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Solve using suitable arrangements a) 13+109+81+87 …

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Solve using suitable arrangements a) 13+109+81+87 b) 40*51*50*10

    • Posted by Manvik Rajput 3 years, 6 months ago

    CBSE > Class 06 > Mathematics
    • 2 answers

    Nikita And Pratik 3 years, 6 months ago

    (A): (109+81)+(87+13)= 200+100=300 (B): (40×50)×(51×10)= 2000×510=1,020,000... please give thanks if this answer is helpful to you/anyone...

    1Thank You

    Sia ? 3 years, 6 months ago

    a - 290
    b - 1020000

    1Thank You

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