In a class test (+3) marks are given for every correct answer and marks are given for every incorrect answer and no marks for not attempting any question. (i)Radhika scored 20 marks. If she has got 12 correct answers, how many questions has she attempted incorrectly? (ii)Mohini scores marks in this test, though she has got 7 correct answers. How many questions has she attempted incorrectly? Answer: (i) Marks given for one correct answer = 3 Marks given for 12 correct answers = 3 x 12 = 36 Radhika scored 20 marks. Therefore, Marks obtained for incorrect answers = 20 – 36 = –16 Now, marks given for one incorrect answer = –2 Therefore, number of incorrect answers = Thus, Radhika has attempted 8 incorrect questions. (ii) Marks given for seven correct answers = 3 x 7 = 21 Mohini scores = –5 Marks obtained for incorrect answers = = –5 – 21 = –26 Now, marks given for one incorrect answer = –2 Therefore, number of incorrect answers = Thus, Mohini has attempted 13 incorrect questions. Question 7. An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 above the ground level, how long will it take to reach m? Answer: Starting position of mine shaft is 10 m above the ground but it moves in opposite direction so it travels the distance (–350) m below the ground. So total distance covered by mine shaft = 10 m – (–350) m = 10 + 350 = 360 m Now, time taken to cover a distance of 6 m by it = 1 minute So, time taken to cover a distance of 1 m by it = minute Therefore, time taken to cover a distance of 360 m = = 60 minutes = 1 hour (Since 60 minutes = 1 hour) Thus, in one hour the mine shaft reaches –350 below the ground.

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Write 4 equivalent fraction

Posted by Somya Verma 5 years, 1 month ago

CBSE > Class 07 > Mathematics

2 answers

Yachika Saharan 5 years, 1 month ago

1/2 , 2/4 , 3/6 , 4/8 , 5/10 , 6/12 etc.

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Yogita Ingle 5 years, 1 month ago

If two fractions are equivalent, then the product of one’s numerator and the other’s denominator is equal to the product of one’s denominator and the other numerator.

8/10, 12/15, 16/20, 20/25 and 24/30 are the equivalent fractions.

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-7mn+5,12mn+3,-9mn-8

Posted by Rohan Kumar 5 years, 1 month ago

CBSE > Class 07 > Mathematics

2 answers

Sarthak Dhawley 5 years, 1 month ago

What is this but

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Rohan Kumar 5 years, 1 month ago

-7mn+5,12mn+3,-9mn-8

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Desending

Posted by Rishika Mehrotra 5 years, 1 month ago

CBSE > Class 07 > Mathematics

1 answers

Aariz Shaikh 5 years, 1 month ago

Definition of Descending Order more ... Arranged from largest to smallest. Decreasing. Example: 100, 45, 22, 18, 2 are in descending order. See: Ascending Order Move the ducks so they are in Ascending or Descending Order © 2015 MathsIsFun.com v0.87

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Construct a triangle HAR given that HA-5CM AR-5.6 CM HR=4.2CM

Posted by Tamanna Yadav 5 years, 1 month ago

CBSE > Class 07 > Mathematics

3 answers

Tamanna Yadav 5 years, 1 month ago

Aariz right answer

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Sarthak Dhawley 5 years, 1 month ago

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Aariz Shaikh 5 years, 1 month ago

Page No 56: Question 1: Construct Δ∆ PQR, in which ∠∠Q = 70∘70°, ∠∠R = 80∘80° and PQ + QR + PR = 9.5 cm. ANSWER: Steps of construction: (1) Draw seg AB of 9.5 cm length. (2) Draw a ray making angle of 35° at point A. (3) Draw another ray making an angle of 40° at point B. (4) Name the point of intersection of the two rays as P. (5) Draw the perpendicular bisector of seg AP and seg BP. Name the points as Q and R respectively where the perpendicular bisectors intersect line AB. (6) Draw seg PQ and seg PR. Therefore, △PQR is the required triangle. Page No 56: Question 2: Construct Δ∆ XYZ, in which ∠∠Y = 58∘58°, ∠∠X = 46∘46° and perimeter of triangle is 10.5 cm. ANSWER: Steps of construction: (1) Draw seg PQ of 10.5 cm length. (2) Draw a ray making angle of 29° at point P. (3) Draw another ray making an angle of 23° at point Q. (4) Name the point of intersection of the two rays as Z. (5) Draw the perpendicular bisector of seg PZ and seg QZ. Name the points as Y and X respectively where the perpendicular bisectors intersect line PQ. (6) Draw seg XZ and seg YZ. Therefore, △XYZ is the required triangle. Page No 56: Question 3: Construct Δ∆LMN, in which ∠∠M = 60∘60°, ∠∠N = 80∘80° and LM + MN + NL = 11 cm. ANSWER: Steps of construction: (1) Draw seg AB of 11 cm length. (2) Draw a ray making angle of 30° at point A. (3) Draw another ray making an angle of 40° at point B. (4) Name the point of intersection of the two rays as L. (5) Draw the perpendicular bisector of seg AL and seg BL. Name the points as M and N respectively where the perpendicular bisectors intersect line AB. (6) Draw seg LM and seg LN. Therefore, △LMN is the required triangle. Page No 56: Question 1: Construct Δ∆ XYZ, such that XY + YZ =10.3 cm, YZ = 4.9 cm, ∠∠XYZ = 45∘45° . ANSWER: Steps of constructions: (1) Draw seg YZ of length 4.9 cm. (2) Draw ray YV such that ∠ZYA = 45°. (3) Mark point W on ray YA such that YB = 10.3 cm (4) Draw seg BZ. (5) Construct the perpendicular bisector of seg BZ . (6) Name the point of intersection of ray YA and the perpendicular bisector of BZ as X. (7) Draw seg XZ. Therefore, △XYZ is the required triangle. Page No 56: Question 2: Construct Δ∆ ABC, in which ∠∠B = 70∘70°, ∠∠C = 60∘60° , AB + BC + AC = 11.2 cm. ANSWER: Steps of construction: (1) Draw seg XY of 11.2 cm length. (2) Draw a ray making angle of 35° at point X. (3) Draw another ray making an angle of 30° at point Y. (4) Name the point of intersection of the two rays as A. (5) Draw the perpendicular bisector of seg AX and seg AY. Name the points as B and C respectively where the perpendicular bisectors intersect line XY. (6) Draw seg AB and seg AC. Therefore, △ABC is the required triangle. Page No 56: Question 3: The perimeter of a triangle is 14.4 cm and the ratio of lengths of its side is 2 : 3 : 4. Construct the triangle. ANSWER: Steps of construction: 1: A line AB = 14.4 cm is drawn. 2: Darw a ray AC making an acute angle at A in the downward direction. Then, divid it into (2 + 3 + 4) = 9 parts. 3: Join B and A9. 4: Draw a line parallel to BA9 at A2 and A5 intersecting AB at X and Y respectively.. 5: With X as centre and XA as radius, draw an arc. 6: With Y as centre and YB as radius, draw an arc cutting the previous arc at Z. 7: Join XZ and YZ. Hence, △XYZ is the required triangle. Page No 56: Question 4: Construct Δ∆ PQR, in which PQ −- PR = 2.4 cm, QR = 6.4 cm and ∠∠PQR =

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If triangle ABC is congruent to triangle FED . Write all the corresponding congruent parts of triangle

Posted by Vivek Kumar Nirala 5 years, 1 month ago

CBSE > Class 07 > Mathematics