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Find the largest number that divides …

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Find the largest number that divides 246 and 1030 leaving remainder 6 in each case
  • 1 answers

Mangesh Joshi 6 years, 3 months ago

Here we have to find L C M  OF 246 and 1030 and add 6 to that L C M

By prime factorization method

246=2 x 123

     = 2 x 3 x 41

1030 = 2 x 515

        = 2  x 5  x 103

 L C M = COMMON FACTORS  X UNCOMMON FACTORS

            = 2 X 3 X 5 X 41 X 103

             =126690

Ans = 126690 + 6 =126696 (as remainder is 6 in each case)

 

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