An isolences right tringle area 8cm2 …
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Posted by Purav Chauhan 3 years, 6 months ago
- 3 answers
Yogita Ingle 3 years, 6 months ago
Given, area of an isosceles right triangle = 8 cm2
Area of an isosceles triangle = 1/2 (Base x Height)
⇒ 8 = 1/2 (Base x Base)
[∴ base = height, as triangle is an isosceles triangle]
⇒ (Base)2 =16 ⇒ Base= 4 cm
In ΔABC, using Pythagoras theorem
AC2 = AB2 + BC2 = 42 + 42 = 16 + 16
⇒ AC2 = 32 ⇒ AC = √32 cm
[taking positive square root because length is always positive]
Hence, the length of its hypotenuse is √32 cm.
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Prem Bahadur 3 years, 2 months ago
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