Find smallest 4 digits numbers which …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Avishi Rajak 5 years ago
- 2 answers
Yogita Ingle 5 years ago
LCM of 18, 24 and 32:
18 = 2 x 3 x 3
24 = 2 x 2 x 2 x 3
32 = 2 x 2 x 2 x 2 x 2
LCM = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288
The smallest four digit number that is divisible by 288:
288 x 3 = 864
288 x 4 = 1152
Since 288 is divisible by 18, 24 and 32, 1152 is also divisible by all these numbers.
Therefore, 1152 is the smallest four digit number divisible by 18, 24 and 32.
Related Questions
Posted by A Sanjay Kumar 1 year ago
- 0 answers
Posted by Laranya Yelmame 1 year, 6 months ago
- 0 answers
Posted by Harshit Sorte 1 year, 6 months ago
- 2 answers
Posted by Simran Choudhury 1 year, 5 months ago
- 1 answers
Posted by Kanika .B 1 year, 4 months ago
- 0 answers
Posted by Ankush Yadav 1 year, 5 months ago
- 1 answers
Posted by Piyush Kumar 1 year, 6 months ago
- 0 answers
Posted by Harshitha K 1 year, 6 months ago
- 2 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Harshit Githala 5 years ago
0Thank You