A road 3.5m wide surrounds a …
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Sahdev Sharma 8 years, 4 months ago
Let r and R be the radius of the inner and outer circle respectively.
Circumference of the inner circle = 44 m
{tex}2\pi r= 44{/tex}
{tex}=> 2\times {22\over 7}\times r = 44{/tex}
=> r = 7 m
Width of the road = 3.5 m
Radius of the outer circle R = 7 m + 3.5 m = 10.5 m
Area of the road = {tex}\pi (R^2-r^2){/tex}
{tex}= {22\over 7}[(10.5)^2-(7)^2]{/tex}
{tex}= {22\over 7}(10.5-7)(10.5+7){/tex}
{tex}= {22\over 7}\times 17.5\times 3.5{/tex}
= 192.5 m2
Rate of paving the road = Rs 50 / m2
Cost of paving the road = {tex}192.5\times 50 = {/tex}Rs. 9625
0Thank You