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Two slits in youngs experiment are …

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Two slits in youngs experiment are 0.02cm apart. The interference fringes for light of wave length 6000A°are formed on a screen 80cm away. Calculate the distance of fifth bright fringe

    • Posted by Anita Kumari 5 years, 11 months ago

    Entrance Exam > NEET-UG > Physics
    • 2 answers

    Deepa Shiju 4 years, 11 months ago

    1.2cm

    1Thank You

    Kurai Dodiya Gohil 5 years, 6 months ago

    in youngs experiment they given us . d=0.0002m π=0.0000006m D=0.8m n=5. then we find x=? we have a formula . nπ=(xd)/D AND GET YOUR ANS

    1Thank You

    ANSWER
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