In the circuit given as Fig, …

In the circuit given as Fig, Boojho observed that copper is deposited on the electrode connected to the negative terminal of the battery. Paheli tried to repeat the same experiment. But she could find only one copper plate. Therefore she took a carbon rod as a negative electrode. Will copper be still deposited on the carbon rod? Explain your answer. The answer will be no na, New chat Manjit Kumar Boojho observed that copper is deposited on the electrode connected to the negative terminal of the battery. Paheli tried to repeat the same experiment. But she could find only one copper plate. Therefore she took a carbon rod as a negative electrode. Will copper be still deposited on the carbon rod? Explain your answer. No, copper will not be deposited on the carbon rod used as a negative electrode in the experiment. This is because the deposition of copper on the electrode is a result of the reduction of copper ions present in the solution onto the electrode. The reduction of copper ions occurs at the negative electrode, which attracts the positively charged ions towards it. However, for the deposition of copper to take place, the electrode used as the negative terminal should be made of a material that has a lower reduction potential than copper. Copper has a reduction potential of -0.34 V, which means any electrode with a reduction potential lower than -0.34 V can be used as the negative electrode. Carbon has a reduction potential of -0.22 V, which is higher than the reduction potential of copper. This means that carbon is not a suitable material for the negative electrode in this experiment, as it cannot attract the copper ions from the solution and reduce them to form a copper deposit. Therefore, even if Paheli uses a carbon rod as the negative electrode, copper will not be deposited on it as it does not have a lower reduction potential than copper. 2 / 2 Manjit Kumar Please explain with example Sure, let's take the example of the electrolysis of a copper(II) sulfate solution using copper and carbon electrodes. In this experiment, a copper(II) sulfate solution is taken as the electrolyte, and two electrodes are dipped into it. The electrode connected to the positive terminal of the battery is the anode, and the electrode connected to the negative terminal of the battery is the cathode. When a current is passed through the solution, the copper(II) ions (Cu2+) present in the solution move towards the cathode due to their positive charge. At the same time, sulfate ions (SO42-) move towards the anode due to their negative charge. At the cathode, the copper(II) ions gain two electrons each and are reduced to form copper atoms that get deposited onto the electrode. This is because the copper electrode has a lower reduction potential than copper ions, so it can easily attract and reduce them. Cu2+ + 2e- → Cu At the anode, the sulfate ions lose two electrons each and are oxidized to form oxygen and sulfuric acid. This is because the copper electrode has a higher oxidation potential than sulfate ions, so it can easily lose electrons and get oxidized. 2SO42- → O2 + 2SO42- + 4e- Now, if Paheli uses a carbon rod as the negative electrode, carbon will not be able to reduce the copper ions as it has a higher reduction potential than copper. Carbon can only attract and reduce certain cations like hydrogen ions (H+) or sodium ions (Na+), which have a higher reduction potential than carbon. So, in this case, the copper ions will remain in the solution, and no copper will be deposited on the carbon electrode. The sulfate ions will still move towards the anode and get oxidized, producing oxygen and sulfuric acid. 2SO42- → O2 + 2SO42- + 4e- (at anode) Overall, the electrolysis of the copper(II) sulfate solution using a copper electrode as the cathode results in the deposition of copper on the electrode, while using a carbon rod as the cathode does not lead to the deposition of copper.

Posted by Vishal Kumar 1 year, 8 months ago