Find the HCF of 12,81,48
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Poulami Dasgupta 8 years, 5 months ago
Prime factors of 12 = {tex}2\times2\times3{/tex}
Prime factors of 81 ={tex}3\times3\times3\times3{/tex}
Prime factors of 48={tex}2\times2\times2\times2\times3{/tex}
Now, 3 is common in all the three numbers
So, 3 is the HCF
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